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This section includes 6 Mcqs, each offering curated multiple-choice questions to sharpen your Heat Transfer Operations Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
1. |
In a shell and tube heat exchanger, in the inner side fluid enters at 15℃ and leaves at 65℃. The shell has oil entering at 105℃ and leaving at 85℃. What is the value of correction factor F? |
A. | 0.94 |
B. | 0.96 |
C. | 0.99 |
D. | 0.91 |
Answer» B. 0.96 | |
2. |
In a shell and tube heat exchanger, in the inner side fluid enters at 15℃ and leaves at 65℃. The shell has oil entering at 105℃ and leaving at 85℃. What is the value of correction factor coefficients R and P? |
A. | R = 0.4, P = 0.55 |
B. | R = 0.3, P = 0.55 |
C. | R = 0.4, P = 0.66 |
D. | R = 0.3, P = 0.66 |
Answer» B. R = 0.3, P = 0.55 | |
3. |
Which one of the following are correct relation of R and P? |
A. | (T/t =shell/tube, 1⁄2 = inlet/outlet) |
B. | R = \(\frac{T_2-T_1}{t_2-t_1}\), P = \(\frac{t_2-t_1}{T_2-T_2}\) |
C. | R = \(\frac{T_2-T_1}{t_2- t_1}\), P = \(\frac{t_2- t_1}{T_1- t_1}\) |
D. | R = \(\frac{T_2-T_1}{t_2- t_1}\), P = \(\frac{t_2- t_1}{T_2- T_1}\) |
E. | R = \(\frac{T_1-T_2}{t_2- t_1}\), P = \(\frac{t_2- t_1}{T_1- t_1}\) |
Answer» E. R = \(\frac{T_1-T_2}{t_2- t_1}\), P = \(\frac{t_2- t_1}{T_1- t_1}\) | |
4. |
In a shell and tube heat exchanger, in the inner side fluid enters at 15℃ and leaves at 65℃. The shell has steam at 1atm. What is the value of corrected LMTD and correction factor? |
A. | 39℃, F = 0 |
B. | 56.35℃, F = 0 |
C. | 70℃, F = 1 |
D. | 56.35℃, F = 1 |
Answer» E. | |
5. |
What is the value of Correction Factor? |
A. | Find the value from the below F-curve chart where R = 2, P = 0.3. |
B. | 0.86 |
C. | 0.90 |
D. | 0.80 |
E. | 0.82 |
Answer» B. 0.86 | |
6. |
When using ΔTLM for a shell and tube heat exchanger, we cannot use the conventional formula for LMTD. |
A. | True |
B. | False |
Answer» B. False | |