MCQOPTIONS
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MCQOPTIONS
This section includes 239 Mcqs, each offering curated multiple-choice questions to sharpen your Operating System knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The replacement of a bad block generally is not totally automatic because ___________ |
| A. | data in bad block can not be replaced |
| B. | data in bad block is usually lost |
| C. | bad block does not contain any data |
| D. | none of the mentioned |
| Answer» C. bad block does not contain any data | |
| 2. |
What will happen during the recovery from a failure? |
| A. | each pair of physical block is examined |
| B. | specified pair of physical block is examined |
| C. | first pair of physical block is examined |
| D. | none of the mentioned |
| Answer» B. specified pair of physical block is examined | |
| 3. |
When we write something on the disk, which one of the following can not happen? |
| A. | successful completion |
| B. | partial failure |
| C. | total failure |
| D. | none of the mentioned |
| Answer» E. | |
| 4. |
RAID level 1 refers to ___________ |
| A. | disk arrays with striping |
| B. | disk mirroring |
| C. | both disk arrays with striping and disk mirroring |
| D. | none of the mentioned |
| Answer» C. both disk arrays with striping and disk mirroring | |
| 5. |
A swap space can reside in ___________ |
| A. | Separate disk partition |
| B. | RAM |
| C. | Cache |
| D. | None of the mentioned |
| Answer» B. RAM | |
| 6. |
The operating system is responsible for? |
| A. | disk initialization |
| B. | booting from disk |
| C. | bad-block recovery |
| D. | all of the mentioned |
| Answer» E. | |
| 7. |
Which algorithm of disk scheduling selects the request with the least seek time from the current head positions? |
| A. | SSTF scheduling |
| B. | FCFS scheduling |
| C. | SCAN scheduling |
| D. | LOOK scheduling |
| Answer» B. FCFS scheduling | |
| 8. |
The time for the disk arm to move the heads to the cylinder containing the desired sector is called ___________ |
| A. | disk time |
| B. | seek time |
| C. | arm time |
| D. | sector time |
| Answer» C. arm time | |
| 9. |
Which private network uses storage protocol rather than networking protocol? |
| A. | storage area network |
| B. | local area network |
| C. | wide area network |
| D. | none of the mentioned |
| Answer» B. local area network | |
| 10. |
For offline storage, data can be backed up with usage of |
| A. | Magnetic tapes |
| B. | Disk drive |
| C. | WORM tapes |
| D. | Magnetic drives |
| Answer» B. Disk drive | |
| 11. |
A magnetic tape type that uses 1/4 inch wide tape ribbon sealed in a cartridge is called |
| A. | Streamer tape |
| B. | Buffer cartridge tape |
| C. | Reel cartridge tape |
| D. | Digital cartridge tape |
| Answer» B. Buffer cartridge tape | |
| 12. |
Magnetic tape can serve as |
| A. | Input media |
| B. | Output media |
| C. | Secondary storage media |
| D. | All of the above |
| Answer» E. | |
| 13. |
Which of the following is not a valid size of a Floppy Disk? |
| A. | 8″ |
| B. | 3 1/2″ |
| C. | 5 1/2″ |
| D. | 5 1/4″ |
| Answer» D. 5 1/4″ | |
| 14. |
What is the latest write-once optical storage media? |
| A. | Digital paper |
| B. | WORM disk |
| C. | CD-ROM disk |
| D. | Magneto-optical disk |
| Answer» D. Magneto-optical disk | |
| 15. |
What does the disk drive of a computer do? |
| A. | Rotate the disk |
| B. | Read the disk |
| C. | Load a program from the disk into the memory |
| D. | Both Rotate the disk and Read the disk |
| Answer» E. | |
| 16. |
Tapes and cartridges are said to be |
| A. | Compact |
| B. | Expensive |
| C. | Light in weight |
| D. | Both a and c |
| Answer» E. | |
| 17. |
The data recording format in most of the modern magnetic tape is |
| A. | 8-bit ASCII |
| B. | 8-bit EBCDIC |
| C. | 7-bit ASCII |
| D. | 7-bit EBCDIC |
| Answer» C. 7-bit ASCII | |
| 18. |
Tapes must be placed in a dust free environment, because they may cause |
| A. | Tape-writing errors |
| B. | Tape-reading errors |
| C. | Tape-blocking errors |
| D. | Tape-accessing errors |
| Answer» C. Tape-blocking errors | |
| 19. |
Data formatting standard used in streamer tapes is known to be |
| A. | Quarter inch cartridge |
| B. | Half inch cartridge |
| C. | Quality inter cartridge |
| D. | Record inter cartridge |
| Answer» B. Half inch cartridge | |
| 20. |
Major form of secondary access device is named as |
| A. | Magnetic Disk |
| B. | Optical Disk |
| C. | CD-ROM |
| D. | Magnetic Tape |
| Answer» E. | |
| 21. |
The number of characters that can be stored in given physical space is |
| A. | Word length |
| B. | Byte |
| C. | Field |
| D. | Data density |
| Answer» E. | |
| 22. |
Word length of a personal computer ___________ |
| A. | 64bits |
| B. | 16 bits |
| C. | 8 bits |
| D. | 32 bits |
| Answer» D. 32 bits | |
| 23. |
Streamer cartridge stores data by using method of |
| A. | Parallel representation |
| B. | Serial representation |
| C. | Absolute representation |
| D. | Compact representation |
| Answer» C. Absolute representation | |
| 24. |
Magnetic disks are suitable for |
| A. | Online storage |
| B. | Offline storage |
| C. | Virtual storage |
| D. | Online and Offline storage |
| Answer» E. | |
| 25. |
Types of secondary storage includes sequential access device and |
