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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Electric Drives knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The problem of short-circuiting in 1- Full wave semi-converter is very common. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 2. |
Diodes in 1- Full wave semi-converter protects the thyristor from short-circuiting. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 3. |
Calculate the r.m.s value of diode current in 1- Full wave semi-converter for the load (Highly inductive) current=.2 A and =74 . (F.D configuration) |
| A. | .154 A |
| B. | .248 A |
| C. | .128 A |
| D. | .587 A |
| Answer» D. .587 A | |
| 4. |
Calculate the average value of diode current in 1- Full wave semi-converter for the load (Highly inductive) current=5.2 A and =11 . (F.D configuration) |
| A. | .32 A |
| B. | .31 A |
| C. | .25 A |
| D. | .27 A |
| Answer» C. .25 A | |
| 5. |
Calculate the average value of diode current in 1- Full wave semi-converter for the load (Highly inductive) current=75.2 A and =41 . (Asymmetrical configuration) |
| A. | 46.16 A |
| B. | 42.15 A |
| C. | 41.78 A |
| D. | 41.18 A |
| Answer» B. 42.15 A | |
| 6. |
Calculate the average value of thyristor current in 1- Full wave semi-converter for the load (Highly inductive) current=25.65 A and =18 . (Asymmetrical configuration) |
| A. | 11.54 A |
| B. | 12.15 A |
| C. | 15.48 A |
| D. | 14.52 A |
| Answer» B. 12.15 A | |
| 7. |
Calculate the r.m.s value of diode current in 1- Full wave semi-converter for the load (Highly inductive) current=5.1 A and =115 . (Asymmetrical configuration) |
| A. | 4.21 A |
| B. | 4.61 A |
| C. | 4.71 A |
| D. | 4.52 A |
| Answer» C. 4.71 A | |
| 8. |
Calculate the r.m.s value of thyristor current in 1- Full wave semi-converter for the load (Highly inductive) current=2.2 A and =155 . (Asymmetrical configuration) |
| A. | .58 A |
| B. | .57 A |
| C. | .51 A |
| D. | .52 A |
| Answer» C. .51 A | |
| 9. |
Calculate the r.m.s value of source current in 1- Full wave semi-converter for the load (Highly inductive) current=51.2 A and =15 . |
| A. | 10.53 A |
| B. | 14.52 A |
| C. | 44.92 A |
| D. | 49.02 A |
| Answer» E. | |
| 10. |
Calculate the fundamental component of source current in 1- Full wave bridge rectifier for the load(Highly inductive) current=78 A. |
| A. | 78 A |
| B. | 45 A |
| C. | 69 A |
| D. | 13 A |
| Answer» B. 45 A | |
| 11. |
Calculate the circuit turn-off time for 1- Full wave bridge rectifier for =145 . Assume the value of =5 rad/sec. |
| A. | 84.9 msec |
| B. | 94.5 msec |
| C. | 101.2 msec |
| D. | 87.2 msec |
| Answer» E. | |
| 12. |
Calculate the fundamental component of source current in 1- Full wave bridge rectifier for load(Highly inductive) current=3.14 A. |
| A. | 2.82 A |
| B. | 1.45 A |
| C. | 3.69 A |
| D. | 4.78 A |
| Answer» B. 1.45 A | |
| 13. |
Calculate the value of the fundamental displacement factor for 1- Full wave semi-converter if the firing angle value is 69 . |
| A. | .48 |
| B. | .24 |
| C. | .82 |
| D. | .88 |
| Answer» D. .88 | |
| 14. |
Calculate the value of the fundamental displacement factor for 1- Full wave bridge rectifier if the firing angle value is 38 . |
| A. | .22 |
| B. | .78 |
| C. | .33 |
| D. | .44 |
| Answer» C. .33 | |
| 15. |
Calculate the value of the Input power factor for 1- Full wave bridge rectifier if the firing angle value is 39 . |
| A. | .69 |
| B. | .59 |
| C. | .78 |
| D. | .15 |
| Answer» B. .59 | |