MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z22 in terms of Inverse Hybrid parameters can be expressed as ________ |
| A. | z22 = \(\frac{1}{g_{11}} \) |
| B. | z22 = – \(\frac{g_{12}}{g_{11}} \) |
| C. | z22 = – \(\frac{g_{21}}{g_{11}} \) |
| D. | z22 = \(\left(g_{22} – \frac{g_{21} g_{12}}{g_{11}}\right)\) |
| Answer» E. | |
| 2. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z12 in terms of Inverse Hybrid parameters can be expressed as ________ |
| A. | z12 = \(\frac{1}{g_{11}} \) |
| B. | z12 = – \(\frac{g_{12}}{g_{11}} \) |
| C. | z12 = – \(\frac{g_{21}}{g_{11}} \) |
| D. | z12 = \(\left(g_{22} – \frac{g_{21} g_{12}}{g_{11}}\right)\) |
| Answer» C. z12 = – \(\frac{g_{21}}{g_{11}} \) | |
| 3. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z11 in terms of Inverse Hybrid parameters can be expressed as ________ |
| A. | z12 = \(\frac{1}{g_{11}} \) |
| B. | z12 = – \(\frac{g_{12}}{g_{11}} \) |
| C. | z12 = – \(\frac{g_{21}}{g_{11}} \) |
| D. | z12 = \(\left(g_{22} – \frac{g_{21} g_{12}}{g_{11}}\right)\) |
| Answer» B. z12 = – \(\frac{g_{12}}{g_{11}} \) | |
| 4. |
A 10 μF capacitor is charged from a 5 volt source through a resistance of 10 kΩ. The charging current offer 35 m sec. If the initial voltage on C is – 3 V is ___________ |
| A. | 0.56 mA |
| B. | 5.6 mA |
| C. | 6 mA |
| D. | 5 μA |
| Answer» B. 5.6 mA | |
| 5. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z22 in terms of Hybrid parameters can be expressed as ________ |
| A. | z22 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \) |
| B. | z22 = – \(\frac{h_{21}}{h_{22}} \) |
| C. | z22 = \(\frac{h_{12}}{h_{22}} \) |
| D. | z22 = \(\frac{1}{h_{22}} \) |
| Answer» E. | |
| 6. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z12 in terms of Hybrid parameters can be expressed as ________ |
| A. | z12 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \) |
| B. | z12 = – \(\frac{h_{21}}{h_{22}} \) |
| C. | z12 = \(\frac{h_{12}}{h_{22}} \) |
| D. | z12 = \(\frac{1}{h_{22}} \) |
| Answer» D. z12 = \(\frac{1}{h_{22}} \) | |
| 7. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z11 in terms of Hybrid parameters can be expressed as ________ |
| A. | z11 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \) |
| B. | z11 = – \(\frac{h_{21}}{h_{22}} \) |
| C. | z11 = \(\frac{h_{12}}{h_{22}} \) |
| D. | z11 = \(\frac{1}{h_{22}} \) |
| Answer» B. z11 = – \(\frac{h_{21}}{h_{22}} \) | |
| 8. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z21 in terms of Hybrid parameters can be expressed as ________ |
| A. | z21 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \) |
| B. | z21 = – \(\frac{h_{21}}{h_{22}} \) |
| C. | z21 = \(\frac{h_{12}}{h_{22}} \) |
| D. | z21 = \(\frac{1}{h_{22}} \) |
| Answer» C. z21 = \(\frac{h_{12}}{h_{22}} \) | |
| 9. |
For a T-network if the Short circuit admittance parameters are given as y11, y21, y12, y22, then y21 in terms of Hybrid parameters can be expressed as ________ |
| A. | y21 = \(\left(- \frac{h_{21} h_{12}}{h_{11}} + h_{22}\right)\) |
| B. | y21 = \(\frac{h_{21}}{h_{11}} \) |
| C. | y21 = –\(\frac{h_{12}}{h_{11}} \) |
| D. | y21 = \(\frac{1}{h_{11}} \) |
| Answer» C. y21 = –\(\frac{h_{12}}{h_{11}} \) | |
| 10. |
In the circuit given below, the current through R is 2 sin 8t. The value of R is ___________ |
| A. | (0.18 + j0.72) |
| B. | (0.46 + j1.90) |
| C. | – (0.18 + j1.90) |
| D. | (0.23 – 0.35 j) |
| Answer» E. | |
| 11. |
A constant k high pass p section has a characteristic impedance of 300 Ω at f = ∞. At f = fc, the characteristic impedance will be? |
| A. | 0 |
| B. | ∞ |
| C. | 300 Ω |
| D. | More than 300 Ω |
| Answer» C. 300 Ω | |
| 12. |
A periodic voltage v (t) = 1 + 4 sin ωt + 2 cos ωt is applied across a 1Ω resistance. The power dissipated is ____________ |
| A. | 1 W |
| B. | 11 W |
| C. | 21 W |
| D. | 24.5 W |
| Answer» C. 21 W | |