MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
We need to apply vector math sometimes in the calculation of the stability of equilibrium configurations. So the coordinate of the Force vector AB is A (2, 0, 2) and B (-2, 3.46, 3). It has a magnitude of 750N. Which is the best Cartesian representation of the vector AB? |
| A. | -557i + 482j + 139k N |
| B. | -557i 482j + 139k N |
| C. | -557i + 482j 139k N |
| D. | 557i 482j 139k N |
| Answer» B. -557i 482j + 139k N | |
| 2. |
For the conditions of the stability of equilibrium configuration of the body, i.e. the body only the external forces defines the equilibrium. Because the internal forces cancels out so not to be considered. |
| A. | The first part of the statement is false and other part is true |
| B. | The first part of the statement is false and other part is false too |
| C. | The first part of the statement is true and other part is false |
| D. | The first part of the statement is true and other part is true too |
| Answer» D. The first part of the statement is true and other part is true too | |
| 3. |
If five forces are acting on the single particle and having an angle of 72 between each and are collinear, then: |
| A. | The net force acting on the body is zero and it is stable |
| B. | The net force acting on the body is horizontal |
| C. | The net force acting on the body is vertical |
| D. | The net force acting on the body is at an angle of 45 |
| Answer» B. The net force acting on the body is horizontal | |
| 4. |
If the body is in stability of equilibrium configuration, but it having a rotational curled ray shown in the free body diagram then: |
| A. | The diagram is wrong |
| B. | Such rotations can t be shown in the fbds(free body diagrams) |
| C. | The ray shown may be correct, but the body is not said to be in equilibrium |
| D. | The body is said to be in equilibrium only, as the other forces will cancel out that rotation |
| Answer» E. | |
| 5. |
If the resolved force for the stability of equilibrium configuration or the force which you get as the answer after solving the question is negative, then what does this implies? |
| A. | The force is in the reverse direction w.r.t the direction set in the free body diagram |
| B. | The force is not in the reverse direction w.r.t the direction set in the free body diagram |
| C. | The force component is not possible |
| D. | The force is possible, but in the direction perpendicular to the resultant force |
| Answer» B. The force is not in the reverse direction w.r.t the direction set in the free body diagram | |
| 6. |
Free body diagrams doesn t play any role in making the calculations on the conditions of stability of equilibrium configuration. |
| A. | True |
| B. | False |
| Answer» C. | |
| 7. |
Which of the following needs to zero for the stability of equilibrium configuration? |
| A. | F=0, M=0 and = 0 |
| B. | F=0, M 0 and = 0 |
| C. | F 0, M=0 and = 0 |
| D. | F=0, M=0 and 0 |
| Answer» E. | |
| 8. |
The net force of the body is zero that means the force are not being applied to the body at all and hence the body has achieved stability. |
| A. | The first part of the statement is false and other part is true |
| B. | The first part of the statement is false and other part is false too |
| C. | The first part of the statement is true and other part is false |
| D. | The first part of the statement is true and other part is true too |
| Answer» D. The first part of the statement is true and other part is true too | |
| 9. |
For stability of equilibrium configuration the net moment acting on the body by various forces is zero. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 10. |
For stability of equilibrium configuration the net force acting on the body is zero. |
| A. | True |
| B. | False |
| Answer» B. False | |