Explore topic-wise MCQs in Mathematics.

This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Mathematics knowledge and support exam preparation. Choose a topic below to get started.

1.

Solve: tan x = cot x

A. x = n /2 + ( /4)
B. x = n + (3 /4)
C. x = n + ( /4)
D. x = n /2 + (3 /4)
Answer» B. x = n + (3 /4)
Discussion
2.

Find general solution to equation cot x = 3.

A. x = n + /3
B. x = n + /6
C. x = n + 2 /3
D. x = n + 5 /6
Answer» C. x = n + 2 /3
Discussion
3.

Find general solution to equation cos x = 1/ 2.

A. x = 2n 7 /4
B. x = 2n 3 /4
C. x = 2n /4
D. x = 2n /3
Answer» D. x = 2n /3
Discussion
4.

Find general solution to equation sin x = 1/2.

A. x = n + (-1)<sup>n</sup> /3
B. x = n + (-1)<sup>n</sup> /6
C. x = n + (-1)<sup>n</sup> 2 /3
D. x = n + (-1)<sup>n</sup> 5 /6
Answer» E.
Discussion
5.

Find the principal solutions of the equation cot x=1/ 3.

A. /3, 4 /3
B. 2 /3, 5 /3
C. 4 /3, 5 /3
D. /3, 5 /3
Answer» B. 2 /3, 5 /3
Discussion
6.

Find the principal solutions of the equation cosec x=2.

A. /6, 5 /6
B. /6, 7 /6
C. 5 /6, 11 /6
D. 5 /6, 7 /6
Answer» B. /6, 7 /6
Discussion
7.

Find the principal solutions of the equation sin x = -1/ 2.

A. /4, 3 /4
B. 3 /4, 5 /4
C. 3 /4, 7 /4
D. 5 /4, 7 /4
Answer» E.
Discussion
8.

Find the principal solutions of the equation sec x = -2.

A. 2 /3, 4 /3
B. 2 /3, 5 /3
C. 4 /3, 5 /3
D. /3, 5 /3
Answer» B. 2 /3, 5 /3
Discussion
9.

Find the principal solutions of the equation tan x = 3.

A. /6, 5 /6
B. /3, 5 /3
C. /3, 2 /3
D. 2 /3, 5 /3
Answer» E.
Discussion
10.

Find the principal solutions of the equation cos x = 1/2.

A. /6, 5 /6
B. /3, 5 /3
C. /3, 2 /3
D. 2 /3, 5 /3
Answer» C. /3, 2 /3
Discussion
11.

The expression involving integer n which gives all solutions of a trigonometric equation is called the principal solution.

A. True
B. False
Answer» C.
Discussion
12.

The solutions of a trigonometric equation for which ___________ are called principal solutions.

A. 0 &lt; x &lt; 2
B. 0 x &lt;
C. 0 x &lt; 2
D. 0 x &lt; n
Answer» D. 0 x &lt; n
Discussion