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This section includes 2095 Mcqs, each offering curated multiple-choice questions to sharpen your Php knowledge and support exam preparation. Choose a topic below to get started.
851. |
Boiled linseed oil is used as a solvent for ___________ resin. |
A. | Amber |
B. | Mastic |
C. | Gum |
D. | Rosin |
Answer» B. Mastic | |
852. |
The __________________ is a hard substance and is available from the Earth at the place where pine trees exist in past. |
A. | Lac |
B. | Copal |
C. | Shellac |
D. | Rosin |
Answer» C. Shellac | |
853. |
___________________ defect occurs when surface to be painted is too smooth. |
A. | Sagging |
B. | Running |
C. | Grinning |
D. | Wrinkling |
Answer» C. Grinning | |
854. |
___________________ defects is caused by the water vapour which is trapped behind the painted surface. |
A. | Flaking |
B. | Fading |
C. | Blistering |
D. | Flashing |
Answer» D. Flashing | |
855. |
The cell fusion happens between spleen cells and _____________ |
A. | Red blood cells |
B. | Cancer cell |
C. | Myeloma cells |
D. | Leukocytes |
Answer» D. Leukocytes | |
856. |
What is the method to harvest monoclonal antibodies from the positive clones? |
A. | Subculture in the new medium |
B. | Bioreactors |
C. | One a single media plate |
D. | Tissue culture method |
Answer» E. | |
857. |
What do we get when we fuse Spleen cells and Myeloma cells? |
A. | Hybridoma cells |
B. | Red blood cells |
C. | Killer cells |
D. | Cancer myeloma B-cell |
Answer» B. Red blood cells | |
858. |
What do you add to Myeloma cells to receive HGPRT- myeloma cells? |
A. | 8 – Azaguanine |
B. | Azaguanine |
C. | Nitrogen flush |
D. | Carbon dioxide flush |
Answer» B. Azaguanine | |
859. |
For how many weeks should you titer the Flow cytometry solution to get pure antigen? |
A. | 1 month |
B. | 3 weeks |
C. | 7 weeks |
D. | 2 weeks |
Answer» E. | |
860. |
What has become an important tool in biochemistry, molecular biology, and medicine? |
A. | DNA structure |
B. | Genome sequencing |
C. | MCA |
D. | PCR |
Answer» D. PCR | |
861. |
MCA are antibodies that are non-identical. |
A. | True |
B. | False |
Answer» C. | |
862. |
Who invented the process of producing monoclonal antibodies in 1975? |
A. | Albert Einstein |
B. | Watson and Creek |
C. | Georges Köhler and César Milstein |
D. | Robert Hook |
Answer» D. Robert Hook | |
863. |
What had helped the study of the structure of antibodies in 1970? |
A. | APC |
B. | Red blood cells |
C. | Killer cells |
D. | Cancer myeloma B-cell |
Answer» E. | |
864. |
Flexural torsional buckling cannot occur in ________ |
A. | unsymmetrical members |
B. | cross section with one axis of symmetry |
C. | cross section with no axis of symmetry |
D. | doubly symmetric members |
Answer» E. | |
865. |
Which of the following is not a solution for torsional buckling? |
A. | increasing length of members subjected to torsion |
B. | by careful arrangement of members |
C. | by providing bracing to prevent lateral movement and twisting |
D. | box section fabricated by adding welding side plates to ISHB sections |
Answer» B. by careful arrangement of members | |
866. |
Which of the following is true about torsional buckling? |
A. | failure occurs by bending about shear centre in longitudinal axis |
B. | failure occurs when torsional rigidity of member is greater than bending rigidity |
C. | standard hot rolled shapes are not susceptible to torsional buckling |
D. | it cannot occur with doubly symmetric cross section |
Answer» D. it cannot occur with doubly symmetric cross section | |
867. |
What is the fundamental path in graph? |
A. | line along load axis up to P > Pcr |
B. | line along load axis up to P < Pcr |
C. | line along load axis up to P = Pcr |
D. | line along load axis up to P ≥ Pcr |
Answer» D. line along load axis up to P ≥ Pcr | |
868. |
Which of the following is the correct expression of the height of chimney emitting sulfur dioxide? |
