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This section includes 19 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mechanics knowledge and support exam preparation. Choose a topic below to get started.
1. |
The body is sometimes acted by two or three force members and we need to find the radius of gyration for the same. The difference between the two and the three force members is: |
A. | The former is collinear and the latter is parallel |
B. | The former is parallel and the latter is perpendicular |
C. | The former is perpendicular and the latter is collinear |
D. | The former is acting on two points in the body while the latter is on three points |
Answer» E. | |
2. |
If any external force also is applied on the structure and we are determining radius of gyration then what should we consider? |
A. | The net force will act at the centroid of the structure only |
B. | The net load will not be formed as all the forces will be cancelled |
C. | The net force will act on the base of the loading horizontally |
D. | The net force will not to be considered, there would be a net force of the distribution, rest will be the external forces |
Answer» E. | |
3. |
If the non-Uniform loading is of the type of parabola then for calculating the radius of gyration? |
A. | The net load will not be formed as all the forces will be cancelled |
B. | The net force will act the centre of the parabola |
C. | The net force will act on the base of the loading horizontally |
D. | The net force will act at the centroid of the parabola |
Answer» E. | |
4. |
One of the use of the centre of mass or centroid is as in the radius of gyration is that the net force acts at the ___________ of the loading body. |
A. | Centroid |
B. | The centre axis |
C. | The corner |
D. | The base |
Answer» B. The centre axis | |
5. |
The parallel axis theorem can add any angle varied moment of inertias to give the perpendicular moment of inertia and the radius of gyration can be calculated. |
A. | True |
B. | False |
Answer» C. | |
6. |
Radius of gyration is indirectly to the parallel axis theorem. The parallel axis theorem gives the moment of inertia ______________ to the surface of considesrance. |
A. | Linear |
B. | Non-Linear |
C. | Perpendicular |
D. | Parallel |
Answer» D. Parallel | |
7. |
There is perpendicular axis theorem for the calculation of the radius of gyration. |
A. | True |
B. | False |
Answer» C. | |
8. |
Moment of Inertia is the integration of the square of the distance of the centroid and the del area along the whole area of the structure and this moment is at a distance from the rotating axis, known as the radius of gyration. |
A. | True |
B. | False |
Answer» B. False | |
9. |
How far from the shaft at P a 200N vertical force must act so as to create the same moment as produced by the 75N, at P? |
A. | 1.2m |
B. | 1.125m |
C. | 0.6m |
D. | 0mView Answer |
Answer» C. 0.6m | |
10. |
Find the moment of the force about the point R. |
A. | 5000Nm |
B. | 5550Nm |
C. | 6000Nm |
D. | 7000NmView Answer |
Answer» B. 5550Nm | |
11. |
THERE_IS_PERPENDICULAR_AXIS_THEOREM_FOR_THE_CALCULATION_OF_THE_RADIUS_OF_GYRATION.?$ |
A. | True |
B. | False |
Answer» B. False | |
12. |
Radius of gyration is indirectly to the parallel axis theorem. The parallel axis theorem gives the moment of inertia ______________ to the surface of considesrance.$ |
A. | Linear |
B. | Non-Linear |
C. | Perpendicular |
D. | Parallel |
Answer» B. Non-Linear | |
13. |
The distance in the parallel axis theorem is multiplied by: |
A. | Area |
B. | Volume |
C. | Linear distance |
D. | Area/Volume |
Answer» E. | |
14. |
As radius of gyration is indirectly to the parallel axis theorem, parallel axis theorem uses the ____________ of the distance. |
A. | Square root |
B. | Square |
C. | Cube root |
D. | Cube |
Answer» E. | |
15. |
Moment of Inertia is the integration of the square of the distance of the centroid and the del area along the whole area of the structure and this moment is at a distance from the rotating axis, known as the radius of gyration? |
A. | True |
B. | False |
Answer» C. | |
16. |
2? |
A. | 1.125m |
B. | 0.6m |
C. | 0m |
Answer» C. 0m | |
17. |
5000Nm |
A. | 5550Nm |
B. | 6000Nm |
C. | 7000Nm |
Answer» B. 6000Nm | |
18. |
The radius of gyration is related to the moment of the body. So the calculation of the moment of the body due to the loadings involve a quantity called ____________ |
A. | Moment |
B. | Inertia |
C. | Moment of Inertia |
D. | Rotation |
Answer» D. Rotation | |
19. |
In the calculation of the radius of gyration, we use intensity of loadings. So whenever the distributed loading acts perpendicular to an area its intensity varies __________ |
A. | Linearly |
B. | Non-Linearly |
C. | Parabolically |
D. | Cubically |
Answer» B. Non-Linearly | |