MCQOPTIONS
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MCQOPTIONS
This section includes 2242 Mcqs, each offering curated multiple-choice questions to sharpen your Php knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
Mostly the high voltage transmission is provided by overhead lines due to _____________ |
| A. | low cost |
| B. | low losses |
| C. | easy installation |
| D. | all of the mentioned |
| Answer» B. low losses | |
| 152. |
As compared with the HVAC lines, dc transmission system is free from ___________ |
| A. | inductance |
| B. | capacitance |
| C. | phase displacement |
| D. | all of the mentioned |
| Answer» E. | |
| 153. |
HVDC transmission would require which of the following equipment’s?(i) Pulse converter(ii) AC filter(iii) DC filter(iv) DC generator |
| A. | (i) |
| B. | (i), (ii) |
| C. | (ii), (iv) |
| D. | (i), (iii) |
| Answer» B. (i), (ii) | |
| 154. |
Back to back HVDC is used to ___________ |
| A. | increase the transmission capability |
| B. | decrease line losses |
| C. | provide a stable connection |
| D. | reduce the voltage drop |
| Answer» D. reduce the voltage drop | |
| 155. |
As depicted in the figure, the power is transferred in the system from B to A by a HVDC link as shown in the figure. The voltages are indicated in the figure and I <0, then ______ |
| A. | Vab<0, Vcd<0, Vab>Vcd |
| B. | Vab<0, Vcd>0, Vab<Vcd |
| C. | Vab>0, Vcd>0, Vab<Vcd |
| D. | Vab>0, Vcd>0, Vab>Vcd |
| Answer» D. Vab>0, Vcd>0, Vab>Vcd | |
| 156. |
As depicted in the figure, the power will be transferred in the system from A to B by a HVDC link as shown in the figure. The voltages are indicated in the figure and I >0, then _______ |
| A. | Vab<0, Vcd<0, Vab>Vcd |
| B. | Vab<0, Vcd>0, Vab<Vcd |
| C. | Vab>0, Vcd<0, Vab>Vcd |
| D. | Vab>0, Vcd>0, Vab>Vcd |
| Answer» E. | |
| 157. |
The power transmission capability of bipolar lines is approximately ____________ |
| A. | same as that of 3-ph single circuit line |
| B. | same as that of 3-ph double circuit line |
| C. | twice to that of 3-ph single circuit line |
| D. | half to that of 3-ph single circuit line |
| Answer» B. same as that of 3-ph double circuit line | |
| 158. |
Step climb helps in saving fuel. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 159. |
Cruise method 1 is ideal for troposphere. |
| A. | True |
| B. | False |
| Answer» C. | |
| 160. |
What is endurance function? |
| A. | \(\big[\frac{E_{max}}{C}\big]\) |
| B. | lnω |
| C. | \(\big\{\frac{2u^2}{u^4+1}\big\}\) |
| D. | \(\big\{\frac{2u^2}{u^4+1}\big\}\)lnω |
| Answer» E. | |
| 161. |
What is endurance factor? |
| A. | \(\big[\frac{E_{max}}{C}\big]\) |
| B. | \(\big[\frac{E_{max}}{VC}\big]\) |
| C. | \(\big\{\frac{2u^3}{u^4+1}\big\}\) |
| D. | \(\big\{\frac{2u^4}{u^4+1}\big\}\) |
| Answer» B. \(\big[\frac{E_{max}}{VC}\big]\) | |
| 162. |
Which of the following is correct statement regarding cruise method 1? |
| A. | Fuel ratio for very long range aircraft is 1.3 |
| B. | Fuel ratio for short range aircraft is 1.3 |
| C. | Fuel ratio for medium to long range aircraft is 1.3 |
| D. | Fuel ratio for short range aircraft is 1.5 |
| Answer» D. Fuel ratio for short range aircraft is 1.5 | |
| 163. |
Minimum range is given when the aircraft is fly’s at u=1.316. |
| A. | True |
| B. | False |
| Answer» C. | |
| 164. |
Which of the following represents range function? |
| A. | \(\Big[\frac{V_{mdi}}{C}E_{max}\Big]\)lnω |
| B. | \(\Big[\frac{V_{max}}{C}E_{max}\Big]\)lnω |
| C. | \(\Big\{\frac{2u^3}{u^4+1}\Big\}\)lnω |
| D. | \(\Big\{\frac{2u^4}{u^4+1}\Big\}\)lnω |
| Answer» D. \(\Big\{\frac{2u^4}{u^4+1}\Big\}\)lnω | |
| 165. |
Relative airspeed acts as a shaping factor. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 166. |
Calculate the amount of sand required for the following data.Flow: 200 m3/hVelocity of dual media filter: 15m/hHeight: 0.4 m |
| A. | 12668 Kg |
| B. | 9237 Kg |
| C. | 1020 Kg |
| D. | 12752 Kg |
| Answer» C. 1020 Kg | |
| 167. |
