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This section includes 292 Mcqs, each offering curated multiple-choice questions to sharpen your Applied Chemistry knowledge and support exam preparation. Choose a topic below to get started.
251. |
By ultra filtration aldrin can be removed by _________ |
A. | 1 |
B. | 0.99 |
C. | 0.98 |
D. | 0.97 |
Answer» C. 0.98 | |
252. |
Coastal water shows major differences in ___________ |
A. | Pollution |
B. | Sewage |
C. | Salinity |
D. | Conductivity |
Answer» D. Conductivity | |
253. |
The biochemical oxygen demand can be given by ___________ |
A. | (Dob – Dos)+dilution factor |
B. | (Dob – Dos)-dilution factor |
C. | (Dob – Dos)/dilution factor |
D. | (Dob – Dos)*dilution factor |
Answer» E. | |
254. |
Control of river pollution can be done by providing the extra ___________ during dry season. |
A. | Water |
B. | Nitrogen |
C. | Carbondioxide |
D. | Oxygen |
Answer» E. | |
255. |
Pollution enters into the water system in ___________ ways. |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» E. | |
256. |
The treatment of water with _________ improves the taste of water. |
A. | Oxygen |
B. | Chlorine |
C. | KMnO4 |
D. | Ozone |
Answer» E. | |
257. |
COD is the short form of the chemical oxygen demand. |
A. | True |
B. | False |
Answer» B. False | |
258. |
1 degree Clark is equal to ________ ppm. |
A. | 12.3 |
B. | 13.3 |
C. | 14.3 |
D. | 15.3 |
Answer» D. 15.3 | |
259. |
In hot lime soda process, the bacteria in water is reduced to the minimum due to the _________ |
A. | High temperature |
B. | Faster reactions |
C. | Slow reactions |
D. | Low temperature |
Answer» B. Faster reactions | |
260. |
In reverse osmosis, the water flows from __________ concentration to ___________ concentration. |
A. | Low, high |
B. | High, low |
C. | High, moderate |
D. | Moderate, low |
Answer» B. High, low | |
261. |
The final hardness of the water after treating by the hot lime soda process is about __________ |
A. | 10-15ppm |
B. | 15-20ppm |
C. | 20-25ppm |
D. | 25-30ppm |
Answer» D. 25-30ppm | |
262. |
The BOD value of the domestic sewage is about__________ |
A. | 160 |
B. | 161 |
C. | 166 |
D. | 168 |
Answer» D. 168 | |
263. |
Zeolite process cannot soften _________ |
A. | Basic water |
B. | Neutral water |
C. | Acidic water |
D. | Salt water |
Answer» D. Salt water | |
264. |
Monitoring systems can be carried out by using __________ |
A. | Motors |
B. | Automatic sensors |
C. | Automatic motors |
D. | Turbines |
Answer» C. Automatic motors | |
265. |
The natural tendency of the water can be reversed by applying ________ to the salty water part. |
A. | Low pressure |
B. | High pressure |
C. | Low temperature |
D. | High temperature |
Answer» C. Low temperature | |
266. |
Hardness in water is expressed in terms of ____________ equivalents. |
A. | Calcium carbonate |
B. | Calcium bicarbonate |
C. | Magnesium hydroxide |
D. | Magnesium oxide |
Answer» B. Calcium bicarbonate | |
267. |
Estimation of hardness can be determined by ________ types. |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» B. 3 | |
268. |
Due to heating at high temperature in the hot lime soda process reduces the __________ |
A. | Time for treating |
B. | Energy |
C. | Corrosion of boiler |
D. | Cost |
Answer» D. Cost | |
269. |
We know that lime required for softening of water is x{temp Ca hardness+2.Mg hardness+perm(Mg+Fe+3Al)hardness+1/2 HCL+H2SO4-NaAlO2-CO2 }-all are in terms of mg of CaCO3. Here x=? |
A. | 7.4 |
B. | 0.74 |
C. | 74 |
D. | 740 |
Answer» C. 74 | |
270. |
One French unit is equal to _________ mg/litre. |
A. | 5 |
B. | 10 |
C. | 15 |
D. | 20 |
Answer» C. 15 | |
271. |
When two solutions of the different concentration is separated by the semi permeable membrane then the solvent flows from low to higher concentration is called osmosis. |
