y1 = 2sin(3x – 2t) & y2 = 3sin(3x – 2t + π/4). Find the expression for resultant displacement caused by superposition of the two waves.

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1.	y1 = 2sin(3x – 2t) & y2 = 3sin(3x – 2t + π/4). Find the expression for resultant displacement caused by superposition of the two waves.
A.	3.6sin(2x-3t+3π/7)
B.	4.63sin(3x-2t+3π/5)
C.	3.6cos(3x-2t+3π/7)
D.	4.63cos(3x-2t+3π/5)
Answer» C. 3.6cos(3x-2t+3π/7)

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