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This section includes 16 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mechanics knowledge and support exam preparation. Choose a topic below to get started.
1. |
We need to apply vector math sometimes in the calculation of the stability of equilibrium configurations. So the coordinate of the Force vector AB is A (2, 0, 2) and B (-2, 3.46, 3). It has a magnitude of 750N. Which is the best Cartesian representation of the vector AB? |
A. | -557i + 482j + 139k N |
B. | -557i – 482j + 139k N |
C. | -557i + 482j – 139k N |
D. | 557i – 482j – 139k N |
Answer» B. -557i – 482j + 139k N | |
2. |
For the conditions of the stability of equilibrium configuration of the body, i.e. the body only the external forces defines the equilibrium. Because the internal forces cancels out so not to be considered. |
A. | The first part of the statement is false and other part is true |
B. | The first part of the statement is false and other part is false too |
C. | The first part of the statement is true and other part is false |
D. | The first part of the statement is true and other part is true too |
Answer» D. The first part of the statement is true and other part is true too | |
3. |
If the body is in stability of equilibrium configuration, but it having a rotational curled ray shown in the free body diagram then: |
A. | The diagram is wrong |
B. | Such rotations can’t be shown in the fbds(free body diagrams) |
C. | The ray shown may be correct, but the body is not said to be in equilibrium |
D. | The body is said to be in equilibrium only, as the other forces will cancel out that rotation |
Answer» E. | |
4. |
If the resolved force for the stability of equilibrium configuration or the force which you get as the answer after solving the question is negative, then what does this implies? |
A. | The force is in the reverse direction w.r.t the direction set in the free body diagram |
B. | The force is not in the reverse direction w.r.t the direction set in the free body diagram |
C. | The force component is not possible |
D. | The force is possible, but in the direction perpendicular to the resultant force |
Answer» B. The force is not in the reverse direction w.r.t the direction set in the free body diagram | |
5. |
Free body diagrams doesn’t play any role in making the calculations on the conditions of stability of equilibrium configuration. |
A. | True |
B. | False |
Answer» C. | |
6. |
Which of the following needs to zero for the stability of equilibrium configuration? |
A. | ∑F=0, ∑M=0 and ∑θ = 0 |
B. | ∑F=0, ∑M≠0 and ∑θ = 0 |
C. | ∑F≠0, ∑M=0 and ∑θ = 0 |
D. | ∑F=0, ∑M=0 and ∑θ≠0 |
Answer» E. | |
7. |
The net force of the body is zero that means the force are not being applied to the body at all and hence the body has achieved stability. |
A. | The first part of the statement is false and other part is true |
B. | The first part of the statement is false and other part is false too |
C. | The first part of the statement is true and other part is false |
D. | The first part of the statement is true and other part is true too |
Answer» D. The first part of the statement is true and other part is true too | |
8. |
For stability of equilibrium configuration the net moment acting on the body by various forces is zero. |
A. | True |
B. | False |
Answer» B. False | |
9. |
For stability of equilibrium configuration the net force acting on the body is zero. |
A. | True |
B. | False |
Answer» B. False | |
10. |
WHICH_OF_THE_FOLLOWING_NEEDS_TO_ZERO_FOR_THE_STABILITY_OF_EQUILIBRIUM_CONFIGURATION??$ |
A. | ∑F=0, ∑M=0 and ∑θ = 0 |
B. | ∑F=0, ∑M≠0 and ∑θ = 0 |
C. | ∑F≠0, ∑M=0 and ∑θ = 0 |
D. | ∑F=0, ∑M=0 and ∑θ≠0 |
Answer» C. ‚Äö√Ñ√∂‚àö‚Ć‚àö¬¥F‚Äö√Ñ√∂‚àö¬¢‚Äö√тĆ0, ‚Äö√Ñ√∂‚àö‚Ć‚àö¬¥M=0 and ‚Äö√Ñ√∂‚àö‚Ć‚àö¬¥‚âà√≠‚Äö√†√® = 0 | |
11. |
The net moment of the body is zero that means the distance between the force and the rotational axis is zero thus the stability of equilibrium configuration. |
A. | The first part of the statement is false and other part is true |
B. | The first part of the statement is false and other part is false too |
C. | The first part of the statement is true and other part is false |
D. | The first part of the statement is true and other part is true too |
Answer» D. The first part of the statement is true and other part is true too | |
12. |
Free body diagrams doesn’t play any role in making the calculations on the conditions of stability of equilibrium configuration.$ |
A. | True |
B. | False |
Answer» B. False | |
13. |
The net force of the body is zero that means the force are not being applied to the body at all and hence the body has achieved stability? |
A. | The first part of the statement is false and other part is true |
B. | The first part of the statement is false and other part is false too |
C. | The first part of the statement is true and other part is false |
D. | The first part of the statement is true and other part is true too |
Answer» B. The first part of the statement is false and other part is false too | |
14. |
Which of the following is correct for the stability of equilibrium configuration? |
A. | The application of the conditions of the equilibrium of the body is valid only in the 2D |
B. | The application of the conditions of the equilibrium of the body is valid only in the 3D |
C. | The application of the conditions of the equilibrium of the body is valid only in the 1D |
D. | The application of the conditions of the equilibrium of the body is valid throughout |
Answer» B. The application of the conditions of the equilibrium of the body is valid only in the 3D | |
15. |
286N |
A. | 68N |
B. | 28N |
C. | 288N |
Answer» B. 28N | |
16. |
The main condition for the stability of the equilibrium configuration is that the distance between various particles of the body does change. |
A. | True |
B. | False |
Answer» C. | |