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This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Phase Transformation knowledge and support exam preparation. Choose a topic below to get started.
1. |
For the given notation {222}, the spacing of equivalent atom plane is given by________ (Take the lattice parameter a as 2) |
A. | 1/ 3 |
B. | 1/ 2 |
C. | 3 |
D. | 2 |
Answer» B. 1/ 2 | |
2. |
When the macroscopic surface plane has a high or irrational {h k l} index the surface will appear as a stepped layer structure where each layer is a close packed plane. |
A. | True |
B. | False |
Answer» B. False | |
3. |
Equilibrium shapes can be determined experimentally by________ |
A. | Annealing large void inside a crystals |
B. | Annealing large crystals at high temperature |
C. | Annealing small crystals at low temperature |
D. | Annealing small void inside a crystals |
Answer» E. | |
4. |
A convenient method for plotting the variation of with surface orientation in three dimensions is to construct a surface about an origin such that the free energy of any plane is equal to the distance between the surface and the origin when measured along the normal to the plane. This type of polar representation is known as_____ |
A. | -plot |
B. | Surface plot |
C. | Energy plot |
D. | - plot |
Answer» B. Surface plot | |
5. |
The equilibrium shape has the property that the summation of Ai* i (Ai represents the planes and i their respective surface energies) is a minimum and the shape that satisfies this condition is given by the following, so-called as _________ |
A. | Wulff construction |
B. | Marks construction |
C. | Henrys diagram |
D. | Twin diagram |
Answer» E. | |
6. |
If we plot (angle between the crystal plane and closed packed plane) vs E (total surface energy), all the low index planes should be located at________ |
A. | Low energy cusps |
B. | High energy cusps |
C. | In between the low energy cusps and high energy cusps |
D. | Cannot be determined |
Answer» B. High energy cusps | |
7. |
For an isolated crystal bounded by the planes A1, A2, with energies 1 and 2 the total surface energy will be given by _______ |
A. | (A1 1) (A2 2) |
B. | (A1 1) / (A2 2) |
C. | (A1- 1)(A2- 2) |
D. | (A1 1) + (A2 2) |
Answer» E. | |
8. |
A crystal plane is at an angle 45 to the close-packed plane. Calculate the energy of the surface, attributing E/2 energy to each broken bond? (Take the a value as 1(lattice parameter)) |
A. | E/2 |
B. | E |
C. | 2E |
D. | (1/ 2) E |
Answer» E. | |
9. |
Melting point of Sn, Ag, Al, and Au are 232, 961, 660, and 1063(In Degree Celsius) given in their respective order. Which among the following values mentioned below corresponds to the surface energy of Sn? (Options corresponds to the surface energy of the above mentioned 4 elements in mJ m-2) |
A. | 680 |
B. | 1080 |
C. | 1390 |
D. | 1120 |
Answer» B. 1080 | |
10. |
Extra configurational entropy can also be introduced into the surface by the formation of surface vacancies. Entropy effects is slightly dependent on temperature and is given as, = -2T+2. Calculate the entropy S from the given condition? |
A. | T |
B. | -2 |
C. | 2 |
D. | T<sup>2</sup> |
Answer» C. 2 | |
11. |
Considering the nearest neighbours it can be seen that the atoms on a {111} surface, for example, are deprived of three of their twelve neighbours. |
A. | True |
B. | False |
Answer» B. False | |
12. |
Surface free energy is given by_____ |
A. | = E +PV+TS |
B. | = E +PV/TS |
C. | = E +PV*TS |
D. | = E +PV-TS |
Answer» B. = E +PV/TS | |
13. |
If 1 mol of solid is vaporized 12Na broken bonds are formed. Therefore L (Latent heat of sublimation) = 12 Na*E/2(E is the bond strength of metal). Consequently the energy of a {111} surface is given as ___ |
A. | 0.50*L/Na (J/surface atoms) |
B. | 0.75*L/Na (J/surface atoms) |
C. | 0.25*L/Na (J/surface atoms) |
D. | 1.25*L/Na (J/surface atoms) |
Answer» C. 0.25*L/Na (J/surface atoms) | |
14. |
Which among the following plane has the least density of atoms? |
A. | {110} |
B. | {200} |
C. | {220} |
D. | {111} |
Answer» D. {111} | |