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This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Analog Circuits knowledge and support exam preparation. Choose a topic below to get started.
1. |
How is BJT used as a faster switch? |
A. | By operating it in the saturation and cut-off region |
B. | By operating it in the active and cut-off region |
C. | By using it in strong saturation |
D. | By decreasing its ON resistance |
Answer» C. By using it in strong saturation | |
2. |
Which of these relations is true always for the BJT as a switch? |
A. | Off time >> On time |
B. | Off time = Storage time – Rise time |
C. | Off time << On time |
D. | Off time = Storage time + Delay time |
Answer» B. Off time = Storage time – Rise time | |
3. |
Find the storage time for the current variation shown below.t1 = 2mst2 = 3mst3 = 4mst4 = 6mst5 = 19mst6 = 20ms |
A. | 1ms |
B. | 13ms |
C. | 3ms |
D. | 2ms |
Answer» C. 3ms | |
4. |
For the graph which depicts collector current, find the ON time.t1 = 1mst2 = 2mst3 = 4mst4 = 6mst5 = 16mst6 = 18ms |
A. | 3ms |
B. | 1ms |
C. | 2ms |
D. | 5ms |
Answer» B. 1ms | |
5. |
What is the ON resistance of a transistor? |
A. | RON = VCEsat/βIB |
B. | RON = VCEsat + VA/ICsat |
C. | RON = VCEsat/(β+1)IB |
D. | RON = VCEsat/ICsat |
Answer» E. | |
6. |
Consider the graph of IC vs VI shown below for a transistor. Find the correct relation for region 3 in the diagram. |
A. | IC = IC(sat) and VCE = VCE(sat) |
B. | IC = IC(sat) and VCE = VCC |
C. | IC = βIB and VCE = VCE(sat) |
D. | IC = βIB and VCE = VCC |
Answer» B. IC = IC(sat) and VCE = VCC | |
7. |
Given that the BJT is completely saturated, what is the overdrive? |
A. | Overdrive = 1 |
B. | Overdrive < 1 |
C. | Overdrive > 1 |
D. | Overdrive > 0 |
Answer» D. Overdrive > 0 | |
8. |
For a transistor in saturation, which is true? |
A. | IC = βIB |
B. | IC > βIB |
C. | IC < βIB |
D. | IC = (β+1)IB |
Answer» D. IC = (β+1)IB | |
9. |
At saturation, which of these is not true for a BJT? |
A. | The collector current IC cannot increase further |
B. | The base current IB, cannot increase further |
C. | The collector-to-emitter voltage, VCE is due to the non-zero internal resistance of BJT |
D. | VCE(saturation) is the minimum voltage drop between C and E |
Answer» C. The collector-to-emitter voltage, VCE is due to the non-zero internal resistance of BJT | |