MCQOPTIONS
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MCQOPTIONS
This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Finite Element Method knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In the Finite Element Method, which element is known for the slowest convergence? |
| A. | Linear triangular element |
| B. | Quadratic triangular element |
| C. | Linear rectangular elements |
| D. | Quadratic rectangular elements |
| Answer» B. Quadratic triangular element | |
| 2. |
In Finite Element Analysis, which option is correct for computation of load due to specified boundary stress? |
| A. | Can be computed using a local coordinate system and one-dimensional interpolation functions |
| B. | Can be computed using a local coordinate system but not one-dimensional interpolation functions |
| C. | Cannot be computed using a local coordinate system but one-dimensional interpolation functions can be used |
| D. | Neither a local coordinate system nor one-dimensional interpolation functions can be used |
| Answer» B. Can be computed using a local coordinate system but not one-dimensional interpolation functions | |
| 3. |
In vibration and transient analysis of beams, if the linear acceleration scheme predicts the solution,then it is unstable for the first several time steps, but it eventually becomes stable. |
| A. | True |
| B. | False |
| Answer» C. | |
| 4. |
In Finite Element Analysis, what are the values of nodal forces in the following element if the line 2-4 is 160 in long? |
| A. | 1600 along both the DOF 3 and 7 |
| B. | 800 and 0 along the DOF 3 and 4 respectively |
| C. | 0 and 800 along the DOF 7 and 8 respectively |
| D. | 0 and 800 along the DOF 3 and 4 respectively |
| Answer» C. 0 and 800 along the DOF 7 and 8 respectively | |
| 5. |
What is the expression for the traction term tn in the element load vector Qe=∮┌cheψTtds of the following figure where L23 is the length of the line 2-3? |
| A. | tn=-T(-1+\(\frac{s}{L_{23}})\) |
| B. | tn=T(-1+\(\frac{s}{L_{23}})\) |
| C. | tn=-T(1+\(\frac{s}{L_{23}})\) |
| D. | tn=T(1+\(\frac{s}{L_{23}})\) |
| Answer» C. tn=-T(1+\(\frac{s}{L_{23}})\) | |
| 6. |
What is the global load vector in Finite Element Analysis of the following structure if the local load vector is \(\begin{bmatrix}0\\0\\2\\0\\1\\0\end{bmatrix}\) and θ=0? |
| A. | \(\begin{bmatrix}0\\0\\0\\2\\0\\1\end{bmatrix}\) |
| B. | \(\begin{bmatrix}0\\0\\2\\0\\0\\1\end{bmatrix}\) |
| C. | \(\begin{bmatrix}0\\0\\2\\0\\1\\0\end{bmatrix}\) |
| D. | \(\begin{bmatrix}0\\0\\0\\2\\1\\0\end{bmatrix}\) |
| Answer» B. \(\begin{bmatrix}0\\0\\2\\0\\0\\1\end{bmatrix}\) | |
| 7. |
In transformations, what is the transformation matrix R in the relation F=RQ if the load vector in global coordinates is F and the load vector in element coordinates is Q? |
| A. | \(\begin{bmatrix}cos \alpha & sin \alpha & 0 & 0 & \\-sin \alpha & cos \alpha & 0 & 0 & \\0 & 0 & cos \alpha & sin \alpha & \\0 & 0 & -sin \alpha & cos \alpha & \\& & & & \ddots\end{bmatrix}\) |
| B. | \(\begin{bmatrix}cos \alpha & -sin \alpha & 0 & 0 & \\sin \alpha & cos \alpha & 0 & 0 & \\0 & 0 & cos \alpha & -sin \alpha & \\0 & 0 & sin \alpha & cos \alpha & \\& & & & \ddots\end{bmatrix}\) |
| C. | \(\begin{bmatrix}cos \alpha & sin \alpha & 0 & 0 & \\-sin \alpha & cos \alpha & 0 & 0 & \\0 & 0 & cos \alpha & -sin \alpha & \\0 & 0 & sin \alpha & cos \alpha & \\& & & & \ddots\end{bmatrix}\) |
| D. | \(\begin{bmatrix}cos \alpha & -sin \alpha & 0 & 0 & \\sin \alpha & cos \alpha & 0 & 0 & \\0 & 0 & cos \alpha & sin \alpha & \\0 & 0 & -sin \alpha & cos \alpha & \\& & & & \ddots\end{bmatrix}\) |
| Answer» B. \(\begin{bmatrix}cos \alpha & -sin \alpha & 0 & 0 & \\sin \alpha & cos \alpha & 0 & 0 & \\0 & 0 & cos \alpha & -sin \alpha & \\0 & 0 & sin \alpha & cos \alpha & \\& & & & \ddots\end{bmatrix}\) | |
| 8. |
Which option is not correct concerning the internal load vector in the finite element model of plane elasticity problems? |
| A. | It is computed at all the nodes interior of the element |
| B. | It is computed only when the element falls on the boundary of the domain on which tractions are known |
| C. | Its computation doesn’t involve evaluation of line integrals for any type of element |
| D. | It is evaluated in global coordinates but not in element coordinates |
| Answer» C. Its computation doesn’t involve evaluation of line integrals for any type of element | |
| 9. |
In the Finite Element Method, the vector of internal forces is computed only when the element falls on the boundary of the domain on which tractions are absent. |
| A. | True |
| B. | False |
| Answer» C. | |
| 10. |
In Finite Element Analysis, what is the correct load vector for the linear quadrilateral element with area Ae, thickness he and uniform body force vector f? |
| A. | \(\frac{A_e h_e}{4} \)f |
| B. | \(\frac{A_e h_e}{3}\)f |
| C. | \(\frac{h_e}{3A_e}\)f |
| D. | \(\frac{h_e}{4A_e}\)f |
| Answer» B. \(\frac{A_e h_e}{3}\)f | |
| 11. |
In Finite Element Analysis, what is the correct load vector for a linear triangular element with area Ae, thickness he and uniform body force vector f? |
| A. | \(\frac{A_e h_e}{4}\)f |
| B. | \(\frac{A_e h_e}{3}\)f |
| C. | \(\frac{h_e}{3A_e}\)f |
| D. | \(\frac{h_e}{4A_e}\)f |
| Answer» C. \(\frac{h_e}{3A_e}\)f | |
| 12. |
In the Finite Element Method, which expression is correct for a linear triangular element if S is the shape function, Ae is its area, and K is a constant? |
| A. | \(\frac{\partial S}{\partial x}=\frac{K}{A_e}\) |
| B. | \(\frac{\partial S}{\partial y}=\frac{K}{A_e^2}\) |
| C. | \(\frac{\partial S}{\partial x}\)=KAe |
| D. | \(\frac{\partial S}{\partial y}\)=KAe2 |
| Answer» B. \(\frac{\partial S}{\partial y}=\frac{K}{A_e^2}\) | |