Explore topic-wise MCQs in Engineering Mathematics.

This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mathematics knowledge and support exam preparation. Choose a topic below to get started.

1.

Expand (1 + x)1‚ÅÑx, gives$#

A. e [1 + <sup>x</sup>⁄<sub>2</sub> + <sup>11x<sup>2</sup></sup>⁄<sub>24</sub> -…..].
B. e [1 – <sup>x</sup>⁄<sub>2</sub> + <sup>11x<sup>2</sup></sup>⁄<sub>24</sub> -…..].
C. e [<sup>x</sup>⁄<sub>2</sub> – <sup>11x<sup>2</sup></sup>⁄<sub>24</sub> -…..].
D. e [<sup>x</sup>⁄<sub>2</sub> + <sup>11x<sup>2</sup></sup>⁄<sub>24</sub> -…..].
Answer» C. e [<sup>x</sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>2</sub> ‚Äö√Ñ√∂‚àö√ë‚àö¬® <sup>11x<sup>2</sup></sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>24</sub> -‚Äö√Ñ√∂‚àö√묨‚àÇ..].
Discussion
2.

Given f(x)= ln⁡(cos⁡(x) ),calculate the value of ln⁡(cos⁡(π⁄2))?#

A. -1.741
B. 1.741
C. 1.563
D. -1.563
Answer» B. 1.741
Discussion
3.

The expansion of eSin(x) is

A. 1 + x + <sup>x<sup>2</sup></sup>⁄<sub>2</sub> + <sup>x<sup>4</sup></sup>⁄<sub>8</sub> +….
B. 1 + x + <sup>x<sup>2</sup></sup>⁄<sub>2</sub> – <sup>x<sup>4</sup></sup>⁄<sub>8</sub> +….
C. 1 + x – <sup>x<sup>2</sup></sup>⁄<sub>2</sub> + <sup>x<sup>4</sup></sup>⁄<sub>8</sub> +….
D. 1 + x + <sup>x<sup>3</sup></sup>⁄<sub>6</sub> – <sup>x<sup>5</sup></sup>⁄<sub>10</sub> +….
Answer» C. 1 + x ‚Äö√Ñ√∂‚àö√ë‚àö¬® <sup>x<sup>2</sup></sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>2</sub> + <sup>x<sup>4</sup></sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>8</sub> +‚Äö√Ñ√∂‚àö√묨‚àÇ.
Discussion
4.

The necessary condition for the maclaurin expansion to be true for function f(x) is
A. f(x) should be continuous
B. f(x) should be differentiable
C. f(x) should exists at every point
D. f(x) should be continuous and differentiable
Answer» E.
Discussion
5.

Expansion of function f(x) is

A. f(0) + <sup>x</sup>⁄<sub>1!</sub> f<sup>‘</sup> (0) + <sup>x<sup>2</sup></sup>⁄<sub>2!</sub> f<sup>”</sup> (0)…….+<sup>x<sup>n</sup></sup>⁄<sub>n!</sub> f<sup>n</sup> (0)
B. 1 + <sup>x</sup>⁄<sub>1!</sub> f<sup>‘</sup> (0) + <sup>x<sup>2</sup></sup>⁄<sub>2!</sub> f<sup>”</sup> (0)…….+<sup>x<sup>n</sup></sup>⁄<sub>n!</sub> f<sup>n</sup> (0)
C. f(0) – <sup>x</sup>⁄<sub>1!</sub> f<sup>‘</sup> (0) + <sup>x<sup>2</sup></sup>⁄<sub>2!</sub> f<sup>”</sup> (0)…….+(-1)^n <sup>x<sup>n</sup></sup>⁄<sub>n!</sub> f<sup>n</sup> (0)
D. f(1) + <sup>x</sup>⁄<sub>1!</sub> f<sup>‘</sup> (1) + <sup>x<sup>2</sup></sup>⁄<sub>2!</sub> f<sup>”</sup> (1)…….+<sup>x<sup>n</sup></sup>⁄<sub>n!</sub> f<sup>n</sup> (1)
Answer» B. 1 + <sup>x</sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>1!</sub> f<sup>‚Äö√Ñ√∂‚àö√ë‚àö‚â§</sup> (0) + <sup>x<sup>2</sup></sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>2!</sub> f<sup>‚Äö√Ñ√∂‚àö√ë‚àöœÄ</sup> (0)‚Äö√Ñ√∂‚àö√묨‚àÇ‚Äö√Ñ√∂‚àö√묨‚àÇ.+<sup>x<sup>n</sup></sup>‚Äö√Ñ√∂‚àö√ñ‚àö√´<sub>n!</sub> f<sup>n</sup> (0)
Discussion