MCQOPTIONS
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MCQOPTIONS
This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Statistical Quality Control knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Increase in process capability ratio Cp states that there is an increase in the percentage of the specification band used. |
| A. | True |
| B. | False |
| Answer» C. | |
| 2. |
What is the formula to calculate the one sided process capability which uses lower specification limit? |
| A. | (C_{pl}= frac{ +LSL}{ } ) |
| B. | (C_{pl}= frac{ -LSL}{6 } ) |
| C. | (C_{pl}= frac{ -LSL}{3 } ) |
| D. | (C_{pl}= frac{ -LSL}{6 } ) |
| Answer» D. (C_{pl}= frac{ -LSL}{6 } ) | |
| 3. |
For a process, the process standard deviation is 32. If the mean of the process is 364, and the upper specification limit is 400, what will be the one side process capability ratio which uses USL of the quality characteristic? |
| A. | 1.242 |
| B. | 1.135 |
| C. | 1.125 |
| D. | 0.991 |
| Answer» D. 0.991 | |
| 4. |
The one sided process capability ratio that uses the USL of the quality characteristic, is written as ____ |
| A. | (C_{pu}= frac{USL+ }{3 } ) |
| B. | (C_{pu}= frac{USL+ }{6 } ) |
| C. | (C_{pu}= frac{USL- }{6 } ) |
| D. | (C_{pu}= frac{USL- }{3 } ) |
| Answer» E. | |
| 5. |
If the process capability ratio Cp is 1.532, what percentages of the specification band will be used by the process? |
| A. | 65.27% |
| B. | 75.11% |
| C. | 44.21% |
| D. | 21.42% |
| Answer» B. 75.11% | |
| 6. |
The percentage of the specification band used by the process is calculated by formula _______________ |
| A. | P=C<sub>p</sub> |
| B. | P= ( frac{1}{C_p} )*100 |
| C. | P=C<sub>p</sub>*100 |
| D. | P= ( frac{1}{C_p} ) |
| Answer» C. P=C<sub>p</sub>*100 | |
| 7. |
If the estimate of the process standard deviation is 0.1368, and the USL for the quality characteristic is 2.00, and the LSL=2.00, what will be the value of the estimate of PCR Cp is _____________ |
| A. | 1.21 |
| B. | 1.19 |
| C. | 1.13 |
| D. | 1.31 |
| Answer» C. 1.13 | |
| 8. |
The estimate of the Cp is calculated by ______________ |
| A. | ( frac{USL-LSL}{6 hat{ sigma}} ) |
| B. | ( frac{USL-LSL}{3 hat{ sigma}} ) |
| C. | ( frac{USL-LSL}{ hat{ sigma}} ) |
| D. | ( frac{USL-LSL}{12 hat{ sigma}} ) |
| Answer» B. ( frac{USL-LSL}{3 hat{ sigma}} ) | |
| 9. |
We use _____________ to calculate the estimate of the process standard deviation. |
| A. | Sample standard deviation |
| B. | Sample average |
| C. | Sample variance |
| D. | Sample mean |
| Answer» B. Sample average | |
| 10. |
When the process standard deviation is unknown for a process, to calculate the PCR we use _____________ |
| A. | The mean |
| B. | The variance |
| C. | The sample average |
| D. | The estimate of |
| Answer» E. | |
| 11. |
USL in the formula of PCR is ____________ |
| A. | Upper safe limit |
| B. | Ultimate safe limit |
| C. | Upper specification limit |
| D. | Ultimate specification limit |
| Answer» D. Ultimate specification limit | |
| 12. |
Process capability ratio is expressed as ____________ |
| A. | (C_p= frac{USL-LSL}{6 } ) |
| B. | (C_p= frac{USL-2LSL}{6 } ) |
| C. | (C_p= frac{2USL-LSL}{6 } ) |
| D. | (C_p= frac{USL+LSL}{6 } ) |
| Answer» B. (C_p= frac{USL-2LSL}{6 } ) | |