A. | HC = 74 Kp0.27 |
B. | HC = 14 Kp0.33 |
C. | HC = 14 Kp0.47 |
D. | HC = 74 Kp0.33 |
Answer» C. HC = 14 Kp0.47 | |
869. |
What is the minimum height of the chimney in a thermal power plant of capacity 350MW? |
A. | 100m |
B. | 220m |
C. | 380m |
D. | 60m |
Answer» C. 380m | |
870. |
The chimney is emitting particulate matter. Which of the following is the correct expression of the height of the chimney? Here ‘Kp’ represents the emission of particulate matter. |
A. | HC = 74 Kp0.27 |
B. | HC = 14 Kp0.27 |
C. | HC = 14 Kp0.47 |
D. | HC = 74 Kp0.33 |
Answer» B. HC = 14 Kp0.27 | |
871. |
The effective height of stack is given by ___________ |
A. | Plume height / Actual height of the stack |
B. | Plume height * Actual height of the stack |
C. | Plume height – Actual height of the stack |
D. | Plume height + Actual height of the stack |
Answer» E. | |
872. |
Concentration of fluorine that cause a phototoxicological effect on the plant is ___________ |
A. | 0.1μg/m3 |
B. | 0.3μg/m3 |
C. | 0.5μg/m3 |
D. | 1μg/m3 |
Answer» C. 0.5μg/m3 | |
873. |
The size of cigarette particles is ______________ |
A. | 1μm |
B. | 10μm |
C. | <1μm |
D. | >10μm |
Answer» D. >10μm | |
874. |
Which of the following is not a part of photochemical smog? |
A. | NO2 |
B. | O3 |
C. | PAN |
D. | SPM |
Answer» E. | |
875. |
The NWF method uses __________ |
A. | TVD |
B. | NVF |
C. | Both NVF and TVD |
D. | Neither NVF nor TVD |
Answer» C. Both NVF and TVD | |
876. |
What is the difficulty in the direct use of nodal values without the deferred correction method? |
A. | Convergence and stability |
B. | Stability and accuracy |
C. | Accuracy and Boundedness |
D. | Boundedness and convergence |
Answer» B. Stability and accuracy | |
877. |
The Downwind Weighing Factor is a function of the flow variables at ___________ |
A. | the face and upwind nodes |
B. | the far upwind, upwind and downwind nodes |
C. | the upwind and downwind nodes |
D. | the face, upwind and downwind nodes |
Answer» E. | |
878. |
Which of these statements is correct? |
A. | The DWF method converges faster than the NWF method |
B. | Both the methods are of the same properties |
C. | The NWF method is more robust than the DWF method |
D. | The DWF method is more robust than the NWF method |
Answer» D. The DWF method is more robust than the NWF method | |
879. |
What does NWF stand for? |
A. | Normalized Weighing Factor |
B. | Northern Weighing Factor |
C. | Normalized West Factor |
D. | Normalized Weighted Formulation |
Answer» B. Northern Weighing Factor | |
880. |
Deferred correction procedure for high-resolution schemes leads to __________ |
A. | NVF and TVD |
B. | NWF and DWF |
C. | NVF and DWF |
D. | TVD and NWF |
Answer» C. NVF and DWF | |
881. |
If the normalized difference between the cell face values is high, the convergence rate ___________ |
A. | tends to infinity |
B. | is undisturbed |
C. | is low |
D. | is high |
Answer» D. is high | |
882. |
Difference between the upwind line and the high-resolution scheme line gives __________ |
A. | the difference between the upwind and the downwind nodes |
B. | the normalized difference between the cell face values |
C. | the difference between the far upwind and the upwind nodes |
D. | the difference between the far upwind and the downwind nodes |
Answer» C. the difference between the far upwind and the upwind nodes | |
883. |
What is added as a source term in the deferred correction method? |
A. | Difference between the high-resolution and the upwind schemes |
B. | Constants in the high-resolution schemes |
C. | Constants in the upwind schemes |
D. | Difference between the downwind and the upwind schemes |
Answer» B. Constants in the high-resolution schemes | |
884. |
The coefficients in the deferred correction procedure are based on ___________ |
A. | the downwind scheme |
B. | the quick scheme |
C. | the upwind scheme |
D. | the high-resolution scheme |
Answer» D. the high-resolution scheme | |
