MCQOPTIONS
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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Mathematics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the second order derivative if y=e2x2. |
| A. | 4e2x2 (4x2+3) |
| B. | 4e2x2 (4x2-1) |
| C. | 4e2x2 (4x2+1) |
| D. | e2x2 (4x2+1) |
| Answer» D. e2x2 (4x2+1) | |
| 2. |
Find the second order derivative of y=3x2 1 + log(4x) |
| A. | 3+\(\frac{1}{x^2}\) |
| B. | 3-\(\frac{1}{x^2}\) |
| C. | 6-\(\frac{1}{x^2}\) |
| D. | 6+\(\frac{1}{x^2}\) |
| Answer» D. 6+\(\frac{1}{x^2}\) | |
| 3. |
Find the second order derivative y=e2x+sin-1ex . |
| A. | e2x+\(\frac{e^x}{(1-e^2x)^{3/2}}\) |
| B. | 4e2x+\(\frac{1}{(1-e^2x)^{3/2}}\) |
| C. | 4e2x–\(\frac{e^x}{(1-e^2x)^{3/2}}\) |
| D. | 4e2x+\(\frac{e^x}{(1-e^2x)^{3/2}}\) |
| Answer» E. | |
| 4. |
Find \(\frac{d^2 y}{dx^2}\)-6 \(\frac{dy}{dx}\) if y=4x4+2x. |
| A. | \((4x^2+8x-1)\) |
| B. | \(12(4x^2+8x-1)\) |
| C. | –\(12(4x^2+8x-1)\) |
| D. | \(12(4x^2-8x-1)\) |
| Answer» E. | |
| 5. |
If y=log(2x3), find \(\frac{d^2 y}{dx^2}\). |
| A. | –\(\frac{2}{x^2}\) |
| B. | \(\frac{3}{x^2}\) |
| C. | \(\frac{2}{x^2}\) |
| D. | –\(\frac{3}{x^2}\) |
| Answer» E. | |
| 6. |
Find \(\frac{d^2 y}{dx^2}\), if y=2 sin-1(cosx). |
| A. | 0 |
| B. | sin-1\((\frac{1}{cosx})\) |
| C. | 1 |
| D. | -1 |
| Answer» B. sin-1\((\frac{1}{cosx})\) | |
| 7. |
Find the second order derivative of y=2e2x-3 log(2x-3). |
| A. | 8e2x+\(\frac{1}{(2x-3)^2}\) |
| B. | 8e2x–\(\frac{12}{(2x-3)^2}\) |
| C. | e2x+\(\frac{12}{(2x-3)^2}\) |
| D. | 8e2x+\(\frac{12}{(2x-3)^2}\) |
| Answer» E. | |
| 8. |
If y=6x2+3, then \(\left (\frac{dy}{dx}\right )^2=\frac{d^2 y}{dx^2}\). |
| A. | True |
| B. | False |
| Answer» C. | |
| 9. |
Find \(\frac{d^2y}{dx^2}\), if y=tan2x+3 tanx. |
| A. | sec2x tanx (2 tanx+secx+3) |
| B. | 2 sec2x tanx (2 tanx-secx+3) |
| C. | 2 sec2x tanx (2 tanx+secx+3) |
| D. | 2 sec2x tanx (2 tanx+secx-3) |
| Answer» D. 2 sec2x tanx (2 tanx+secx-3) | |
| 10. |
Find the second order derivative of y=9 log t3. |
| A. | \(\frac{27}{t^2}\) |
| B. | –\(\frac{27}{t^2}\) |
| C. | –\(\frac{1}{t^2}\) |
| D. | –\(\frac{27}{2t^2}\) |
| Answer» C. –\(\frac{1}{t^2}\) | |