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This section includes 6 Mcqs, each offering curated multiple-choice questions to sharpen your Analog Circuits knowledge and support exam preparation. Choose a topic below to get started.
1. |
How is BJT used as a faster switch? |
A. | By operating it in the saturation and cut-off region |
B. | By operating it in the active and cut-off region |
C. | By using it in strong saturation |
D. | By decreasing its ON resistance |
Answer» C. By using it in strong saturation | |
2. |
Which of these relations is true always for the BJT as a switch? |
A. | Off time >> On time |
B. | Off time = Storage time Rise time |
C. | Off time << On time |
D. | Off time = Storage time + Delay time |
Answer» B. Off time = Storage time Rise time | |
3. |
What is the ON resistance of a transistor? |
A. | R<sub>ON</sub> = V<sub>CEsat</sub>/ I<sub>B</sub> |
B. | R<sub>ON</sub> = V<sub>CEsat</sub> + V<sub>A</sub>/I<sub>Csat</sub> |
C. | R<sub>ON</sub> = V<sub>CEsat</sub>/( +1)I<sub>B</sub> |
D. | R<sub>ON</sub> = V<sub>CEsat</sub>/I<sub>Csat</sub> |
Answer» E. | |
4. |
Given that the BJT is completely saturated, what is the overdrive? |
A. | Overdrive = 1 |
B. | Overdrive < 1 |
C. | Overdrive > 1 |
D. | Overdrive > 0 |
Answer» D. Overdrive > 0 | |
5. |
For a transistor in saturation, which is true? |
A. | I<sub>C</sub> = I<sub>B</sub> |
B. | I<sub>C</sub> > I<sub>B</sub> |
C. | I<sub>C</sub> < I<sub>B</sub> |
D. | I<sub>C</sub> = ( +1)I<sub>B</sub> |
Answer» D. I<sub>C</sub> = ( +1)I<sub>B</sub> | |
6. |
At saturation, which of these is not true for a BJT? |
A. | The collector current I<sub>C</sub> cannot increase further |
B. | The base current I<sub>B</sub>, cannot increase further |
C. | The collector-to-emitter voltage, V<sub>CE</sub> is due to the non-zero internal resistance of BJT |
D. | V<sub>CE</sub>(saturation) is the minimum voltage drop between C and E |
Answer» C. The collector-to-emitter voltage, V<sub>CE</sub> is due to the non-zero internal resistance of BJT | |