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This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mathematics knowledge and support exam preparation. Choose a topic below to get started.
1. |
Find the solution of differential equation, dy dx = xy + x2, if y = 1 at x = 0. |
A. | (1- frac{x^2}{2!}+ frac{3x^4}{4!}- frac{15x^6}{6!}+ ) |
B. | ( frac{x}{1!}+ frac{3x^3}{4!}+ frac{15x^5}{6!}+ ) |
C. | ( frac{x}{1!}- frac{3x^3}{4!}+ frac{15x^5}{6!}- ) |
D. | (1+ frac{x^2}{2!}+ frac{3x^4}{4!}+ frac{15x^6}{6!}+.. ) |
Answer» E. | |
2. |
Expand (1 + x)1 x, gives ___________ |
A. | e[1 + <sup>x</sup> <sub>2</sub> + <sup>11x<sup>2</sup></sup> <sub>24</sub> - ..] |
B. | e[1 <sup>x</sup> <sub>2</sub> + <sup>11x<sup>2</sup></sup> <sub>24</sub> - ..] |
C. | e[<sup>x</sup> <sub>2</sub> <sup>11x<sup>2</sup></sup> <sub>24</sub> - ..] |
D. | e[<sup>x</sup> <sub>2</sub> + <sup>11x<sup>2</sup></sup> <sub>24</sub> - ..] |
Answer» C. e[<sup>x</sup> <sub>2</sub> <sup>11x<sup>2</sup></sup> <sub>24</sub> - ..] | |
3. |
Find the expansion of Sin(lSin-1 (x)). |
A. | (lx- frac{l(1-l^2)}{3!}x^3+ frac{l(1-l^2)(9-l^2)}{5!} x^5- ) |
B. | (lx+ frac{l(1-l^2)}{3!} x^3+ frac{l(1-l^2)(9-l^2)}{5!} x^5+ ) |
C. | (1-lx^2+ frac{l(1-l^2)}{3!} x^4- frac{l(1-l^2)(9-l^2)}{5!} x^6+ ) |
D. | (1+lx^2+ frac{l(1-l^2)}{3!} x^4+ frac{l(1-l^2)(9-l^2)}{5!} x^6+ ) |
Answer» C. (1-lx^2+ frac{l(1-l^2)}{3!} x^4- frac{l(1-l^2)(9-l^2)}{5!} x^6+ ) | |
4. |
Find the expansion of cos(xsin(t)). |
A. | ( sum_{n=1}^ ( frac{x^n [Cos(nt)]}{n!}) ) |
B. | ( sum_{n=0}^ ( frac{x^n [Cos(nt)]}{n!}) ) |
C. | ( sum_{n=1}^ ( frac{x^n [Sin(nt)]}{n!}) ) |
D. | ( sum_{n=0}^ ( frac{x^n [Sin(nt)]}{n!}) ) |
Answer» C. ( sum_{n=1}^ ( frac{x^n [Sin(nt)]}{n!}) ) | |
5. |
Given f(x)= ln (cos (x)),calculate the value of ln (cos ( 2)). |
A. | -1.741 |
B. | 1.741 |
C. | 1.563 |
D. | -1.563 |
Answer» B. 1.741 | |
6. |
Find the expansion of exSin(x)? |
A. | (e^{xSin(x)}=1+x^2-x^4/3+x^6/120- ) |
B. | (e^{xSin(x)}=1+x^2+x^4/3+x^6/120+ ) |
C. | (e^{xSin(x)}=x+x^3/3+x^5/120+.. ) |
D. | (e^{xSin(x)}=x+x^3/3-x^5/120+ ) |
Answer» C. (e^{xSin(x)}=x+x^3/3+x^5/120+.. ) | |
7. |
Find the expansion of f(x) = ln (1+ex)? |
A. | (ln(2)+x/2+x^2/8-x^4/192+ . ) |
B. | (ln u2061(2)+x/2+x^2/8+x^4/192+ . ) |
C. | (ln u2061(2)+x/2+x^3/8-x^5/192+ . ) |
D. | (ln u2061(2)+x/2+x^3/8+x^5/192+ . ) |
Answer» B. (ln u2061(2)+x/2+x^2/8+x^4/192+ . ) | |
8. |
Expansion of y = Sin-1(x) is? |
