Explore topic-wise MCQs in Mechanical Operations.

This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Mechanical Operations knowledge and support exam preparation. Choose a topic below to get started.

1.

What is the terminal settling velocity of spherical particle flowing through a liquid of density 1100 kg/m3 and Reynolds number 1500 with a velocity 0.04 m/s? The diameter of the particle is 10 m a its density it 1300 kg/m3.

A. 2.3 m/s
B. 2.5 m/s
C. 2 m/s
D. 2.7 m/s
Answer» B. 2.5 m/s
2.

What is the diameter of a particle that has a density of 2600 kg/m3 and flows through water under laminar conditions. Assume viscosity of water as 8.11 10-4 kg/ms. The terminal velocity is found to be 0.005 m/s.

A. 0.9 m
B. 1 m
C. 0.4 m
D. 0.7 m
Answer» E.
3.

A spherical particle of diameter 1 m and density 1200kg/m3 is falling freely through a column of water with a velocity of 0.7 m/s. Considering the viscosity of water to be 8.11 10-4 kg/ms and acceleration due to gravity as 9.8 m/s2, calculate the terminal velocity of the particle.

A. 0.34 10<sup>-6</sup> m/s
B. 1.34 10<sup>-7</sup> m/s
C. 1.34 10<sup>-8</sup> m/s
D. 2.34 10<sup>-7</sup> m/s
Answer» B. 1.34 10<sup>-7</sup> m/s
4.

Which of the following is the equation of a spherical ball of radius r, settling under gravity through a fluid, if acceleration due to gravity is considered as 10 m/s2?

A. u = 4x ( sqrt { frac {5 times r times ( P )}{3 times Cd times }} )
B. u = 4x ( sqrt { frac {r times ( P )}{Cd times }} )
C. u = 5x ( sqrt { frac {5 times ( P )}{3 times Cd times }} )
D. u = ( sqrt { frac {8 times ( P )}{3 times Cd times }} )
Answer» B. u = 4x ( sqrt { frac {r times ( P )}{Cd times }} )
5.

What is the equation for drag force on a spherical body, when external force acts with acceleration a? Here is the density of fluid, P is the density of particle, m is mass of the particle, Cd is the drag coefficient and r is the radius of the sphere.

A. u = ( sqrt { frac {8 times r times a( P)}{3 times Cd times P}} )
B. u = ( sqrt { frac {8 times r times a( P )}{3 times Cd times }} )
C. u = ( sqrt { frac {3 times r times a( P )}{Cd times }} )
D. u = ( sqrt { frac {4 times r times a( P )}{3 times Cd times }} )
Answer» C. u = ( sqrt { frac {3 times r times a( P )}{Cd times }} )