Explore topic-wise MCQs in Refrigeration.

This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Refrigeration knowledge and support exam preparation. Choose a topic below to get started.

1.

C.O.P. of the refrigerator is always __________ the C.O.P. of the heat pump when both are working between the same temperature limits.

A. less than
B. greater than
C. equal to
D. inverse of
Answer» B. greater than
Discussion
2.

A heat pump which runs (1/3)rd of time removes on an average 2400 kJ/hr of heat. If power consumed is 0.25 kW, what is the value of the C.O.P.?

A. 4
B. 2
C. 8
D. 6
Answer» D. 6
Discussion
3.

A heat pump is used to maintain a hall at 30 C when the atmospheric temperature is 15 C. The heat loss from the hall is 1200 kJ/min. Calculate the power required to run the heat pump if its C.O.P. is 40% of the Carnot machine working between the same temperature limits.

A. 0.495
B. 4.04
C. 0.247
D. 8.08
Answer» D. 8.08
Discussion
4.

If the coefficient of performance of the refrigerator is 4.67, then what is the value of the coefficient of performance of the heat pump operating under the same conditions?

A. 3.67
B. 5.67
C. 0.214
D. 9.34
Answer» C. 0.214
Discussion
5.

A reversed Carnot cycle is operating between temperature limits of (-) 33 C and (+) 27 C. If it acts as a heat engine gives an efficiency of 20%. What is the value of C.O.P. of a heat pump operating under the same conditions?

A. 6.5
B. 8
C. 5
D. 2.5
Answer» D. 2.5
Discussion
6.

If the reversed Carnot cycle operating as a heat pump between temperature limits of 364 K and 294 K, then what is the value of C.O.P?

A. 4.2
B. 0.19
C. 5.2
D. 0.23
Answer» D. 0.23
Discussion
7.

For the systems working on reversed Carnot cycle, what is the relation between C.O.P. of Refrigerator i.e. (C.O.P.)R and Heat Pump i.e. (C.O.P)P?

A. (C.O.P.)<sub>R</sub> + (C.O.P)<sub>P</sub> = 1
B. (C.O.P.)<sub>R</sub> = (C.O.P)<sub>P</sub>
C. (C.O.P.)<sub>R</sub> = (C.O.P)<sub>P</sub> 1
D. (C.O.P.)<sub>R</sub> + (C.O.P)<sub>P</sub> + 1 = 0
Answer» D. (C.O.P.)<sub>R</sub> + (C.O.P)<sub>P</sub> + 1 = 0
Discussion
8.

C.O.P. of the heat pump is always _____

A. one
B. less than One
C. greater than One
D. zero
Answer» D. zero
Discussion
9.

How is the Relative coefficient of performance represented?

A. Theoretical C.O.P. / Actual C.O.P.
B. Actual C.O.P. / Theoretical C.O.P.
C. Theoretical C.O.P. x Actual C.O.P.
D. 1 / Theoretical C.O.P. x Actual C.O.P.
Answer» C. Theoretical C.O.P. x Actual C.O.P.
Discussion
10.

What is the equation between efficiency of Heat engine and C.O.P. of heat pump?

A. <sub>E</sub> = (C.O.P.)<sub>P</sub>
B. <sub>E</sub> = 1 / (C.O.P.)<sub>P</sub>
C. <sub>E</sub> / (C.O.P.)<sub>P</sub> = 1
D. <sub>E</sub> x (C.O.P.)<sub>P</sub> = 0
Answer» C. <sub>E</sub> / (C.O.P.)<sub>P</sub> = 1
Discussion
11.

What is the difference between Heat Pump and Refrigerator?

A. Heat Pump Gives efficiency and refrigerator gives C.O.P.
B. Both are similar
C. Both are almost similar, just the desired effect is different
D. Work is output in refrigerator and work is input in heat pump
Answer» D. Work is output in refrigerator and work is input in heat pump
Discussion
12.

For a standard system with temperatures T1 and T2, where T1 &lt; Ta &lt; T2 (Ta Atmospheric Temperature). Q1 is the heat extracted from a body at temperature T1, and Q2 is heat delivered to the body at temperature T2. What is the C.O.P. of the heat pump for given conditions?

A. Q<sub>2</sub> / (Q<sub>2</sub> Q<sub>1</sub>)
B. (Q<sub>2</sub> Q<sub>1</sub>) / Q<sub>1</sub>
C. (Q<sub>2</sub> Q<sub>1</sub>) / Q<sub>2</sub>
D. Q<sub>1</sub> / (Q<sub>2</sub> Q<sub>1</sub>)
Answer» B. (Q<sub>2</sub> Q<sub>1</sub>) / Q<sub>1</sub>
Discussion