| A. | Linear access device |
| B. | Absolute access device |
| C. | Zip access device |
| D. | Direct access device |
| Answer» E. | |
| 26. |
Type of device which is 3.5 inch floppy drive is nothing but |
| A. | storage |
| B. | input |
| C. | output |
| D. | software |
| Answer» B. input | |
| 27. |
A track of a magnetic tape comprises of |
| A. | 4 sectors |
| B. | 6 sectors |
| C. | 8 sectors |
| D. | 10 sectors |
| Answer» D. 10 sectors | |
| 28. |
Magnetic tapes can be reused and erased for |
| A. | One time only |
| B. | Two times only |
| C. | Multiple times |
| D. | Not at all |
| Answer» D. Not at all | |
| 29. |
The storage capacity of a disk system depends on the bits per inch of track and the tracks per inch of |
| A. | Cluster |
| B. | Surface |
| C. | Cylinder |
| D. | Hum |
| Answer» C. Cylinder | |
| 30. |
The secondary storage devices can only store data but they cannot perform |
| A. | Arithmetic Operation |
| B. | Logic operation |
| C. | Fetch operations |
| D. | Either Arithmetic or Logic or Fetch operations |
| Answer» E. | |
| 31. |
CD-ROM is a |
| A. | Semiconductor memory |
| B. | Magnetic memory |
| C. | Memory register |
| D. | None of the above |
| Answer» E. | |
| 32. |
In fixed head discs, sum of rotational delay and transfer time is equals to |
| A. | access time |
| B. | delay time |
| C. | processing time |
| D. | storage time |
| Answer» B. delay time | |
| 33. |
Type of tape having width of half an inch and is 730 meters in length is known as |
| A. | standard magnetic tape |
| B. | customized tape |
| C. | direct recording tape |
| D. | sequential recording tape |
| Answer» B. customized tape | |
| 34. |
The disk’s surface is divided into a number of invisible concentric circles called: |
| A. | Drives |
| B. | Tracks |
| C. | Slits |
| D. | References |
| Answer» C. Slits | |
| 35. |
A DVD is |
| A. | optical disk |
| B. | output device |
| C. | solid state storage |
| D. | hard disk |
| Answer» B. output device | |
| 36. |
QIC stands for |
| A. | Quality input carrier |
| B. | Quality instable computation |
| C. | Quarter inch cartridge |
| D. | Quarter inaction compound |
| Answer» D. Quarter inaction compound | |
| 37. |
A magnetic tape can be used as a shared device because of its property known to be |
| A. | Indirect access |
| B. | Random access |
| C. | Sequential access |
| D. | Direct access |
| Answer» D. Direct access | |
| 38. |
Unit used to store contents as backup of data for later disc failure is called as |
| A. | tape streamers |
| B. | disc streamers |
| C. | direct streamers |
| D. | serial streamers |
| Answer» B. disc streamers | |
| 39. |
The number of clock cycles per second is referred as ______ |
| A. | Clock speed |
| B. | Clock frequency |
| C. | Clock rate |
| D. | Clock timing |
| Answer» B. Clock frequency | |
| 40. |
Data on magnetic disk is recorded in form of |
| A. | Magnetized spots and mechanized spots |
| B. | Non-magnetized and non-mechanized spots |
| C. | Magnetized spots and non-magnetized spots |
| D. | Mechanized spots and non-mechanized spots |
| Answer» D. Mechanized spots and non-mechanized spots | |
| 41. |
Serial or direct access occurs in |
| A. | temporary store |
| B. | permanent store |
| C. | backing store |
| D. | erasable store |
| Answer» D. erasable store | |
| 42. |
UDF stands for |
| A. | undated disk format |
| B. | universal data frequency |
| C. | unique disk format |
| D. | universal disk format |
| Answer» E. | |
| 43. |
Average transfer rate can be calculated as |
| A. | Average seek time -Average latency |
| B. | Average seek time + Average latency |
| C. | Average seek time -Average latency/2 |
| D. | Average seek time + Average latency/2 |
| Answer» C. Average seek time -Average latency/2 | |
| 44. |
The term gigabyte refers to |
| A. | 1024 bytes |
| B. | 1024 gigabyte |
| C. | 1024 megabytes |
| D. | 1024 kilobytes |
| Answer» D. 1024 kilobytes | |
| 45. |
Which of the following is not true for a magnetic disk? |
| A. | It is expensive relative to magnetic tape |
| B. | Users can easily update records by writing over the old data |
| C. | It provides only sequential access to stored data |
| D. | All of the above |
| Answer» D. All of the above | |
| 46. |
To maintain security of information is difficult that is stored on |
| A. | Secondary storage |
| B. | Offline storage |
| C. | Online storage |
| D. | Virtual storage |
| Answer» D. Virtual storage | |
| 47. |
Hard disk is coated in both side above |
| A. | Optical metallic oxide |
| B. | Carbon layer |
| C. | Magnetic metallic oxide |
| D. | All of the above |
| Answer» D. All of the above | |
| 48. |
What is the full form of USB in Secondary Storage? |
| A. | Universal Signal Board |
| B. | Universal Signal Bus |
| C. | Universal Serial Bus |
| D. | Universal Serial Board |
| Answer» D. Universal Serial Board | |
| 49. |
Cost per bit of storage in terms of primary memory of computer is |
| A. | Low |
| B. | High |
| C. | Incomputable |
| D. | Unknown |
| Answer» C. Incomputable | |
| 50. |
Replacement of a bad block generally is not automatic because |
| A. | data in bad block can not be replaced |
| B. | data in bad block is usually lost |
| C. | bad block does not contain any data |
| D. | data in bad block is formated |
| Answer» C. bad block does not contain any data | |