Explore topic-wise MCQs in Bioprocess Engineering.

This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Bioprocess Engineering knowledge and support exam preparation. Choose a topic below to get started.

1.

What is the COD (chemical oxygen demand) of ethanol, expressed as g COD/g ethanol?

A. 1.30 g COD/g ethanol
B. 32 g COD/g ethanol
C. 2.24 g COD/g ethanol
D. 2.09 g COD/g ethanol
Answer» E.
2.

What is the degree of reduction of glucose?

A. 4
B. 3
C. 12
D. 24
Answer» E.
3.

The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:
C6H12O6 + aNH3 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH + 0.036H2O and determine the product yield coefficient Y etoh/s and determine coefficient a.

A. 0.57 g. g , 0.078
B. 0.33 g. g , 0.094
C. 0.45 g. g , 0.086
D. 0.44 g. g , 0.056
Answer» C. 0.45 g. g , 0.086
4.

The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:
C6H12O6 + aNH3 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH +0.036H2O

A. nDetermine the biomass (MW= 23.74) yield coefficient Y x/s
B. 0.078 g. g
C. 0.070 g. g
D. 0.068 g. g
E. 0.060 g. g
Answer» B. 0.078 g. g
5.

A yeast (CH1.66N0.13O0.40) is growing aerobically on arabinose (C5H10O5) and ammonium hydroxide (NH4OH) with a respiratory quotient of 1.4. Estimate the stoichiometric coefficient of the equation:
aC5H10O5 + bO2 + cNH4OH CH1.66N0.13O0.40 + dCO2 + eH2O

A. a = 0.2823, b = 0.2938, c = 0.13, d = 0.4113, e = 0.9065
B. a = 0.2893, b = 0.3638, c = 0.13, d = 0.4321, e = 0.9478
C. a = 0.2843, b = 0.2590, c = 0.13, d = 0.4321, e = 0.9576
D. a = 0.2823, b = 0.2130, c = 0.13, d = 0.4113, e = 0.8743
Answer» B. a = 0.2893, b = 0.3638, c = 0.13, d = 0.4321, e = 0.9478
6.

Calculate the stoichiometric coefficients of the following biological reaction:
Glucose: C6H12O6 + aO2 + bNH3 = c (C4.4H7.3N0.86O1.2) + d H2O + e CO2

A. a = 1.573, b = 0.685, c = 0.470, d = 2.564, e = 2
B. a = 2.789, b = 1.896, c = 0.438, d = 1.395, e = 1
C. a = 1.473, b = 0.782, c = 0.909, d = 3.854, e = 2
D. a = 2.390, b = 1.295, c = 0.943, d = 2. 564, e = 1
Answer» D. a = 2.390, b = 1.295, c = 0.943, d = 2. 564, e = 1
7.

Calculate the stoichiometric coefficients of the following biological reaction:
Hexadecane: C16H34 + a O2 + b NH3 = c (C4.4H7.3N0.86O1.2) + d H2O + e CO2

A. a = 12.427, b = 2.085, c = 2.42, d = 12.43, e = 5.33
B. a = 12.345, b = 3.456, c = 2.42, d = 12.46, e = 5.44
C. a = 12.594, b = 2.345, c = 3.42, d = 12.49, e = 5.66
D. a = 12.345, b = 3.560, c = 3.42, d = 12.46, e = 5.44
Answer» B. a = 12.345, b = 3.456, c = 2.42, d = 12.46, e = 5.44
8.

Estimate the degree of reduction of Methane, Glucose and Ethanol?

A. (CH<sub>4</sub>) = 6, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 4, (C<sub>2</sub>H<sub>5</sub>OH) = 6
B. (CH<sub>4</sub>) = 6, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 4, (C<sub>2</sub>H<sub>5</sub>OH) = 8
C. (CH<sub>4</sub>) = 8, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 4, (C<sub>2</sub>H<sub>5</sub>OH) = 6
D. (CH<sub>4</sub>) = 4, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 6, (C<sub>2</sub>H<sub>5</sub>OH) = 8
Answer» D. (CH<sub>4</sub>) = 4, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 6, (C<sub>2</sub>H<sub>5</sub>OH) = 8
9.

Bacteria have slightly higher nitrogen content than fungi .

A. True
B. False
Answer» B. False