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Molecular Aggregation in Engineering Chemistry
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1 degree Clarke = 1 part of CaCO3 per ___________..
1.
1 degree Clarke = 1 part of CaCO3 per _____________ parts of water.
A.
10,000
B.
30,000
C.
50,000
D.
70,000
Answer» E.
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Related MCQs
EDTA method for hardness determination is a less accurate and inconvenient procedure.
How many grams of MgCO3 dissolved per litre gives 84 ppm hardness?
1 ppm = ____________
1 degree Clarke = 1 part of CaCO3 per _____________ parts of water.
The chemical equivalent of MgSO4 salt is ____________
Hardness of water is conventionally expressed in terms of equivalent amount of ____________
Hardness of water is due to the presence of salts of ____________
1_DEGREE_CLARKE_=_1_PART_OF_CACO<SUB>3</SUB>_PER_______________PARTS_OF_WATER.?$
<p>How many grams of MgCO3 dissolved per litre gives 84 ppm hardness?</p>
1_ppm_=$
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