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This section includes 11 Mcqs, each offering curated multiple-choice questions to sharpen your Optical Communications knowledge and support exam preparation. Choose a topic below to get started.
1. |
Non-zero-dispersion-shifted fiber was introduced in the year 2000. |
A. | True |
B. | False |
Answer» C. | |
2. |
The variant of non-zero-dispersion-shifted fiber is called as __________ |
A. | Dispersion flattened fiber |
B. | Zero-dispersion fiber |
C. | Positive-dispersion fiber |
D. | Negative-dispersion fiber |
Answer» E. | |
3. |
Any amount of stress occurring at the core-cladding interface would be reduced by grading the material composition. |
A. | True |
B. | False |
Answer» B. False | |
4. |
For suitable power confinement of fundamental mode, the normalized frequency v should be maintained in the range 1.5 to 2.4 m and the fractional index difference must be linearly increased as a square function while the core diameter is linearly reduced to keep v constant. This confinement is achieved by? |
A. | Increasing level of silica doping in fiber core |
B. | Increasing level of germanium doping in fiber core |
C. | Decreasing level of silica germanium in fiber core |
D. | Decreasing level of silica doping in fiber core |
Answer» C. Decreasing level of silica germanium in fiber core | |
5. |
The fibers which relax the spectral requirements for optical sources and allow flexible wavelength division multiplying are known as __________ |
A. | Dispersion-flattened single mode fiber |
B. | Dispersion-enhanced single mode fiber |
C. | Dispersion-compressed single mode fiber |
D. | Dispersion-standardized single mode fiber |
Answer» B. Dispersion-enhanced single mode fiber | |
6. |
An alternative modification of the dispersion characteristics of single mode fibers involves achievement of low dispersion gap over the low-loss wavelength region between __________ |
A. | 0.2 and 0.9 m |
B. | 0.1 and 0.2 m |
C. | 1.3 and 1.6 m |
D. | 2 and 3 m |
Answer» D. 2 and 3 m | |
7. |
Dispersion-shifted single mode fibers are created by __________ |
A. | Increasing fiber core diameter and decreasing fractional index difference |
B. | Decreasing fiber core diameter and decreasing fractional index difference |
C. | Decreasing fiber core diameter and increasing fractional index difference |
D. | Increasing fiber core diameter and increasing fractional index difference |
Answer» D. Increasing fiber core diameter and increasing fractional index difference | |
8. |
A single mode fiber has a zero dispersion wavelength of 1.21 m and a dispersion slope of 0.08 psnm-2km-1. What is the total first order dispersion at wavelength 1.26 m. |
A. | -2.8psnm<sup>-1</sup> km<sup>-1</sup> |
B. | -3.76psnm<sup>-1</sup> km<sup>-1</sup> |
C. | -1.2psnm<sup>-1</sup> km<sup>-1</sup> |
D. | 2.4psnm<sup>-1</sup> km<sup>-1</sup> |
Answer» C. -1.2psnm<sup>-1</sup> km<sup>-1</sup> | |
9. |
Most of the power in an optical fiber is transmitted in fiber cladding. |
A. | True |
B. | False |
Answer» C. | |
10. |
g = d / C*dk. What is in the given equation? |
A. | Attenuation constant |
B. | Propagation constant |
C. | Boltzmann s constant |
D. | Free-space |
Answer» C. Boltzmann s constant | |
11. |
A multimode step index fiber has source of RMS spectral width of 60nm and dispersion parameter for fiber is 150psnm-1km-1. Estimate rms pulse broadening due to material dispersion. |
A. | 12.5ns km<sup>-1</sup> |
B. | 9.6ns km<sup>-1</sup> |
C. | 9.0ns km<sup>-1</sup> |
D. | 10.2ns km<sup>-1</sup> |
Answer» D. 10.2ns km<sup>-1</sup> | |