885. |
Which of the following starter can sufficiently start the DC series motor? |
A. | 3-point starter |
B. | 4-point starter |
C. | 2-point starter |
D. | Cannot be determined |
Answer» D. Cannot be determined | |
886. |
Which of the following is the correct formula for calculating step resistance? |
A. | γ = rn/rn-1 |
B. | γ = rn/rn+1 |
C. | γ = rn*rn-1 |
D. | γ = rn*rn+1 |
Answer» B. γ = rn/rn+1 | |
887. |
For a certain machine having γ = 1.8, we are using starter with 5 steps. What will be the resistance at step 3 if step 2 resistance is equal to 2 Ω? |
A. | 2.111 |
B. | 1.111 |
C. | 3.6 |
D. | 10.8 |
Answer» C. 3.6 | |
888. |
Maximum allowable current for a 240-V DC shunt motor is equal to 65 A. Minimum allowable current for same is equal to 40 A. What will be the value of γ? |
A. | 0.6153 |
B. | 1.265 |
C. | 1.625 |
D. | 2.652 |
Answer» D. 2.652 | |
889. |
What will be the γ value for starter taking 4 steps, where ratio of resistance at maximum allowable current to armature resistance is equal to 1.8? |
A. | 1.2164 |
B. | 1.8 |
C. | 2.2468 |
D. | 0.8220 |
Answer» B. 1.8 | |
890. |
In three-point starter, as a starting handle is rotated __________ |
A. | The resistance is added into armature circuit |
B. | The resistance is removed from field circuit |
C. | The resistance is added into field circuit |
D. | Resistance is neither added nor removed |
Answer» D. Resistance is neither added nor removed | |
891. |
In Polarization-twist reflector, sub-reflector consists of a horizontal grating of wires. |
A. | True |
B. | False |
Answer» B. False | |
892. |
Which of the following condition holds good for minimum total aperture blocking in Cassegrain? |
A. | Area of sub-reflector and projected area of feed are equal |
B. | Area of primary reflector and projected area of feed are equal |
C. | Area of sub-reflector greater than area of primary reflector |
D. | Area of sub-reflector is less than projected area of feed |
Answer» B. Area of primary reflector and projected area of feed are equal | |
893. |
Which of the following is not used for aperture blocking? |
A. | Reducing size of sub-reflector |
B. | Offset feed system |
C. | High directive feed |
D. | Reducing spillover |
Answer» D. Reducing spillover | |
894. |
In which of the following a sub-reflector called trans-reflector is present? |
A. | Polarization-twist reflector |
B. | Plane reflector |
C. | Cassegrain |
D. | Gregorian |
Answer» B. Plane reflector | |
895. |
In which of the following the aperture blocking is reduced by permitting antenna to operate in a single polarization? |
A. | Truncated reflector |
B. | Cassegrain |
C. | Polarization-twist reflector |
D. | Plane reflector |
Answer» D. Plane reflector | |
896. |
Which of the following statement is true regarding a Gregorian antenna? |
A. | Sub-reflector ellipsoidal lies closer to the focus of the paraboloid |
B. | Sub-reflector is a hyperboloid with its convex facing feed |
C. | Sub-reflector is an ellipsoidal with its concave facing reflector |
D. | Sub-reflector is an ellipsoidal with its concave facing feed |
Answer» D. Sub-reflector is an ellipsoidal with its concave facing feed | |
897. |
In which of the following the secondary reflector faces the primary reflector? |
A. | Cassegrain |
B. | Gregorian |
C. | Corner reflector |
D. | Plane reflector |
Answer» C. Corner reflector | |
898. |
Which of the following causes aperture blockage in a Cassegrain antenna? |
A. | Main reflector |
B. | Sub-reflector |
C. | Feed radiator |
D. | Noise from surroundings |
Answer» C. Feed radiator | |
899. |
Which of the following is used to avoid the aperture blockage due to secondary reflector? |
A. | Offset feed system |
B. | Cassegrain |
C. | Plane reflector |
D. | Parabolic antenna |
Answer» B. Cassegrain | |
900. |
Cross-layer communication between data link and network layer can minimize the wastage of resources caused by packet loss. |
A. | True |
B. | False |
Answer» B. False | |