Calculate the amount of pebbles required for the following data.Flow: 200 m3/hVelocity of dual media filter: 15m/hHeight: 0.6 m |
| A. | 12668 Kg |
| B. | 13792 Kg |
| C. | 35000 Kg |
| D. | 15792 Kg |
| Answer» B. 13792 Kg | |
| 168. |
Calculate the flow rate of the backwash pump to be used for a multimedia filter with the following data.Flowrate: 2200 m3/hRise velocity of multimedia filter: 18 m/h |
| A. | 3700 m3/ h |
| B. | 2900 m3/ h |
| C. | 5300 m3/ h |
| D. | 3800 m3/ h |
| Answer» C. 5300 m3/ h | |
| 169. |
Calculate the flow rate of the backwash pump to be used for a pressure sand filter with the following data.Flowrate: 2200 m3/hRise velocity of PSF (Pressure Sand filter): 10 m/h |
| A. | 4500 m3/ h |
| B. | 5280 m3/ h |
| C. | 6480 m3/ h |
| D. | 7580 m3/ h |
| Answer» C. 6480 m3/ h | |
| 170. |
Calculate the flow rate of the backwash pump to be used for a dual media filter with the following data.Flowrate: 2200 m3/hRise velocity of DMF: 15 m/h |
| A. | 4500 m3/ h |
| B. | 3520 m3/ h |
| C. | 3750 m3/ h |
| D. | 4920 m3/ h |
| Answer» C. 3750 m3/ h | |
| 171. |
While designing a blower for backwash for multimedia filters without air scouring what is the velocity considered? |
| A. | 36 m/h |
| B. | 30 m/h |
| C. | 24 m/h |
| D. | 20 m/h |
| Answer» D. 20 m/h | |
| 172. |
While designing a blower for backwash for dual media filters without air scouring what is the velocity considered? |
| A. | 36 m/h |
| B. | 30 m/h |
| C. | 24 m/h |
| D. | 20 m/h |
| Answer» C. 24 m/h | |
| 173. |
While designing a blower for backwash for sand filters with air scouring what is the velocity considered? |
| A. | 36 m/h |
| B. | 30 m/h |
| C. | 24 m/h |
| D. | 20 m/h |
| Answer» D. 20 m/h | |
| 174. |
Calculate the diameter of a multimedia filter with the following data.Flow: 2200 m3/hrVelocity: 18 m/hr |
| A. | 13.3 m |
| B. | 14.5 m |
| C. | 12.5 m |
| D. | 12.9 m |
| Answer» D. 12.9 m | |
| 175. |
Calculate the diameter of a dual media filter with the following data.Flow: 2200 m3/hrVelocity: 15 m/hr |
| A. | 15.5 m |
| B. | 13.6 m |
| C. | 13.9 m |
| D. | 16.5 m |
| Answer» C. 13.9 m | |
| 176. |
Which of the following comprises large cone-shaped protozoa? |
| A. | Didinium |
| B. | Vorticella |
| C. | Stentor |
| D. | Colpoda |
| Answer» D. Colpoda | |
| 177. |
During binary fission in Paramecium, the rear daughter cell receives a new gullet? |
| A. | True |
| B. | False |
| Answer» C. | |
| 178. |
Undigested particles are eliminated from the cell through the ___________________ |
| A. | gullet |
| B. | contractile vacuole |
| C. | cytoproct |
| D. | cell membrane |
| Answer» D. cell membrane | |
| 179. |
Members of order Diplomonadida have how many flagella? |
| A. | 2 to 4 |
| B. | 6 to 8 |
| C. | 2 to 8 |
| D. | 1 to 2 |
| Answer» C. 2 to 8 | |
| 180. |
What is the name of the compound? |
| A. | Paraffin wax |
| B. | Polyethylene |
| C. | Natural rubber |
| D. | IsopreneView Answer |
| Answer» C. Natural rubber | |
| 181. |
Ink doesn’t consists of pigments, such as TiO2, to supply colour and opacity and a vehicle to carry the pigment and bind it to the paper. |
| A. | True |
| B. | False |
| Answer» C. | |
| 182. |
Fillers include _________ which could interfere with rosin/alum sizing, clays, and TiO2. |
| A. | Calcium hydroxide |
| B. | Calcium silicate |
| C. | Calcium carbonate |
| D. | Hydrogen silicate |
| Answer» D. Hydrogen silicate | |
| 183. |
Recycled fiber is separated from _________ which’s off-specification paper produced at the mill and reused within the mill. |
| A. | Reel |
| B. | Broke |
| C. | Matte |
| D. | Emulsion |
| Answer» C. Matte | |
| 184. |
The source of_________ was arising from the locations outside the mills which helped to expedite the paper making process. |
| A. | Recycled fiber |
| B. | Used fiber |
| C. | Used latex |
| D. | Used lignin |
| Answer» B. Used fiber | |
| 185. |
The “lac promoter” is the sequence that controls transcription of _____________ |
| A. | LacZ’ gene |
| B. | Trp gene |
| C. | Lambda DNA |
| D. | Amylose |
