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				This section includes 19 Mcqs, each offering curated multiple-choice questions to sharpen your Organic Chemistry knowledge and support exam preparation. Choose a topic below to get started.
| 1. | A substance absorbs 2.0 x 1016 quanta or radiations per second and 0.002 mole of it reacts in 1200 seconds. What is the quantum yield or the reaction (N = 6.02 x 1023)? | 
| A. | 50 | 
| B. | 40 | 
| C. | 80 | 
| D. | 100 | 
| Answer» B. 40 | |
| 2. | Which of the following are the reactions in which molecules absorbing light do not themselves react but induce other molecules to react? | 
| A. | Free radical reactions | 
| B. | Chain reactions | 
| C. | Reversible reactions | 
| D. | Photosensitized reactions | 
| Answer» E. | |
| 3. | The quantum efficiency of a photochemical reaction is defined as _______ | 
| A. | ratio of molecules decomposed in a given time to the number of quanta absorbed in the same time | 
| B. | number of 11101ecules decomposed in a given time | 
| C. | number or quanta absorbed percent time | 
| D. | ratio of’ molecules decomposed in a given time to the number of quanta emitted in the same time | 
| Answer» B. number of 11101ecules decomposed in a given time | |
| 4. | Which of the following will result in deviation from Beer’s law? | 
| A. | A, B and C | 
| B. | B, C and D | 
| C. | A, C and D | 
| D. | A, B and DView Answer | 
| Answer» B. B, C and D | |
| 5. | A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1 nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1 nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699]. | 
| A. | 33.3% | 
| B. | 50% | 
| C. | 66.7% | 
| D. | 70% | 
| Answer» B. 50% | |
| 6. | What are the appropriate reasons for the deviation from the Beer’s law among the following? | 
| A. | A, B and D | 
| B. | B, C and D | 
| C. | A, C and D | 
| D. | A, B and CView Answer | 
| Answer» C. A, C and D | |
| 7. | The molar extinction coefficient of B (MW = 180) is 4 x 103 L mol-1 cm-1. One-liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. What is the percentage (w/w) of B in the pharmaceutical preparation? | 
| A. | 10.2 | 
| B. | 13.60 | 
| C. | 20.40 | 
| D. | 29.12 | 
| Answer» C. 20.40 | |
| 8. | Which regions of the light radiations of the visible ultraviolet lying between – wavelength are chiefly concerned in bringing about photochemical reactions? | 
| A. | 1000 Å and 2000 Å | 
| B. | 1500 Å and 1000 Å | 
| C. | 8000 Å and 2000 Å | 
| D. | 19000 Å and 12,000 Å | 
| Answer» D. 19000 Å and 12,000 Å | |
| 9. | WHICH_OF_THE_FOLLOWING_ARE_THE_REACTIONS_IN_WHICH_MOLECULES_ABSORBING_LIGHT_DO_NOT_THEMSELVES_REACT_BUT_INDUCE_OTHER_MOLECULES_TO_REACT??$ | 
| A. | Free radical reactions | 
| B. | Chain reactions | 
| C. | Reversible reactions | 
| D. | Photosensitized reactions | 
| Answer» E. | |
| 10. | THE_QUANTUM_EFFICIENCY_OF_A_PHOTOCHEMICAL_REACTION_IS_DEFINED_AS________?$ | 
| A. | ratio of molecules decomposed in a given time to the number of quanta absorbed in the same time | 
| B. | number of 11101ecules decomposed in a given time | 
| C. | number or quanta absorbed percent time | 
| D. | ratio of’ molecules decomposed in a given time to the number of quanta emitted in the same time | 
| Answer» B. number of 11101ecules decomposed in a given time | |
| 11. | A substance absorbs 2.0 x 1016 quanta or radiations per second and 0.002 mole of it reacts in 1200 seconds. What is the quantum yield or the reaction (N = 6.02 x 1023)?$ | 
| A. | 50 | 
| B. | 40 | 
| C. | 80 | 
| D. | 100 | 
| Answer» B. 40 | |
| 12. | Which of the following will result in deviation from Beer’s law?# | 
| A. | Change in a refractive index of medium | 
| B. | Dissociation of analyte on dilution | 
| C. | Polychromatic light | 
| D. | Path length of cuvette | 
| Answer» B. Dissociation of analyte on dilution | |
| 13. | A 0.1 M solution of compound A shows 50% transmittance when a cell of 1 cm width is used at λ1 nm. Another 0.1 M solution of compound B gives the optical density value of 0.1761 using 1cm cell at λ1 nm. What will be the transmittance of a solution that is simultaneously 0.1 M in A and 0.1 M in B using the same cell and at the same wave length? [log 1.301; log 1.4771; log 50 = 1.699].$ | 
| A. | 33.3% | 
| B. | 50% | 
| C. | 66.7% | 
| D. | 70% | 
| Answer» B. 50% | |
| 14. | What are the appropriate reasons for the deviation from the Beer’s law among the following?$ | 
| A. | Monochromaticity of light | 
| B. | Very high concentration of analyte | 
| C. | Association of analyte | 
| D. | Dissociation of analyte | 
| Answer» C. Association of analyte | |
| 15. | The molar extinction coefficient of B (MW = 180) is 4 x 103 L mol-1 cm-1. One-liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. What is the percentage (w/w) of B in the pharmaceutical preparation? | 
| A. | 10.20 | 
| B. | 13.60 | 
| C. | 20.40 | 
| D. | 29.12 | 
| Answer» C. 20.40 | |
| 16. | Which of the following instruments is used to measure the energy of the monochromatic radiation most accurately? | 
| A. | Photoelectric cell | 
| B. | Thermopile | 
| C. | The potential detector | 
| D. | The chemical actinometer | 
| Answer» C. The potential detector | |
| 17. | Which regions of the light radiations of the visible ultraviolet lying between – wavelength are chiefly concerned in bringing about photochemical reactions?$ | 
| A. | 1000 √Ö and 2000 √Ö | 
| B. | 1500 √Ö and 1000 √Ö | 
| C. | 8000 √Ö and 2000 √Ö | 
| D. | 19000 √Ö and 12,000 √Ö | 
| Answer» D. 19000 ‚Äö√†√∂‚àö√± and 12,000 ‚Äö√†√∂‚àö√± | |
| 18. | Which of the following is an incorrect statement? | 
| A. | First step in photochemistry is excited state (photoexcitation) | 
| B. | Photochemical reactions are caused by absorption of ultraviolet only | 
| C. | When a molecule or atom in the ground state (S<sub>0</sub>) absorbs light, one electron is excited to a higher orbital level | 
| D. | it is possible for the excited state S<sub>1</sub> to undergo spin inversion | 
| Answer» C. When a molecule or atom in the ground state (S<sub>0</sub>) absorbs light, one electron is excited to a higher orbital level | |
| 19. | The fact that the fluorescence wavelength is often much longer than the irradiation wavelength (Stokes shift) is a consequence of which phenomenon? | 
| A. | low extinction coefficients (Lambert-Beer law) | 
| B. | vertical transitions (Kasha’s rule) | 
| C. | high ISC rates (El Sayed rule) | 
| D. | the Franck–Condon principle | 
| Answer» E. | |