MCQOPTIONS
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MCQOPTIONS
This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Bioprocess Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the COD (chemical oxygen demand) of ethanol, expressed as g COD/g ethanol? |
| A. | 1.30 g COD/g ethanol |
| B. | 32 g COD/g ethanol |
| C. | 2.24 g COD/g ethanol |
| D. | 2.09 g COD/g ethanol |
| Answer» E. | |
| 2. |
What is the degree of reduction of glucose? |
| A. | 4 |
| B. | 3 |
| C. | 12 |
| D. | 24 |
| Answer» E. | |
| 3. |
The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:C6H12O6 + aNH3 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH + 0.036H2O and determine the product yield coefficient Y etoh/s and determine coefficient a. |
| A. | 0.57 g. g , 0.078 |
| B. | 0.33 g. g , 0.094 |
| C. | 0.45 g. g , 0.086 |
| D. | 0.44 g. g , 0.056 |
| Answer» C. 0.45 g. g , 0.086 | |
| 4. |
The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:C6H12O6 + aNH3 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH +0.036H2O |
| A. | nDetermine the biomass (MW= 23.74) yield coefficient Y x/s |
| B. | 0.078 g. g |
| C. | 0.070 g. g |
| D. | 0.068 g. g |
| E. | 0.060 g. g |
| Answer» B. 0.078 g. g | |
| 5. |
A yeast (CH1.66N0.13O0.40) is growing aerobically on arabinose (C5H10O5) and ammonium hydroxide (NH4OH) with a respiratory quotient of 1.4. Estimate the stoichiometric coefficient of the equation:aC5H10O5 + bO2 + cNH4OH CH1.66N0.13O0.40 + dCO2 + eH2O |
| A. | a = 0.2823, b = 0.2938, c = 0.13, d = 0.4113, e = 0.9065 |
| B. | a = 0.2893, b = 0.3638, c = 0.13, d = 0.4321, e = 0.9478 |
| C. | a = 0.2843, b = 0.2590, c = 0.13, d = 0.4321, e = 0.9576 |
| D. | a = 0.2823, b = 0.2130, c = 0.13, d = 0.4113, e = 0.8743 |
| Answer» B. a = 0.2893, b = 0.3638, c = 0.13, d = 0.4321, e = 0.9478 | |
| 6. |
Calculate the stoichiometric coefficients of the following biological reaction:Glucose: C6H12O6 + aO2 + bNH3 = c (C4.4H7.3N0.86O1.2) + d H2O + e CO2 |
| A. | a = 1.573, b = 0.685, c = 0.470, d = 2.564, e = 2 |
| B. | a = 2.789, b = 1.896, c = 0.438, d = 1.395, e = 1 |
| C. | a = 1.473, b = 0.782, c = 0.909, d = 3.854, e = 2 |
| D. | a = 2.390, b = 1.295, c = 0.943, d = 2. 564, e = 1 |
| Answer» D. a = 2.390, b = 1.295, c = 0.943, d = 2. 564, e = 1 | |
| 7. |
Calculate the stoichiometric coefficients of the following biological reaction:Hexadecane: C16H34 + a O2 + b NH3 = c (C4.4H7.3N0.86O1.2) + d H2O + e CO2 |
| A. | a = 12.427, b = 2.085, c = 2.42, d = 12.43, e = 5.33 |
| B. | a = 12.345, b = 3.456, c = 2.42, d = 12.46, e = 5.44 |
| C. | a = 12.594, b = 2.345, c = 3.42, d = 12.49, e = 5.66 |
| D. | a = 12.345, b = 3.560, c = 3.42, d = 12.46, e = 5.44 |
| Answer» B. a = 12.345, b = 3.456, c = 2.42, d = 12.46, e = 5.44 | |
| 8. |
Estimate the degree of reduction of Methane, Glucose and Ethanol? |
| A. | (CH<sub>4</sub>) = 6, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 4, (C<sub>2</sub>H<sub>5</sub>OH) = 6 |
| B. | (CH<sub>4</sub>) = 6, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 4, (C<sub>2</sub>H<sub>5</sub>OH) = 8 |
| C. | (CH<sub>4</sub>) = 8, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 4, (C<sub>2</sub>H<sub>5</sub>OH) = 6 |
| D. | (CH<sub>4</sub>) = 4, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 6, (C<sub>2</sub>H<sub>5</sub>OH) = 8 |
| Answer» D. (CH<sub>4</sub>) = 4, (C<sub>6</sub>H<sub>12</sub>O<sub>6</sub>) = 6, (C<sub>2</sub>H<sub>5</sub>OH) = 8 | |
| 9. |
Bacteria have slightly higher nitrogen content than fungi . |
| A. | True |
| B. | False |
| Answer» B. False | |