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This section includes 21 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mechanics knowledge and support exam preparation. Choose a topic below to get started.
1. |
The calculation of the product of a moment of the body due to the loadings involve a quantity called ____________ |
A. | Moment |
B. | Inertia |
C. | Moment of Inertia |
D. | Rotation |
Answer» D. Rotation | |
2. |
Whenever the distributed loading acts perpendicular to an area its intensity varies __________ for the determination of the product of moment of inertia. |
A. | Linearly |
B. | Non-Linearly |
C. | Parabolically |
D. | Cubically |
Answer» B. Non-Linearly | |
3. |
The body is sometimes acted by two or three force members and we need to find the product of moment of inertia for the same. The difference between the two and the three force members is: |
A. | The former is collinear and the latter is parallel |
B. | The former is parallel and the latter is perpendicular |
C. | The former is perpendicular and the latter is collinear |
D. | The former is acting on two points in the body while the latter is on three points |
Answer» E. | |
4. |
If any external force also is applied on the structure and we are determining the product of moment of inertia then what should we consider? |
A. | The net force will act at the centroid of the structure only |
B. | The net load will not be formed as all the forces will be cancelled |
C. | The net force will act on the base of the loading horizontally |
D. | The net force will not to be considered, there would be a net force of the distribution, rest will be the external forces |
Answer» E. | |
5. |
Determine the del product of inertia for the triangle in the given figure used for the calculations. |
A. | dIxy=(h2/2b2)x3dx |
B. | dIxy=(h/2b2)x3dx |
C. | dIxy=(h2/2)x3dx |
D. | dIxy=(h2/b2)x3dxView Answer |
Answer» B. dIxy=(h/2b2)x3dx | |
6. |
The product of Inertia for an area is helpful so as to _____________ |
A. | Determine Minimum moments of inertia for an Area |
B. | Determine Maximum moments of inertia for a Line |
C. | Determine Minimum moments of inertia for a Volume |
D. | Determine Maximum moments of inertia for a Rectangle |
Answer» B. Determine Maximum moments of inertia for a Line | |
7. |
One of the use of the centre of mass or centroid is as in the determination of the product of moment of inertia is that the net force acts at the ___________ of the loading body. |
A. | Centroid |
B. | The centre axis |
C. | The corner |
D. | The base |
Answer» B. The centre axis | |
8. |
The distance in the parallel axis theorem for the use in the determination of the product of the moment of inertia is multiplied by: |
A. | Area |
B. | Volume |
C. | Linear distance |
D. | Area/Volume |
Answer» B. Volume | |
9. |
The product of moment of inertia is the sum of _____________ and _________________ |
A. | Area and volume |
B. | Volume and linear distance |
C. | Moment of inertia at centroid and the product of the area and del dx and del dy |
D. | Moment of inertia at base and the product of the area and del dx and del dy |
Answer» E. | |
10. |
There is a perpendicular axis theorem for the area, and it is can be used to determine the product of a moment of inertia. |
A. | True |
B. | False |
Answer» C. | |
11. |
Determine the product of inertia for the triangle in the given figure. |
A. | (bh)2/8 |
B. | (bh)2/16 |
C. | (bh)2/2 |
D. | (bh)2/4View Answer |
Answer» B. (bh)2/16 | |
12. |
THE_DISTANCE_IN_THE_PARALLEL_AXIS_THEOREM_FOR_THE_USE_IN_THE_DETERMINATION_OF_THE_PRODUCT_OF_THE_MOMENT_OF_INERTIA_IS_MULTIPLIED_BY:?$ |
A. | Area |
B. | Volume |
C. | Linear distance |
D. | Area/Volume |
Answer» B. Volume | |
13. |
The product of Inertia for an area is helpful so as to _____________$ |
A. | Determine Minimum moments of inertia for an Area |
B. | Determine Maximum moments of inertia for a Line |
C. | Determine Minimum moments of inertia for a Volume |
D. | Determine Maximum moments of inertia for a Rectangle |
Answer» E. | |
14. |
One_of_the_use_of_the_centre_of_mass_or_centroid_is_as_in_the_determination_of_the_product_of_moment_of_inertia_is_that_the_net_force_acts_at_the_____________of_the_loading_body.$ |
A. | Centroid |
B. | The centre axis |
C. | The corner |
D. | The base |
Answer» B. The centre axis | |
15. |
If the non-Uniform loading is of the type of parabola then for calculating the product of the moment of inertia for areas? |
A. | The net load will not be formed as all the forces will be cancelled |
B. | The net force will act the centre of the parabola |
C. | The net force will act on the base of the loading horizontally |
D. | The net force will act at the centroid of the parabola |
Answer» D. The net force will act at the centroid of the parabola | |
16. |
dIxy=(h2/2b2)x3dx |
A. | dIxy=(h/2b2)x<sup>3</sup>dx |
B. | dIxy=(h<sup>2</sup>/2)x<sup>3</sup>dx |
C. | dIxy=(h<sup>2</sup>/b2)x<sup>3</sup>dx |
Answer» B. dIxy=(h<sup>2</sup>/2)x<sup>3</sup>dx | |
17. |
The product of moment of inertia is the sum of _____________ and ________________? |
A. | Area and volume |
B. | Volume and linear distance |
C. | Moment of inertia at centroid and the product of the area and del dx and del dy |
D. | Moment of inertia at base and the product of the area and del dx and del dy |
Answer» B. Volume and linear distance | |
18. |
What is parallel axis theorem and to whom it is applied so that it can give the product of inertia of an area? |
A. | Theorem used to add the two mutually perpendicular moment of inertias for areas |
B. | Theorem used to add the two mutually perpendicular moment of inertias for volumes |
C. | Theorem used to add the two mutually perpendicular moment of inertias for linear distances |
D. | Theorem used to add the two mutually perpendicular moment of inertias for vectors |
Answer» B. Theorem used to add the two mutually perpendicular moment of inertias for volumes | |
19. |
Moment of Inertia is the integration of the square of the distance of the centroid and the del area along the whole area of the structure and after these calculations, we multiply the moment of areas. |
A. | True |
B. | False |
Answer» B. False | |
20. |
(bh)2/8 |
A. | (bh)<sup>2</sup>/16 |
B. | (bh)<sup>2</sup>/2 |
C. | (bh)<sup>2</sup>/4 |
Answer» C. (bh)<sup>2</sup>/4 | |
21. |
The product of Inertia for an area is required so as to _____________ |
A. | Determine Maximum moments of inertia for an Area |
B. | Determine Maximum moments of inertia for a Line |
C. | Determine Maximum moments of inertia for a Volume |
D. | Determine Maximum moments of inertia for a Rectangle |
Answer» B. Determine Maximum moments of inertia for a Line | |