A. | (x+ frac{x^3}{6}+ frac{3}{40} x^5+ frac{5}{112} x^7+ .. ) |
B. | (x- frac{x^3}{6}+ frac{3}{40} x^5- frac{5}{112} x^7+ .. ) |
C. | ( frac{x^3}{6}- frac{3}{40} x^5+ frac{5}{112} x^7 .. ) |
D. | (x+ frac{x^2}{6}+ frac{3}{40} x^2+ frac{5}{112} x^2+ .. ) |
Answer» B. (x- frac{x^3}{6}+ frac{3}{40} x^5- frac{5}{112} x^7+ .. ) | |
9. |
The expansion of eSin(x) is? |
A. | 1 + x + <sup>x<sup>2</sup></sup> <sub>2</sub> + <sup>x<sup>4</sup></sup> <sub>8</sub> + . |
B. | 1 + x + <sup>x<sup>2</sup></sup> <sub>2</sub> <sup>x<sup>4</sup></sup> <sub>8</sub> + . |
C. | 1 + x <sup>x<sup>2</sup></sup> <sub>2</sub> + <sup>x<sup>4</sup></sup> <sub>8</sub> + . |
D. | 1 + x + <sup>x<sup>3</sup></sup> <sub>6</sub> <sup>x<sup>5</sup></sup> <sub>10</sub> + . |
Answer» C. 1 + x <sup>x<sup>2</sup></sup> <sub>2</sub> + <sup>x<sup>4</sup></sup> <sub>8</sub> + . | |
10. |
The expansion of f(a+h) is ______ |
A. | (f(a)+ frac{h}{1!} f'(a)+ frac{h^2}{2!} f (a) .+ frac{h^n}{n!} f^n (a) ) |
B. | (f(a)+ frac{h}{1!} f'(a)+ frac{h^2}{2!} f (a) . ) |
C. | (hf(a)+ frac{h^2}{1!} f'(a)+ frac{h^3}{2!} f (a) .+ frac{h^n}{n!} f^n (a) ) |
D. | (hf(a)+ frac{h^2}{1!} f'(a)+ frac{h^3}{2!} f (a) ) |
Answer» B. (f(a)+ frac{h}{1!} f'(a)+ frac{h^2}{2!} f (a) . ) | |
11. |
The necessary condition for the maclaurin expansion to be true for function f(x) is __________ |
A. | f(x) should be continuous |
B. | f(x) should be differentiable |
C. | f(x) should exists at every point |
D. | f(x) should be continuous and differentiable |
Answer» E. | |
12. |
Expansion of function f(x) is? |
A. | f(0) + <sup>x</sup> <sub>1!</sub> f<sup> </sup> (0) + <sup>x<sup>2</sup></sup> <sub>2!</sub> f<sup> </sup> (0) .+<sup>x<sup>n</sup></sup> <sub>n!</sub> f<sup>n</sup> (0) |
B. | 1 + <sup>x</sup> <sub>1!</sub> f<sup> </sup> (0) + <sup>x<sup>2</sup></sup> <sub>2!</sub> f<sup> </sup> (0) .+<sup>x<sup>n</sup></sup> <sub>n!</sub> f<sup>n</sup> (0) |
C. | f(0) <sup>x</sup> <sub>1!</sub> f<sup> </sup> (0) + <sup>x<sup>2</sup></sup> <sub>2!</sub> f<sup> </sup> (0) .+(-1)^n <sup>x<sup>n</sup></sup> <sub>n!</sub> f<sup>n</sup> (0) |
D. | f(1) + <sup>x</sup> <sub>1!</sub> f<sup> </sup> (1) + <sup>x<sup>2</sup></sup> <sub>2!</sub> f<sup> </sup> (1) .+<sup>x<sup>n</sup></sup> <sub>n!</sub> f<sup>n</sup> (1) |
Answer» B. 1 + <sup>x</sup> <sub>1!</sub> f<sup> </sup> (0) + <sup>x<sup>2</sup></sup> <sub>2!</sub> f<sup> </sup> (0) .+<sup>x<sup>n</sup></sup> <sub>n!</sub> f<sup>n</sup> (0) | |