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This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Mechanical Operations knowledge and support exam preparation. Choose a topic below to get started.
1. |
Power is the time derivative of which quantity? |
A. | Energy |
B. | Acceleration |
C. | Velocity |
D. | Position |
Answer» B. Acceleration | |
2. |
The force applied on a body can be given as F = 4i + 2j + 6k. The displacement of the body is given by s = 3i + 9k. Calculate the power at t = 2 seconds. |
A. | 66 W |
B. | 33 W |
C. | 30 W |
D. | 15 W |
Answer» C. 30 W | |
3. |
What is the unit of Bond s constant? |
A. | kW mm<sup>1/2</sup> s/kg |
B. | kW mm s/kg |
C. | kW mm<sup>1/2</sup> kg/s |
D. | kW mm kg/s |
Answer» B. kW mm s/kg | |
4. |
Which of the following is the correct formula of Bond s law? |
A. | ( frac {P}{m} ) = k<sub>b</sub> (( frac {1}{ sqrt {D_{sb}}} + frac {1}{ sqrt {D_{sa}}}) ) |
B. | P = k<sub>b</sub> (( frac {1}{ sqrt {D_{sb}}} frac {1}{ sqrt {D_{sa}}}) ) |
C. | ( frac {P}{m} ) = k<sub>b</sub> (( frac {1}{ sqrt {D_{sb}}} frac {1}{ sqrt {D_{sa}}}) ) |
D. | P = k<sub>b</sub> (( frac {1}{ sqrt {D_{sb}}} + frac {1}{ sqrt {D_{sa}}}) ) |
Answer» D. P = k<sub>b</sub> (( frac {1}{ sqrt {D_{sb}}} + frac {1}{ sqrt {D_{sa}}}) ) | |
5. |
What are the dimensions of power? |
A. | [ML<sup>2</sup>T<sup>-3</sup>] |
B. | [ML<sup>2</sup>T<sup>-1</sup>] |
C. | [ML<sup>1</sup>T<sup>-3</sup>] |
D. | [ML<sup>3</sup>T<sup>-3</sup>] |
Answer» C. [ML<sup>1</sup>T<sup>-3</sup>] | |
6. |
What is the unit of Kick s constant? |
A. | kg / kW |
B. | kW * s/kg |
C. | kW * kg/s |
D. | kg * s/kW |
Answer» C. kW * kg/s | |
7. |
Calculate the power required in Watts, if the work done can be given as w = 3t4 16t at t = 5 seconds. |
A. | 1795 W |
B. | 1420 W |
C. | 1484 W |
D. | 1675 W |
Answer» D. 1675 W | |
8. |
Work index is the gross energy required to reduce very large feed to a size such that, 65 percent of the product passes through a 100 m mesh screen. |
A. | True |
B. | False |
Answer» C. | |
9. |
Using Rittinger s law, calculate the power required to crush 12 ton/hr of rocks, if 10 ton/hr rocks were crushed at a power of 9 hp. The diameter of the rocks was reduced from 3 cm to 0.5 cm in each case. |
A. | 10.7 hp |
B. | 11 hp |
C. | 10.8 hp |
D. | 12 hp |
Answer» E. | |