Explore topic-wise MCQs in Electronic Devices and Circuits.

This section includes 3 Mcqs, each offering curated multiple-choice questions to sharpen your Electronic Devices and Circuits knowledge and support exam preparation. Choose a topic below to get started.

1.

Consider the figure given below. If the resistance R1 is disconnected from the ground and connected to a third power source v3, then expression for the value of
v0 is

A. n<a href="https://www.sanfoundry.com/wp-content/uploads/2017/06/electronic-devices-circuits-questions-answers-non-inverting-configuration-q10.png"><img alt="Find expression for the value of v0 if resistance R1 is disconnected from ground" class="alignnone size-full wp-image-206678" height="185" src="https://www.sanfoundry.com/wp-content/uploads/2017/06/electronic-devices-circuits-questions-answers-non-inverting-configuration-q10.png" width="288"/></a>
B. 2v<sub>1</sub> + 4v<sub>2</sub> 3v<sub>3</sub>
C. 6v<sub>1</sub> + 8v<sub>2</sub> 3v<sub>3</sub>
D. 6v<sub>1</sub> + 4v<sub>2</sub> 9v<sub>3</sub>
E. 3v<sub>1</sub> + 4v<sub>2</sub> 3v<sub>3</sub>
Answer» D. 6v<sub>1</sub> + 4v<sub>2</sub> 9v<sub>3</sub>
Discussion
2.

It is required to connect a transducer having an open-circuit voltage of 1 V and a source resistance of 1 M to a load of 1-k resistance. Find the load voltage if the connection is done (a) directly and (b) through a unity-gain voltage follower.

A. 1 V and 1 mV respectively
B. 1 mV and 1 V respectively
C. 0.1 V and 0.1 mV respectively
D. 0.1 mV and 0.1 V respectively
Answer» C. 0.1 V and 0.1 mV respectively
Discussion
3.

For designing a non-inverting amplifier with a gain of 2 at the maximum output voltage of 10 V and the current in the voltage divider is to be 10 A the resistance required are R1 and R2 where R2 is used to provide negative feedback. Then

A. R<sub>1</sub> = 0.5 M and R<sub>2</sub> = 0.5 M
B. R<sub>1</sub> = 0.5 k and R<sub>2</sub> = 0.5 k
C. R<sub>1</sub> = 5 M and R<sub>2</sub> = 5 M
D. R<sub>1</sub> = 5 k and R<sub>2</sub> = 5 k
Answer» B. R<sub>1</sub> = 0.5 k and R<sub>2</sub> = 0.5 k
Discussion