MCQOPTIONS
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This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Signals Systems knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z| |
| A. | \(\frac{z^{-3}}{(z^2-16)^2}\) |
| B. | \(\frac{z^7}{(z^2-16)^2}\) |
| C. | \(\frac{z^5}{(z^2-16)^2}\) |
| D. | \(\frac{z}{(z^2-16)^2}\) |
| Answer» E. | |
| 2. |
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z| |
| A. | \(\frac{z^2}{16z^2-257z^4-16}\) |
| B. | \(\frac{-16z^2}{(z^2-16)^2}\) |
| C. | \(\frac{z^2}{(257z^2-16z^4-16)}\) |
| D. | \(\frac{16z^2}{(z^2-16)^2}\) |
| Answer» D. \(\frac{16z^2}{(z^2-16)^2}\) | |
| 3. |
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z| |
| A. | \(\frac{(z+2)^2}{(z+2)^2-16}\) |
| B. | \(\frac{z^2}{z^2-4}\) |
| C. | \(\frac{(z-2)^2}{(z-2)^2-16}\) |
| D. | \(\frac{z^2}{z^2-64}\) |
| Answer» C. \(\frac{(z-2)^2}{(z-2)^2-16}\) | |
| 4. |
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z| |
| A. | \(\frac{z^4}{z^2-16}\) |
| B. | \(\frac{(z+2)^2}{(z+2)^2-16}\) |
| C. | \(\frac{1}{z^2-16}\) |
| D. | \(\frac{(z-2)^2}{(z-2)^2-16}\) |
| Answer» D. \(\frac{(z-2)^2}{(z-2)^2-16}\) | |
| 5. |
The z-transform of x[n]= {1,0,-1,0,1,-1} (1st 1 as the reference variable) is __________ |
| A. | 1+2z-2 -4 z-4 + 5z-5 |
| B. | 1-z-2 + z-4 – z-5 |
| C. | 1-2z2 + 4z4 – 5z5 |
| D. | 1-z2 + z4 – z5 |
| E. | is __________a) 1+2z-2 -4 z-4 + 5z-5b) 1-z-2 + z-4 – z-5c) 1-2z2 + 4z4 – 5z5d) 1-z2 + z4 – z5 |
| Answer» C. 1-2z2 + 4z4 – 5z5 | |
| 6. |
The z-transform of x[n]= {2,4,5,7,0,1} (5 as the reference variable) is ___________ |
| A. | 2z2 + 4z + 5 +7z + z3, z≠∞ |
| B. | 2z-2 + 4z-1 + 5 + 7z + z3, z≠∞ |
| C. | 2z-2 + 4z-1 + 5 + 7z + z3, 0<|z|<∞ |
| D. | 2z2 + 4z + 5 + 7z-1 + z3, 0<|z|<∞ |
| E. | is ___________a) 2z2 + 4z + 5 +7z + z3, z≠∞b) 2z-2 + 4z-1 + 5 + 7z + z3, z≠∞c) 2z-2 + 4z-1 + 5 + 7z + z3, 0<|z|<∞d) 2z2 + 4z + 5 + 7z-1 + z3, 0<|z|<∞ |
| Answer» E. is ___________a) 2z2 + 4z + 5 +7z + z3, z≠∞b) 2z-2 + 4z-1 + 5 + 7z + z3, z≠∞c) 2z-2 + 4z-1 + 5 + 7z + z3, 0<|z|<∞d) 2z2 + 4z + 5 + 7z-1 + z3, 0<|z|<∞ | |
| 7. |
The z-transform of {3,0,0,0,0,6,1,-4} (1 as the reference variable) is ___________ |
| A. | 3z5 + 6 + z-1 – 4z-2, 0≤|z|<∞ |
| B. | 3z5 + 6 + z-1 – 4z-2, 0<|z|<∞ |
| C. | 3z5 + 6 + z – 4z-2 0<|z|<∞ |
| D. | 3z5 + 6 + z-1 – 4z-2, 0≤|z|<∞ |
| E. | is ___________a) 3z5 + 6 + z-1 – 4z-2, 0≤|z|<∞b) 3z5 + 6 + z-1 – 4z-2, 0<|z|<∞c) 3z5 + 6 + z – 4z-2 0<|z|<∞d) 3z5 + 6 + z-1 – 4z-2, 0≤|z|<∞ |
| Answer» C. 3z5 + 6 + z – 4z-2 0<|z|<∞ | |
| 8. |
The z-transform of \((\frac{2}{3})^{[n]}\) is ____________ |
| A. | \(\frac{-5z}{(2z-3)(3z-2)}\), –\(\frac{3}{2} \) < z < –\(\frac{2}{3}\) |
| B. | \(\frac{-5z}{(2z-3)(3z-2)}\), \(\frac{2}{3}\) < |z| < \(\frac{3}{2} \) |
| C. | \(\frac{5z}{(2z-3)(3z-2)}\), \(\frac{2}{3}\) < |z| |
| D. | \(\frac{5z}{(2z-3)(3z-2)}\), –\(\frac{3}{2} \) < z< –\(\frac{2}{3}\) |
| Answer» C. \(\frac{5z}{(2z-3)(3z-2)}\), \(\frac{2}{3}\) < |z| | |
| 9. |
The z-transform of \((\frac{1}{4})^4\) u[-n] is ___________ |
| A. | \(\frac{4z}{4z-1}\), |Z|>\(\frac{1}{4}\) |
| B. | \(\frac{4z}{4z-1}\), |Z|<\(\frac{1}{4}\) |
| C. | \(\frac{1}{1-4z}\), |Z|>\(\frac{1}{4}\) |
| D. | \(\frac{1}{1-4z}\), |Z|<\(\frac{1}{4}\) |
| Answer» E. | |
| 10. |
The z-transform of \((\frac{1}{4})^n\) (u[n] – u[n-5]) is __________ |
| A. | \(\frac{z^5 – 0.25^5}{z^4 (z-0.25)}\), z>0.25 |
| B. | \(\frac{z^5 – 0.25^5}{z^4 (z-0.25)}\), z>0 |
| C. | \(\frac{z^5 – 0.25^5}{z^3 (z-0.25)}\), z<0.25 |
| D. | \(\frac{z^5 – 0.25^5}{z^4 (z-0.25)}\), all z |
| Answer» E. | |
| 11. |
The z-transform of u[n] is _________ |
| A. | \(\frac{1}{1-z^{-1}}\), |Z|>1 |
| B. | \(\frac{1}{1-z^{-1}}\), |Z|<1 |
| C. | \(\frac{z}{1-z^{-1}}\), |Z|<1 |
| D. | \(\frac{z}{1-z^{-1}}\), |Z|>1 |
| Answer» B. \(\frac{1}{1-z^{-1}}\), |Z|<1 | |
| 12. |
The z-transform of δ[n+k]>0 is __________ |
| A. | Z-k, Z≠0 |
| B. | Zk, Z≠0 |
| C. | Z-k, all Z |
| D. | Zk, all Z |
| Answer» E. | |
| 13. |
The z-transform of δ[n-k]>0 is __________ |
| A. | Zk, Z>0 |
| B. | Z-k, Z>0 |
| C. | Zk, Z≠0 |
| D. | Z-k, Z≠0 |
| Answer» E. | |