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This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Electronic Devices and Circuits Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
1. |
Consider the figure given below. If the resistance R1 is disconnected from the ground and connected to a third power source v3, then expression for the value of |
A. | v0 is |
B. | 2v1 + 4v2 − 3v3 |
C. | 6v1 + 8v2 − 3v3 |
D. | 6v1 + 4v2 − 9v3 |
E. | 3v1 + 4v2 − 3v3 |
Answer» D. 6v1 + 4v2 − 9v3 | |
2. |
It is required to connect a transducer having an open-circuit voltage of 1 V and a source resistance of 1 MΩ to a load of 1-kΩ resistance. Find the load voltage if the connection is done (a) directly and (b) through a unity-gain voltage follower. |
A. | 1 μV and 1 mV respectively |
B. | 1 mV and 1 V respectively |
C. | 0.1 μV and 0.1 mV respectively |
D. | 0.1 mV and 0.1 V respectively |
Answer» C. 0.1 μV and 0.1 mV respectively | |
3. |
For designing a non-inverting amplifier with a gain of 2 at the maximum output voltage of 10 V and the current in the voltage divider is to be 10 μA the resistance required are R1 and R2 where R2 is used to provide negative feedback. Then |
A. | R1 = 0.5 MΩ and R2 = 0.5 MΩ |
B. | R1 = 0.5 kΩ and R2 = 0.5 kΩ |
C. | R1 = 5 MΩ and R2 = 5 MΩ |
D. | R1 = 5 kΩ and R2 = 5 kΩ |
Answer» B. R1 = 0.5 kΩ and R2 = 0.5 kΩ | |
4. |
The finite voltage gain of a non-inverting operational amplifier is A and the resistance used is R1 and R2 in which R2 is the feedback resistance. Under what conditions it can one use the expression 1 + R2/R1 to determine the gain of the amplifier? |
A. | A ~ R2/R1 |
B. | A >> R2/R1 |
C. | A << R2/R1 |
D. | None of the mentioned |
Answer» C. A << R2/R1 | |
5. |
While performing an experiment to determine the gain for an ideal operational amplifier having finite gain, a student mistakenly used the equation 1 + R2/R1 where R2 is the feedback resistance. What is the percentage error in his result? Given A is the finite voltage gain of the ideal amplifier used. |
A. | (R2/R1)/(A+ R2/R1) X 100% |
B. | (1+R2/R1)/(A+R2/R1) X 100% |
C. | (1+R2/R1)/(A+1+R2/R1) X 100% |
D. | (R2/R1)/(A+1+R2/R1) X 100% |
Answer» D. (R2/R1)/(A+1+R2/R1) X 100% | |
6. |
The gain for an ideal non-inverting operational amplifier is (given R2 is the feedback resistance) |
A. | R2/R1 – 1 |
B. | R2/R1 |
C. | -R2/R1 |
D. | R2/R1 + 1 |
Answer» E. | |
7. |
For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance) |
A. | (1+R2/R1)/(1+((1+R2/R1)/A)) |
B. | (R2/R1)/(((1+R2/R1)/A)) |
C. | (1+R2/R1)/(((1+R2/R1)/A)) |
D. | (R2/R1)/(1+((1+R2/R1)/A)) |
Answer» B. (R2/R1)/(((1+R2/R1)/A)) | |