MCQOPTIONS
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MCQOPTIONS
This section includes 16 Mcqs, each offering curated multiple-choice questions to sharpen your Bioprocess Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Due to algal growth in a water supply reservoir in a neighborhood, the water has acquired an unpleasant taste. The compound is non-degradable, and the water utility has decided that the best way to deal with the situation is simply to flush the contaminant out of the system. The reservoir contains 11,000 m3 of water, and the proposal is to pump 300 m3/h of clean water through the system and discharge the effluent to the sewer system until 95% of the offending compound has been removed. If the reservoir is intensely mixed, how much flushing water will be required?a) 30, 000 m3b) 33, 000 m3c) 35, 000 m3d) 39, 000 m3 10.” A balloon is filled with air at a steady rate.” Which process can be correct for this condition? |
| A. | 30, 000 m3b) 33, 000 m3c) 35, 000 m3d) 39, 000 m3 10.” A balloon is filled with air at a steady rate.” Which process can be correct for this condition?a) Semi – batch |
| B. | 33, 000 m3c) 35, 000 m3d) 39, 000 m3 10.” A balloon is filled with air at a steady rate.” Which process can be correct for this condition?a) Semi – batchb) Batch |
| C. | 35, 000 m3d) 39, 000 m3 10.” A balloon is filled with air at a steady rate.” Which process can be correct for this condition?a) Semi – batchb) Batchc) Fed – batch |
| D. | 39, 000 m3 10.” A balloon is filled with air at a steady rate.” Which process can be correct for this condition?a) Semi – batchb) Batchc) Fed – batchd) ContinuousView Answer |
| Answer» C. 35, 000 m3d) 39, 000 m3 10.” A balloon is filled with air at a steady rate.” Which process can be correct for this condition?a) Semi – batchb) Batchc) Fed – batch | |
| 2. |
Which of the following is not an example of batch process? |
| A. | Cooking |
| B. | Specialty chemicals |
| C. | Refining |
| D. | Brewing |
| Answer» D. Brewing | |
| 3. |
In a batch process, the reaction takes place in the presence of an acid medium. The acid is drained from the reaction vessel at the rate of 15ml/s as a result of the density difference of the acid from the reacting component. To avoid wastage of acid, it is recycled to an acid tank which has 1000 L capacity. The acid drained from the reaction vessel, picks up 50 g/L solids from the reactor. Acid is fed once again to the process from acid tank. When the process is started, the acid is almost pure in the tank as a result of filtration. As the reaction proceeds, acid in the tank gets more and more contaminated with the solids. The concentration of the solids should not exceed 100 g/L from the process point of view. The batch time is 16h. Estimate whether the concentration of the solids will exceed 100g/L during the batch reaction. |
| A. | 37.04 h |
| B. | 30.05 h |
| C. | 36.04 h |
| D. | 32.05 h |
| Answer» B. 30.05 h | |
| 4. |
Determine the volume required for a PFR to obtain the degree of pollutant reduction, Assume that the flow rate and first-order decay rate constant are unchanged (Q = 50 m3/day, k = 0.216 day-1), Cout / Cin = 32/100 = 0.32. |
| A. | 204 m3 |
| B. | 234 m3 |
| C. | 254 m3 |
| D. | 264 m3 |
| Answer» E. | |
| 5. |
The water level in a municipal reservoir has been decreasing steadily during a dry spell, and there is a concern that the drought could continue for another 60 days. The local water company estimates that the consumption rate in the city is approximately 107 L/day. The state conservation service estimates that rainfall and stream drainage into the reservoir coupled with evaporation from the reservoir should yield a net water input rate of 106 exp (-t/100) L/day, where t is the time in days from the beginning of the drought, at which time the reservoir contained an estimated 109 liters of water.Integrate the balance to calculate the reservoir volume at the end of the 60 days of continued drought. |
| A. | 4.50 × 109 L |
| B. | 4.50 × 108 L |
| C. | 4.45 × 108 L |
| D. | 4.45 × 109 L |
| Answer» D. 4.45 × 109 L | |
| 6. |
What is the first – order decay? |
| A. | The rate of loss of the pollutant is constant |
| B. | The rate of loss of the reactant is constant |
| C. | The rate of loss of the pollutant is directly proportional to its concentration |
| D. | The rate of loss of the reactant is directly proportional to its concentration |
| Answer» D. The rate of loss of the reactant is directly proportional to its concentration | |
| 7. |