| Answer» B. Trp gene | |
| 186. |
The “tac promoter” is induced by _______ |
| A. | Lactose |
| B. | Amylose |
| C. | Lactose |
| D. | IPTG |
| Answer» E. | |
| 187. |
High level of transcription may affect the ability of the recombinant plasmid to _____________ |
| A. | Express |
| B. | Sustain |
| C. | Replicate |
| D. | Take up DNA |
| Answer» D. Take up DNA | |
| 188. |
A repressible gene is the one that can be _________ |
| A. | Switched off |
| B. | Switched on |
| C. | Expressed |
| D. | Killed |
| Answer» B. Switched on | |
| 189. |
An inducible gene is the one whose __________ can be switched on by the addition of a chemical to the medium. |
| A. | Translocation |
| B. | Transcription |
| C. | Replication |
| D. | Translation |
| Answer» C. Replication | |
| 190. |
What is the most critical component of an expression vector? |
| A. | Terminator |
| B. | Suppressor |
| C. | Inducer |
| D. | Promoter |
| Answer» E. | |
| 191. |
Using which of the given formula the chimney height is calculated to get the answer of 67.4m when the coal burnt is 18.8TPH and considering 0.5% of sulfur content in coal? |
| A. | H = 12(Q)13 |
| B. | H = 17(Q)13 |
| C. | H = 14(Q)13 |
| D. | H = 22(Q)13 |
| Answer» D. H = 22(Q)13 | |
| 192. |
A 15kg of air is supplied per kg of fuel burnt to the combustion chamber of a boiler using fuel 600kg/hr. the temperature of flue gases and ambient air are 273°C and 32°C. If the minimum draught required to start the flue is 9.5mm of water, find out the minimum height of the chimney? |
| A. | 22.66m |
| B. | 23.84m |
| C. | 24.52m |
| D. | 25.16m |
| Answer» B. 23.84m | |
| 193. |
The flue gases of natural draught are at higher temperature when compared to flue gases in artificial gas. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 194. |
Determine the height of the chimney to produce a static draught of 22mm of water if the mean flue gas temperature in chimney is 290oC and ambient temperature in boiler house is 20oC. The gas constant for air is 29.26Kgm/Kgk and for chimney flue gas is 26.2 Kgfm/Kgk. Assume reading as 760mm of mercury? |
| A. | 38.42m |
| B. | 42.55m |
| C. | 45.84m |
| D. | 44.03m |
| Answer» C. 45.84m | |
| 195. |
A draught of 15mm of water is produced by using a chimney of height 30m. The ambient air and flue gases are at 27oC and 300oC respectively. The coal burned on the grate contains 81% carbon, 5% moisture and remaining ash. Neglect the losses and assume values of burnt products equivalent to the volume of air supplied and for the complete combustion of fuel, find the percentage of excess of air supplied? |
| A. | 14.56% |
| B. | 52.89% |
| C. | 8.13% |
| D. | 20.002% |
| Answer» D. 20.002% | |
| 196. |
Determine the height of chimney above grate level. Where diameter of chimney is 1.75m and produces a draught of 1.8cms of water. Temperature of flue gases is 290oC. The flue gases formed per kg of fuel burnt are 23kg. Neglect the losses and assume atmospheric temperature as 20oC? |
| A. | H = 23.28m |
| B. | H = 18.56m |
| C. | H = 32.77m |
| D. | H = 41.92m |
| Answer» D. H = 41.92m | |
| 197. |
Which is the equation used to find chimney diameter? |
| A. | D = 1.128\(\sqrt{\frac{Mg}{ρg V}}\) |
| B. | D = 5.48\(\sqrt{\frac{ρg V}{Mg}}\) |
| C. | D = 5.48\(\sqrt{\frac{Mg}{ρg V}}\) |
| D. | D = 1.128\(\sqrt{\frac{ρg V}{Mg}}\) |
| Answer» B. D = 5.48\(\sqrt{\frac{ρg V}{Mg}}\) | |
| 198. |
Which is the net pressure equation used to find chimney height?a) P = H (Wa-Wg)b) P = H (Wa+Wg)c) P = H (Wg-W |
| A. | P = H (Wa-Wg) |
| B. | P = H (Wa+Wg) |
| C. | P = H (Wg-Wa) |
| D. | P = H (\(\frac{W_a}{W_g}\)) |
| Answer» B. P = H (Wa+Wg) | |
| 199. |
Jacobin equation is solved using the |
| A. | Matrix Multiplication |
| B. | LU Factorization |
| C. | Elimination Method |
| D. | Follow up method |
| Answer» C. Elimination Method | |
| 200. |
The first assumption of the NR Method is |
| A. | Assume K=0 |
| B. | Assume Xi = 0 |
| C. | Assume F(x) = 0 |
| D. | Assume F’(x) = 0 |
| Answer» B. Assume Xi = 0 | |