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This section includes 4 Mcqs, each offering curated multiple-choice questions to sharpen your Optical Communications Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
1. |
For suitable power confinement of fundamental mode, the normalized frequency v should be maintained in the range 1.5 to 2.4μm and the fractional index difference must be linearly increased as a square function while the core diameter is linearly reduced to keep v constant. This confinement is achieved by? |
A. | Increasing level of silica doping in fiber core |
B. | Increasing level of germanium doping in fiber core |
C. | Decreasing level of silica germanium in fiber core |
D. | Decreasing level of silica doping in fiber core |
Answer» C. Decreasing level of silica germanium in fiber core | |
2. |
The dispersion due to material, waveguide and profile are -2.8nm-1km-1, 20.1nm-1km-1 and 23.2nm-1km-1respectively. Find the total first order dispersion? |
A. | 36.2psnm-1 km-1 |
B. | 38.12psnm-1 km-1 |
C. | 40.5psnm-1 km-1 |
D. | 20.9psnm-1 km-1 |
Answer» D. 20.9psnm-1 km-1 | |
3. |
Γg = dβ / C*dk. What is β in the given equation? |
A. | Attenuation constant |
B. | Propagation constant |
C. | Boltzmann’s constant |
D. | Free-space |
Answer» C. Boltzmann’s constant | |
4. |
A multimode step index fiber has source of RMS spectral width of 60nm and dispersion parameter for fiber is 150psnm-1km-1. Estimate rms pulse broadening due to material dispersion. |
A. | 12.5ns km-1 |
B. | 9.6ns km-1 |
C. | 9.0ns km-1 |
D. | 10.2ns km-1 |
Answer» D. 10.2ns km-1 | |