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This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Physics Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
1. |
Two simple pendulums of the same length are released from 10° & 20° respectively. Select the correct statement. |
A. | The second pendulum have will have a double time period than that of the first |
B. | They both will reach the mean position at the same time |
C. | The first pendulum will have a double time period than that of the second |
D. | Their maximum speed will be the same |
Answer» C. The first pendulum will have a double time period than that of the second | |
2. |
A spring block system is on a horizontal surface. The block is compressed by 10cm. What should be the coefficient of friction between the block and ground such that the block comes to a stop at the mean position? Mass of block = 0.5kg & spring constant = 3N/m. |
A. | 0.03 |
B. | 0.06 |
C. | 0.12 |
D. | 0.05 |
Answer» C. 0.12 | |
3. |
A spring mass system is on a horizontal plane. Spring constant is 2N/m & mass of block is 2kg. The spring is compressed by 10cm and released. A small ball is released from a height of 2m above the block on the horizontal plane. At what time should the ball be left if the block is released from the extreme position at t=0, given that the ball has to fall on the block when the speed of block is maximum? |
A. | 1.57s |
B. | 0.94s |
C. | 0s |
D. | 0.63s |
Answer» C. 0s | |
4. |
A spring block system is on a horizontal plane. If spring constant is 2N/m & mass of block is 1kg. By what amount should the block be extended from equilibrium position such that maximum velocity at mean position is 2m/s? |
A. | 2√2 m |
B. | 3√2 m |
C. | 4√2 m |
D. | 2 m |
Answer» B. 3√2 m | |
5. |
Let T1 be the time period of a single spring mass system on a horizontal surface. Let T2 be the time period of the same system when hung from the ceiling. What is the expression for T1 & T2? |
A. | T1 = T2 = 2π √(k/m) |
B. | T1 = 2π √(m/k), T2 = 2π √(mg/k) |
C. | T1 = T2 = 2π √(m/k) |
D. | T1 = 2π √(m/k), T2 = 2π √(k/mg) |
Answer» D. T1 = 2π √(m/k), T2 = 2π √(k/mg) | |