MCQOPTIONS
Bookmark
Saved Bookmarks
→
Applied Chemistry
→
Ocean Thermal Energy Conversion in Applied Chemistry
→
100 parts of CaCO
3
is equivalent to the..
1.
100 parts of CaCO
3
is equivalent to the __________ parts of sodium carbonate.
A.
103
B.
104
C.
105
D.
106
Answer» E.
Show Answer
Discussion
No Comment Found
Post Comment
Related MCQs
If a sample water has not supplied any heat and having impurities as follows: Mg(HCO<sub>3</sub>)<sub>2</sub>=50 mg of CaCO<sub>3</sub>, MgSO<sub>4</sub> = 100mg of CaCO<sub>3</sub>, CaCl<sub>2</sub>=200mg of CaCO<sub>3</sub>, Ca(NO<sub>3</sub>)<sub>2</sub>=100mg of CaCO<sub>3</sub>. Calculate the lime required for treatment of 10000 litres of water.
100 parts of CaCO<sub>3</sub> is equivalent to the __________ parts of sodium carbonate.
We know that lime required for softening of water is x{temp Ca hardness + 2.Mg hardness + perm(Mg+Fe+3Al)hardness + 1/2 HCL + H<sub>2</sub>SO<sub>4</sub> NaAlO<sub>2</sub> CO<sub>2</sub>}-all are in terms of mg of CaCO<sub>3</sub>. Here x=?
50 ml of standard and hard water containing 1mg of pure CaCO<sub>3</sub> per ml consumed 10ml of EDTA solution. 50ml of given EDTA sample requires 10ml of same EDTA solution. Calculate the total hardness of water sample in ppm.
Reply to Comment
×
Name
*
Email
*
Comment
*
Submit Reply