 
			 
			MCQOPTIONS
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				This section includes 6 Mcqs, each offering curated multiple-choice questions to sharpen your Analog Circuits knowledge and support exam preparation. Choose a topic below to get started.
| 1. | How is BJT used as a faster switch? | 
| A. | By operating it in the saturation and cut-off region | 
| B. | By operating it in the active and cut-off region | 
| C. | By using it in strong saturation | 
| D. | By decreasing its ON resistance | 
| Answer» C. By using it in strong saturation | |
| 2. | Which of these relations is true always for the BJT as a switch? | 
| A. | Off time >> On time | 
| B. | Off time = Storage time Rise time | 
| C. | Off time << On time | 
| D. | Off time = Storage time + Delay time | 
| Answer» B. Off time = Storage time Rise time | |
| 3. | What is the ON resistance of a transistor? | 
| A. | R<sub>ON</sub> = V<sub>CEsat</sub>/ I<sub>B</sub> | 
| B. | R<sub>ON</sub> = V<sub>CEsat</sub> + V<sub>A</sub>/I<sub>Csat</sub> | 
| C. | R<sub>ON</sub> = V<sub>CEsat</sub>/( +1)I<sub>B</sub> | 
| D. | R<sub>ON</sub> = V<sub>CEsat</sub>/I<sub>Csat</sub> | 
| Answer» E. | |
| 4. | Given that the BJT is completely saturated, what is the overdrive? | 
| A. | Overdrive = 1 | 
| B. | Overdrive < 1 | 
| C. | Overdrive > 1 | 
| D. | Overdrive > 0 | 
| Answer» D. Overdrive > 0 | |
| 5. | For a transistor in saturation, which is true? | 
| A. | I<sub>C</sub> = I<sub>B</sub> | 
| B. | I<sub>C</sub> > I<sub>B</sub> | 
| C. | I<sub>C</sub> < I<sub>B</sub> | 
| D. | I<sub>C</sub> = ( +1)I<sub>B</sub> | 
| Answer» D. I<sub>C</sub> = ( +1)I<sub>B</sub> | |
| 6. | At saturation, which of these is not true for a BJT? | 
| A. | The collector current I<sub>C</sub> cannot increase further | 
| B. | The base current I<sub>B</sub>, cannot increase further | 
| C. | The collector-to-emitter voltage, V<sub>CE</sub> is due to the non-zero internal resistance of BJT | 
| D. | V<sub>CE</sub>(saturation) is the minimum voltage drop between C and E | 
| Answer» C. The collector-to-emitter voltage, V<sub>CE</sub> is due to the non-zero internal resistance of BJT | |