MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Materials Metallurgy knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The phenomenon where the density of metal is exceptionally low due to increasing potential is known as _______ |
| A. | Polarization |
| B. | Ionization |
| C. | Passivation |
| D. | Canonization |
| Answer» D. Canonization | |
| 2. |
A galvanic cell formed due to residual stresses is known as ________ |
| A. | Stress cell |
| B. | Residual cell |
| C. | Residual ion |
| D. | Admiralty cell |
| Answer» B. Residual cell | |
| 3. |
A galvanic cell set up due to differences in the concentration of metal ion is known as ________ |
| A. | Concentration ion |
| B. | Concentration cell |
| C. | Admiralty ion |
| D. | Admiralty cell |
| Answer» C. Admiralty ion | |
| 4. |
What is the free energy of formation value for Al2O3? |
| A. | 419 kJ mol-1 |
| B. | 1045 kJ mol-1 |
| C. | 1576 kJ mol-1 |
| D. | 2562 kJ mol-1 |
| Answer» D. 2562 kJ mol-1 | |
| 5. |
How is the Faraday’s constant defined? |
| A. | F = e NA |
| B. | F = e / NA |
| C. | F = e + NA |
| D. | F = NA / e |
| Answer» B. F = e / NA | |
| 6. |
What is the Faraday’s constant? |
| A. | 96.49 kC mol-1 |
| B. | 99.01 kC mol-1 |
| C. | 100.3 kC mol-1 |
| D. | 104.49 kC mol-1 |
| Answer» B. 99.01 kC mol-1 | |
| 7. |
THE_PHENOMENON_WHERE_THE_DENSITY_OF_A_METAL_IS_EXCEPTIONALLY_LOW_DUE_TO_INCREASING_POTENTIAL_IS_KNOWN_AS________?$ |
| A. | Polarization |
| B. | Ionization |
| C. | Passivation |
| D. | Canonization |
| Answer» D. Canonization | |
| 8. |
A galvanic cell formed due to residual stresses is known as _______? |
| A. | Stress cell |
| B. | Residual cell |
| C. | Residual ion |
| D. | Admiralty cell |
| Answer» B. Residual cell | |
| 9. |
A galvanic cell set up due to differences in concentration of metal ion is known as ________ |
| A. | Concentration ion |
| B. | Concentration cell |
| C. | Admiralty ion |
| D. | Admiralty cell |
| Answer» C. Admiralty ion | |
| 10. |
What is the Piling-Bedworth ratio of MgO? |
| A. | 0.41 |
| B. | 0.79 |
| C. | 1.71 |
| D. | 2.03 |
| Answer» C. 1.71 | |
| 11. |
What is the free energy of formation value for Al2O3? |
| A. | 419 kJ mol<sup>-1</sup> |
| B. | 1045 kJ mol<sup>-1</sup> |
| C. | 1576 kJ mol<sup>-1</sup> |
| D. | 2562 kJ mol<sup>-1</sup> |
| Answer» D. 2562 kJ mol<sup>-1</sup> | |
| 12. |
How is the Faraday’s constant defined?$ |
| A. | F = e N<sub>A</sub> |
| B. | F = e / N<sub>A</sub> |
| C. | F = e + N<sub>A</sub> |
| D. | F = N<sub>A</sub> / e |
| Answer» B. F = e / N<sub>A</sub> | |
| 13. |
What is the Faraday’s constant?$ |
| A. | 96.49 kC mol<sup>-1</sup> |
| B. | 99.01 kC mol<sup>-1</sup> |
| C. | 100.3 kC mol<sup>-1</sup> |
| D. | 104.49 kC mol<sup>-1</sup> |
| Answer» B. 99.01 kC mol<sup>-1</sup> | |
| 14. |
Which code is followed by the corrosion of metals? |
| A. | Burger’s vector |
| B. | Pilling–Bedworth |
| C. | Frank-Read mechanism |
| D. | Miller’s theorem |
| Answer» C. Frank-Read mechanism | |