MCQOPTIONS
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MCQOPTIONS
This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Physics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The radiation pressure is given by __________ |
| A. | S |
| B. | S<sub>av</sub> |
| C. | S/c |
| D. | S<sub>av</sub>/c |
| Answer» E. | |
| 2. |
The magnitude of average value of S at a point is called as __________ |
| A. | Amplitude of radiation |
| B. | Frequency of radiation |
| C. | Intensity of radiation |
| D. | Momentum flow |
| Answer» D. Momentum flow | |
| 3. |
Poynting vector gives the energy flow per unit area per unit time through a cross-sectional area along the direction of propagation of the wave. |
| A. | True |
| B. | False |
| Answer» C. | |
| 4. |
The amplitude of the electric field in a parallel beam of light of intensity 3 W/m2 is __________ |
| A. | 23.4 N/C |
| B. | 34.5 N/C |
| C. | 47.53 N/C |
| D. | 51.45 N/C |
| Answer» D. 51.45 N/C | |
| 5. |
In an electromagnetic wave, the electric field of amplitude 4 V/m is oscillating. The Energy density of the wave is ___________ |
| A. | 1.41 X 10<sup>-10</sup> J/m<sup>3</sup> |
| B. | 2.41 X 10<sup>-10</sup> J/m<sup>3</sup> |
| C. | 3.41 X 10<sup>-10</sup> J/m<sup>3</sup> |
| D. | 4.41 X 10<sup>-10</sup> J/m<sup>3</sup> |
| Answer» B. 2.41 X 10<sup>-10</sup> J/m<sup>3</sup> | |
| 6. |
Earth receives 2 cal/min/cm2 of solar energy. What is the value of mid H mid? |
| A. | 1.98 A/m |
| B. | 2.45 A/m |
| C. | 3.75 A/m |
| D. | 4.13 A/m |
| Answer» B. 2.45 A/m | |
| 7. |
In free space, E(z,t) = 103sin( t z) ( hat{y} ). Obtain H(z,t). |
| A. | 1.23 sin ( t z) (- ( hat{y} )) |
| B. | 1.23 sin( t z) (- ( hat{x} )) |
| C. | 2.65 sin ( t z) (- ( hat{y} )) |
| D. | 2.65 sin( t z) (- ( hat{x} )) |
| Answer» E. | |
| 8. |
The correct expression for the Poynting vector is __________ |
| A. | <strong>S = E X B</strong> |
| B. | <strong>S = E X B</strong>/2 |
| C. | <strong>S = E X B</strong>/ <sub>o</sub> |
| D. | <strong>S = E X B</strong>/2 <sub>o</sub> |
| Answer» D. <strong>S = E X B</strong>/2 <sub>o</sub> | |
| 9. |
According to the Poynting theorem, the energy flow per unit time out of any closed surface is ___________ |
| A. | Integral of S over the length of the surface |
| B. | Integral of S over the are of the surface |
| C. | Differential of S over the length of the surface |
| D. | Differential of S over the are of the surface |
| Answer» C. Differential of S over the length of the surface | |
| 10. |
The direction of Poynting vector is perpendicular to the direction of propagation of wave. |
| A. | True |
| B. | False |
| Answer» C. | |
| 11. |
The energy transported by the fields per unit time per unit are is called __________ |
| A. | Poynting Energy |
| B. | Electro-magnetic energy |
| C. | Poynting vector |
| D. | Flux density |
| Answer» D. Flux density | |
| 12. |
Unit of Poynting Vector is _____________ |
| A. | Watt |
| B. | Watt/s |
| C. | Watt/m |
| D. | Watt/m<sup>2</sup> |
| Answer» E. | |