Explore topic-wise MCQs in Linear Integrated Circuit.

This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Integrated Circuit knowledge and support exam preparation. Choose a topic below to get started.

1.

DEFINE_TOTAL_CURRENT_(IQ)_EQUATION_IN_DIFFERENTIAL_AMPLIFIER_WITH_CONSTANT_CURRENT_BIAS_CURRENT?$

A. I<sub>Q</sub>=1/R<sub>3</sub>√ó(VEE/R<sub>1</sub>+R<sub>2</sub>)
B. I<sub>Q</sub> =(VEE√óR<sub>2</sub>)/(R<sub>1</sub>+R<sub>2</sub>)
C. I<sub>Q</sub>=1/R<sub>3</sub>√ó(VEE√óR<sub>2</sub>/R<sub>1</sub>+R<sub>2</sub>)
D. I<sub>Q</sub>)=R<sub>3</sub>√ó(VEE/R<sub>1</sub>+R<sub>2</sub>)
Answer» D. I<sub>Q</sub>)=R<sub>3</sub>‚Äö√†√∂‚àö‚â•(VEE/R<sub>1</sub>+R<sub>2</sub>)
Discussion
2.

When will be the mirror effect valid$

A. β≫1
B. β=1
C. β<1
D. β≠1
Answer» B. ‚âà√≠‚Äö√¢¬ß=1
Discussion
3.

Constant_current_source_in_differential_amplifier_is_also_called_as$

A. Current Mirror
B. Current Source
C. Current Repeaters
D. All of the mentioned
Answer» B. Current Source
Discussion
4.

Calculate_the_value_of_reference_current_and_input_resistor_for_current_mirror_with_IC=1.2μA_&_VCC=12v._Assume_β=50.$

A. 1.248mA, 9kΩ
B. 1.248mA, 9.6kΩ
C. 1.248mA, 9.2kΩ
D. 1.2mA, 9.6kΩ
Answer» B. 1.248mA, 9.6k‚âà√≠¬¨¬©
Discussion
5.

How to improve CMRR valu?

A. Increase common mode gain
B. Decrease common mode gain
C. Increase Differential mode gain
D. Decrease differential mode gain
Answer» C. Increase Differential mode gain
Discussion
6.

What is the purpose of diode in differential amplifier with constant current circuit?

A. Total current independent on temperature
B. Diode is dependent of temperature
C. Transistor is depend on temperature
D. None of the mentioned
Answer» B. Diode is dependent of temperature
Discussion
7.

To increase the value of CMRR, which circuit is used to replace the emitter resistance Re in differential amplifier?

A. Constant current bias
B. Resistor in parallel with Re
C. Resistor in series with Re
D. Diode in parallel with Re
Answer» B. Resistor in parallel with Re
Discussion
8.

If the value of Common Mode Rejection Ratio and Common Mode Gain are 40db and -0.12 respectively, then determine the value of differential mode gain

A. 0.036
B. -1.2
C. 4.8
D. 12
Answer» E.
Discussion
9.

In differential amplifier the input are given as V1=30sin⁡Π(50t)+10sin⁡Π(25t) , V2=30sin⁡Π(50t)-10 sin⁡Π(25t), β0 =200,RE =1kΩ and RC = 15kΩ. Find the output voltages V01, V02 & gm=4MΩ-1$

A. V<sub>01</sub>=-60[10 sin⁡Π(25t) ]-6.637[30sin⁡Π(50t) ], V<sub>02</sub>=60[10 sin⁡Π(25t) ]-6.637[30sin⁡Π(50t) ].
B. V<sub>01</sub>=-6.637[10 sin⁡Π(25t) ]-60[30sin⁡Π(50t) ], V<sub>02</sub>=6.637[10 sin⁡Π(25t) ]-60[30sin⁡Π(50t) ].
C. V<sub>01</sub>=-60[30 sin⁡Π(50t) ]-6.637[10sin⁡Π(25t) ], V<sub>02</sub>=60[30 sin⁡Π(50t) ]-6.637[10sin⁡Π(25t) ].
D. V<sub>01</sub>=-6.637[30 sin⁡Π(50t) ]-60[10sin⁡Π(25t) ], V<sub>02</sub>=6.637[30 sin⁡Π(50t) ]-60[10sin⁡Π(25t) ].
Answer» B. V<sub>01</sub>=-6.637[10 sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(25t) ]-60[30sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(50t) ], V<sub>02</sub>=6.637[10 sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(25t) ]-60[30sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(50t) ].
Discussion
10.

Find Common Mode Rejection Ration, given gm =16MΩ-1, RE=25kΩ$

A. 58 db
B. 40 db
C. 63 db
D. 89 db
Answer» B. 40 db
Discussion
11.

How the differential mode gain is expressed using ‘h’ parameter for a single ended output?$

A. – h<sub>fe</sub>RC/h<sub>ie</sub>
B. 1/2√ó(h<sub>fe</sub>RC)/h<sub>ie</sub>
C. – 1/2×h<sub>fe</sub>RC
D. None of the mentioned
Answer» C. ‚Äö√Ñ√∂‚àö√ë‚àö¬® 1/2‚Äö√†√∂‚àö‚â•h<sub>fe</sub>RC
Discussion
12.

How are the arbitrary signal represented, that are applied to the input of transistor? (Assume common mode signal and differential mode signal to be VCM & VDM respectively).

A. Sum of V<sub>CM</sub> & V<sub>DM</sub>
B. Difference of V<sub>CM</sub> & V<sub>DM</sub>
C. Sum and Difference of V<sub>CM</sub> & V<sub>DM</sub>
D. None of the mentioned
Answer» D. None of the mentioned
Discussion