MCQOPTIONS
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MCQOPTIONS
This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Integrated Circuit knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Calculate the maximum input frequency at which the output will be distorted from the given specifications
|
| A. | 1000Hz |
| B. | 10kHz |
| C. | 1kHz |
| D. | 10kHz |
| Answer» E. | |
| 2. |
Compute the peak output amplitude, when the voltage gain verses frequency curve of 741C is flat upto 25Hz. |
| A. | 4V<sub>peak</sub> |
| B. | 9V<sub>peak</sub> |
| C. | 20V<sub>peak</sub> |
| D. | None of the mentioned |
| Answer» E. | |
| 3. |
What happens if the frequency or amplitude of the input signal is increased to exceed slew rate of the op-amp? |
| A. | All of the mentioned |
| B. | High frequency output |
| C. | Distorted output |
| D. | Large amplitude output |
| Answer» D. Large amplitude output | |
| 4. |
Determine the maximum input signal to be applied to an op-amp to get distortion free output. If the op-amp used is an inverting amplifier with a gain of 50 and maximum output amplitude obtained is 4.2V sine wave? |
| A. | 159mv |
| B. | 0.168mv |
| C. | 207mv |
| D. | 111mv |
| Answer» C. 207mv | |
| 5. |
Consider a square wave having a peak to peak amplitude of 275mv and it is amplified to a peak to peak amplitude of 4v, with rise time of 5.2 s. Calculate the slew rate? |
| A. | 0.615 v/ s |
| B. | 0.712 v/ s |
| C. | 0.325 v/ s |
| D. | None of the mentioned |
| Answer» B. 0.712 v/ s | |
| 6. |
Calculate the time taken by the output to swing from +14v to -14v for a 741C op-amp having a slew rate of 0.5V/ s? |
| A. | 22 s |
| B. | 42 s |
| C. | 56 s |
| D. | 70 s |
| Answer» D. 70 s | |
| 7. |
Find the expression for full power response. |
| A. | f<sub>max</sub>(Hz) =(slew rate 10<sup>6</sup>)/(6.28 V<sub>m</sub>) |
| B. | f<sub>max</sub>(Hz) =slew rate /(628 10<sup>6</sup> V<sub>m</sub>) |
| C. | f<sub>max</sub>(Hz) =(slew rate V<sub>m</sub> 10<sup>6</sup>)/6.28 |
| D. | f<sub>max</sub>(Hz) =(6.28 V<sub>m</sub> 10<sup>6</sup>)/ slew rate |
| Answer» B. f<sub>max</sub>(Hz) =slew rate /(628 10<sup>6</sup> V<sub>m</sub>) | |
| 8. |
To obtain a faster slew rate the op-amp should have |
| A. | High current and large compensating capacitor |
| B. | Small compensating capacitor |
| C. | High current or small compensating capacitor |
| D. | Low current or large compensating capacitor |
| Answer» D. Low current or large compensating capacitor | |