MCQOPTIONS
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MCQOPTIONS
This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Soil Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the influence factor for the vertical pressure at depth 5m for a uniformly loaded circular area of 80 kN/m2 load and radius of 1m. |
| A. | 0.6212 |
| B. | 0.0571 |
| C. | 0.0328 |
| D. | 0.0624 |
| Answer» C. 0.0328 | |
| 2. |
Find the vertical pressure at depth 5m for a uniformly loaded circular area of 80 kN/m2 load and radius of 5m. |
| A. | 51.72 kN/m2 |
| B. | 54.12 kN/m2 |
| C. | 78.325 kN/m2 |
| D. | 12.24 kN/m2 |
| Answer» B. 54.12 kN/m2 | |
| 3. |
For a uniformly loaded rectangular area, the Newmark’s influence factor given by ___________ |
| A. | \(K= \left[\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}*\frac{0.2^2+0.4^2+2}{0.2^2+0.4^2+1}+tan^{-1}\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}\right] \) |
| B. | \(K= \frac{1}{4π} \left[\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}*\frac{0.2^2+0.4^2+2}{0.2^2+0.4^2+1}+tan^{-1}\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}\right] \) |
| C. | \(K= \frac{1}{4π}\) |
| D. | \(K= \frac{q}{4π} \left[\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}*\frac{0.2^2+0.4^2+2}{0.2^2+0.4^2+1}+tan^{-1}\frac{20.20.4\sqrt{(0.2^2+0.4^2+1)}}{0.2^2+0.4^2+0.2^2 0.4^2+1}\right] \) |
| Answer» C. \(K= \frac{1}{4π}\) | |
| 4. |
The Westergaard’s influence factor is given by _____________ |
| A. | \(K_W=\frac{1}{π\left[1+2(\frac{r}{z})^2 \right]^\frac{3}{2}} \) |
| B. | \(K_W=\frac{Q}{z^2} \) |
| C. | \(K_W=\frac{1}{π\left[1+2(\frac{r}{z})^2 \right]^\frac{5}{2}} \frac{Q}{z^2} \) |
| D. | \(K_W=\frac{1}{π\left[1+2(\frac{r}{z})^2 \right]^3}\frac{Q}{z^2} \) |
| Answer» B. \(K_W=\frac{Q}{z^2} \) | |
| 5. |
The Westergaard’s equation is given by ___________ |
| A. | \(σ_z=\frac{1}{\left[1+2(\frac{r}{z})^2 \right]^\frac{3}{2}} \) |
| B. | \(σ_z=\frac{1}{2\left[1+2(\frac{r}{z})^2 \right]^\frac{3}{2}} \) |
| C. | \(σ_z=\frac{1}{π\left[1+2(\frac{r}{z})^2 \right]^\frac{3}{2}}\frac{Q}{z^2} \) |
| D. | \(σ_z=\frac{1}{π\left[1+2(\frac{r}{z})^2 \right]^\frac{3}{2}} \) |
| Answer» D. \(σ_z=\frac{1}{π\left[1+2(\frac{r}{z})^2 \right]^\frac{3}{2}} \) | |
| 6. |
The influence factor for the vertical stress under the corner of a uniformly loaded rectangular area of size 1m*2m at depth 5m and load of 80 kN/m2 is given by ___________ |
| A. | 0.6212 |
| B. | 0.7465 |
| C. | 0.0328 |
| D. | 0.0624 |
| Answer» D. 0.0624 | |
| 7. |
The vertical stress under the corner of a uniformly loaded rectangular area of size 2m*4m at depth 5m and load of 80 kN/m2 is given by ___________ |
| A. | 6.22 kN/m2 |
| B. | 7.45 kN/m2 |
| C. | 8.12 kN/m2 |
| D. | 9.23 kN/m2 |
| Answer» C. 8.12 kN/m2 | |
| 8. |
The vertical stress under the corner of a uniformly loaded rectangular area of size a, b at depth z and m=a/z, n=b/z is given by ___________ |
| A. | \(σ_z=\frac{2q’}{πz}\frac{1}{\left[1+(\frac{x}{z})^2\right]^2}\) |
| B. | \(σ_z=\frac{q}{4π} \left[\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1}\right] \) |
| C. | \(σ_z=\frac{q}{4π} \left[\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1}* \frac{m^2+n^2+2}{m^2+n^2+1}+tan^{-1}\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1} \right] \) |
| D. | \(σ_z=q\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \) |
| Answer» D. \(σ_z=q\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \) | |
| 9. |
In Newmark’s influence chart method, the point below which pressure is required should lie within the loaded area. |
| A. | True |
| B. | False |
| Answer» C. | |
| 10. |
If a uniformly loaded circular area is divided into 44 sectors, then the influence value if is given by ___________ |
| A. | \(\frac{1}{44} \left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \) |
| B. | \(44\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \) |
| C. | \(44\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2}\right] \) |
| D. | \(\frac{1}{44} \left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2}\right] \) |
| Answer» B. \(44\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \) | |
| 11. |
If the influence value \(i_f=\frac{1}{35} \left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \) for a uniformly loaded circular area, then the circular area is divided into _________ sectors. |
| A. | 20 |
| B. | 35 |
| C. | 7 |
| D. | 14 |
| Answer» C. 7 | |
| 12. |
If a uniformly loaded circular area is divided into 20 sectors, then the influence value if is given by ___________ |
| A. | \(\frac{1}{20}\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right]\) |
| B. | \(20\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right]\) |
| C. | \(20\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2}\right]\) |
| D. | \(\frac{1}{20}\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2} \right]\) |
| Answer» B. \(20\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right]\) | |
| 13. |
The Newmark’s influence chart consists of _________ |
| A. | a single circle only |
| B. | a number of circles and radiating lines |
| C. | bar diagram |
| D. | small rectangular unit areas |
| Answer» C. bar diagram | |
| 14. |
_________ is more accurate method of determining the vertical stress at any point. |
| A. | Isobar chart |
| B. | equivalent point load method |
| C. | Influence chart |
| D. | Fenske’s chart |
| Answer» D. Fenske’s chart | |
| 15. |
_________ chart is used to find the vertical stress on Westergaard’s equation. |
| A. | Influence chart |
| B. | Isocurve chart |
| C. | Isobar chart |
| D. | Fenske’s chart |
| Answer» B. Isocurve chart | |