A. | True |
B. | False |
Answer» B. False | |
272. |
The ____________ is an important requirement of the aquatic life. |
A. | Dissolved nitrogen |
B. | Dissolved chlorine |
C. | Dissolved oxygen |
D. | Dissolved methane |
Answer» D. Dissolved methane | |
273. |
Aerobic process is also called as ___________ |
A. | Activated sludge process |
B. | Sludge thickening process |
C. | Sedimentation |
D. | Screening |
Answer» B. Sludge thickening process | |
274. |
The initial equipment in the ion exchange process is ___________ |
A. | More |
B. | Less |
C. | Very less |
D. | Very high |
Answer» B. Less | |
275. |
The organic matter in drinking water must be about _________ |
A. | 0.2-1.0ppm |
B. | 1.0-2.0ppm |
C. | 2.0-3.0ppm |
D. | 3.0-4.0ppm |
Answer» B. 1.0-2.0ppm | |
276. |
__________ imparts peculiar odour to the water. |
A. | Decaying organic matter |
B. | Detergents |
C. | Phenols |
D. | Dissolved oxygen |
Answer» C. Phenols | |
277. |
Dried sludge can be used as _________ |
A. | Fertilizer |
B. | Pesticide |
C. | Reagent |
D. | Medicine |
Answer» B. Pesticide | |
278. |
In final step of the domestic water process, the effluent contain ___________ BOD. |
A. | 10ppm |
B. | 15ppm |
C. | 20ppm |
D. | 25ppm |
Answer» E. | |
279. |
In _____________ when the eater is heated then the soluble salts turns into insoluble ones and removed by filtration. |
A. | Temporary hardness |
B. | Permanent hardness |
C. | Non-carbonate |
D. | Non-alkaline |
Answer» B. Permanent hardness | |
280. |
In reverse osmosis, the membrane pores are smaller in size about ___________ |
A. | 0.04 to 600nm |
B. | 0.08 to 500nm |
C. | 0.1 to 600nm |
D. | 0.2 to 500nm |
Answer» B. 0.08 to 500nm | |
281. |
In ion exchange process, the cation exchange resin is generated by passing ____________ |
A. | Acids |
B. | Dilute acids |
C. | Alkalis |
D. | Dilute alkalis |
Answer» C. Alkalis | |
282. |
In sewage the waste is about ___________ |
A. | 0.01 |
B. | 0.02 |
C. | 0.03 |
D. | 0.05 |
Answer» E. | |
283. |
The iron is about the range in drinking water is _________ |
A. | 1-1.5ppm |
B. | 0.01-0.1ppm |
C. | 1-1.1ppm |
D. | 0.1-1ppm |
Answer» E. | |
284. |
Helminth in the water causes __________ |
A. | Hook worm |
B. | Amoebic dysentery |
C. | Cholera |
D. | Typhoid |
Answer» B. Amoebic dysentery | |
285. |
50 ml of standard and hard water containing 1mg of pure CaCO3 per ml consumed 10ml of EDTA solution. 50ml of given EDTA sample requires 10ml of same EDTA solution. Calculate the total hardness of water sample in ppm. |
A. | 10ppm |
B. | 100ppm |
C. | 1000ppm |
D. | 10000ppm |
Answer» D. 10000ppm | |
286. |
The optimum value in natural water is ________ |
A. | 2-4ppm |
B. | 4-7ppm |
C. | 4-6ppm |
D. | 2-7ppm |
Answer» D. 2-7ppm | |
287. |
The standard hard water is prepared such that each ml must contain ________ mg of CaCO3. |
A. | 1 |
B. | 2 |
C. | 3 |
D. | 4 |
Answer» B. 2 | |
288. |
EDTA has the ability to form _________ with metal ions. |
A. | Stable complexes |
B. | Unstable complexes |
C. | Salts |
D. | Acids |
Answer» B. Unstable complexes | |
289. |
__________ co polymer can remove the chlorinated pesticides. |
A. | Styrene di vinyl benzene |
B. | Styrene |
C. | Benzoyl peroxide |
D. | Phenol |
Answer» B. Styrene | |
290. |
100 parts of CaCO3 is equivalent to the __________ parts of sodium carbonate. |
A. | 103 |
B. | 104 |
C. | 105 |
D. | 106 |
Answer» E. | |
291. |
The ppm is one part of calcium carbonate equivalent hardness is present in __________ of water. |
A. | One |
B. | One million |
C. | One billion |
D. | One trillion |
Answer» C. One billion | |
292. |
Bacteria and micro organisms present in the water will cause _________ in human and animals. |
A. | Indigestion |
B. | Intestinal tract |
C. | Brain tumour |
D. | Cancer |
Answer» C. Brain tumour | |