A compound dissolves in water at a rate proportional to the product of the amount of undissolved solid and the difference between the concentration in a saturated solution and the actual solution; i.e., Csat – C(t). A saturated solution of this compound contains 40 g per 100 g of water. In a test run starting with 20 kg of undissolved compound in 100 kg of water, it was found that 5 kg dissolved in 3 hr. if the test continues, how many kg of compound will remain undissolved after 7 hr? Assume that the system is isothermal. |
| A. | 11.56 kg |
| B. | 10.72 kg |
| C. | 11.76 kg |
| D. | 10.52 kg |
| Answer» C. 11.76 kg | |
| 8. |
WHICH_OF_THE_FOLLOWING_IS_NOT_AN_EXAMPLE_OF_BATCH_PROCESS??$ |
| A. | Cooking |
| B. | Specialty chemicals |
| C. | Refining |
| D. | Brewing |
| Answer» C. Refining | |
| 9. |
Due_to_algal_growth_in_a_water_supply_reservoir_in_a_neighborhood,_the_water_has_acquired_an_unpleasant_taste._The_compound_is_non-degradable,_and_the_water_utility_has_decided_that_the_best_way_to_deal_with_the_situation_is_simply_to_flush_the_contaminant_out_of_the_system._The_reservoir_contains_11,000_m3_of_water,_and_the_proposal_is_to_pump_300_m3_/h_of_clean_water_through_the_system_and_discharge_the_effluent_to_the_sewer_system_until_95%_of_the_offending_compound_has_been_removed._If_the_reservoir_is_intensely_mixed,_how_much_flushing_water_will_be_required?$ |
| A. | 30, 000 m<sup>3</sup> |
| B. | 33, 000 m<sup>3</sup> |
| C. | 35, 000 m<sup>3</sup> |
| D. | 39, 000 m<sup>3</sup> |
| Answer» B. 33, 000 m<sup>3</sup> | |
| 10. |
In a batch process, the reaction takes place in the presence of an acid medium. The acid is drained from the reaction vessel at the rate of 15ml/s as a result of the density difference of the acid from the reacting component. To avoid wastage of acid, it is recycled to an acid tank which has 1000 L capacity. The acid drained from the reaction vessel, picks up 50 g/L solids from the reactor. Acid is fed once again to the process from acid tank. When the process is started, the acid is almost pure in the tank as a result of filtration. As the reaction proceeds, acid in the tank gets more and more contaminated with the solids. The concentration of the solids should not exceed 100 g/L from the process point of view. The batch time is 16h. Estimate whether the concentration of the solids will exceed 100g/L during the batch reaction? |
| A. | 37.04 h |
| B. | 30.05 h |
| C. | 36.04 h |
| D. | 32.05 h |
| Answer» D. 32.05 h | |
| 11. |
Determine the volume required for a PFR to obtain the degree of pollutant reduction, Assume that the flow rate and first-order decay rate constant are unchanged (Q = 50 m3/day, k = 0.216 day-1), Cout / Cin = 32/100 = 0.32. |
| A. | 204 m<sup>3</sup> |
| B. | 234 m<sup>3</sup> |
| C. | 254 m<sup>3</sup> |
| D. | 264 m<sup>3</sup> |
| Answer» B. 234 m<sup>3</sup> | |
| 12. |
Which of the following is the steady state condition based on the water tank concept? |
| A. | Q<sub>in</sub> ≠ Q<sub>out</sub> |
| B. | Q<sub>in</sub> = Q<sub>out</sub> |
| C. | Q<sub>in</sub> > Q<sub>out</sub> |
| D. | Q<sub>in</sub> < Q<sub>out</sub> |
| Answer» E. | |
| 13. |
Which one process is not a transient process? |
| A. | Fed- batch |
| B. | Batch |
| C. | Continuous |
| D. | Semi- batch |
| Answer» C. Continuous | |
| 14. |
50 √ó 109 L$ |
| A. | 4.50 √ó 10<sup>8</sup> L |
| B. | 4.45 √ó 10<sup>8</sup> L |
| C. | 4.45 √ó 10<sup>9</sup> L |
| Answer» B. 4.45 ‚Äö√†√∂‚àö‚â• 10<sup>8</sup> L | |
| 15. |
What is the first – order decay?$ |
| A. | The rate of loss of the pollutant is constant |
| B. | The rate of loss of the reactant is constant |
| C. | The rate of loss of the pollutant is directly proportional to its concentration |
| D. | The rate of loss of the reactant is directly proportional to its concentration |
| Answer» D. The rate of loss of the reactant is directly proportional to its concentration | |
| 16. |
A compound dissolves in water at a rate proportional to the product of the amount of undissolved solid and the difference between the concentration in a saturated solution and the actual solution; i.e., Csat – C(t). A saturated solution of this compound contains 40 g per 100 g of water. In a test run starting with 20 kg of undissolved compound in 100 kg of water, it was found that 5 kg dissolved in 3 hr. if the test continues, how many kg of compound will remain undissolved after 7 hr? Assume that the system is isothermal. |
| A. | 11.56 kg |
| B. | 10.72 kg |
| C. | 11.76 kg |
| D. | 10.52 kg |
| Answer» C. 11.76 kg | |