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This section includes 2095 Mcqs, each offering curated multiple-choice questions to sharpen your Php knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
Boiled linseed oil is used as a solvent for ___________ resin. |
| A. | Amber |
| B. | Mastic |
| C. | Gum |
| D. | Rosin |
| Answer» B. Mastic | |
| 852. |
The __________________ is a hard substance and is available from the Earth at the place where pine trees exist in past. |
| A. | Lac |
| B. | Copal |
| C. | Shellac |
| D. | Rosin |
| Answer» C. Shellac | |
| 853. |
___________________ defect occurs when surface to be painted is too smooth. |
| A. | Sagging |
| B. | Running |
| C. | Grinning |
| D. | Wrinkling |
| Answer» C. Grinning | |
| 854. |
___________________ defects is caused by the water vapour which is trapped behind the painted surface. |
| A. | Flaking |
| B. | Fading |
| C. | Blistering |
| D. | Flashing |
| Answer» D. Flashing | |
| 855. |
The cell fusion happens between spleen cells and _____________ |
| A. | Red blood cells |
| B. | Cancer cell |
| C. | Myeloma cells |
| D. | Leukocytes |
| Answer» D. Leukocytes | |
| 856. |
What is the method to harvest monoclonal antibodies from the positive clones? |
| A. | Subculture in the new medium |
| B. | Bioreactors |
| C. | One a single media plate |
| D. | Tissue culture method |
| Answer» E. | |
| 857. |
What do we get when we fuse Spleen cells and Myeloma cells? |
| A. | Hybridoma cells |
| B. | Red blood cells |
| C. | Killer cells |
| D. | Cancer myeloma B-cell |
| Answer» B. Red blood cells | |
| 858. |
What do you add to Myeloma cells to receive HGPRT- myeloma cells? |
| A. | 8 – Azaguanine |
| B. | Azaguanine |
| C. | Nitrogen flush |
| D. | Carbon dioxide flush |
| Answer» B. Azaguanine | |
| 859. |
For how many weeks should you titer the Flow cytometry solution to get pure antigen? |
| A. | 1 month |
| B. | 3 weeks |
| C. | 7 weeks |
| D. | 2 weeks |
| Answer» E. | |
| 860. |
What has become an important tool in biochemistry, molecular biology, and medicine? |
| A. | DNA structure |
| B. | Genome sequencing |
| C. | MCA |
| D. | PCR |
| Answer» D. PCR | |
| 861. |
MCA are antibodies that are non-identical. |
| A. | True |
| B. | False |
| Answer» C. | |
| 862. |
Who invented the process of producing monoclonal antibodies in 1975? |
| A. | Albert Einstein |
| B. | Watson and Creek |
| C. | Georges Köhler and César Milstein |
| D. | Robert Hook |
| Answer» D. Robert Hook | |
| 863. |
What had helped the study of the structure of antibodies in 1970? |
| A. | APC |
| B. | Red blood cells |
| C. | Killer cells |
| D. | Cancer myeloma B-cell |
| Answer» E. | |
| 864. |
Flexural torsional buckling cannot occur in ________ |
| A. | unsymmetrical members |
| B. | cross section with one axis of symmetry |
| C. | cross section with no axis of symmetry |
| D. | doubly symmetric members |
| Answer» E. | |
| 865. |
Which of the following is not a solution for torsional buckling? |
| A. | increasing length of members subjected to torsion |
| B. | by careful arrangement of members |
| C. | by providing bracing to prevent lateral movement and twisting |
| D. | box section fabricated by adding welding side plates to ISHB sections |
| Answer» B. by careful arrangement of members | |
| 866. |
Which of the following is true about torsional buckling? |
| A. | failure occurs by bending about shear centre in longitudinal axis |
| B. | failure occurs when torsional rigidity of member is greater than bending rigidity |
| C. | standard hot rolled shapes are not susceptible to torsional buckling |
| D. | it cannot occur with doubly symmetric cross section |
| Answer» D. it cannot occur with doubly symmetric cross section | |
| 867. |
What is the fundamental path in graph? |
| A. | line along load axis up to P > Pcr |
| B. | line along load axis up to P < Pcr |
| C. | line along load axis up to P = Pcr |
| D. | line along load axis up to P ≥ Pcr |
| Answer» D. line along load axis up to P ≥ Pcr | |
| 868. |
Which of the following is the correct expression of the height of chimney emitting sulfur dioxide? |
| A. | HC = 74 Kp0.27 |
| B. | HC = 14 Kp0.33 |
| C. | HC = 14 Kp0.47 |
| D. | HC = 74 Kp0.33 |
| Answer» C. HC = 14 Kp0.47 | |
| 869. |
What is the minimum height of the chimney in a thermal power plant of capacity 350MW? |
| A. | 100m |
| B. | 220m |
| C. | 380m |
| D. | 60m |
| Answer» C. 380m | |
| 870. |
The chimney is emitting particulate matter. Which of the following is the correct expression of the height of the chimney? Here ‘Kp’ represents the emission of particulate matter. |
| A. | HC = 74 Kp0.27 |
| B. | HC = 14 Kp0.27 |
| C. | HC = 14 Kp0.47 |
| D. | HC = 74 Kp0.33 |
| Answer» B. HC = 14 Kp0.27 | |
| 871. |
The effective height of stack is given by ___________ |
| A. | Plume height / Actual height of the stack |
| B. | Plume height * Actual height of the stack |
| C. | Plume height – Actual height of the stack |
| D. | Plume height + Actual height of the stack |
| Answer» E. | |
| 872. |
Concentration of fluorine that cause a phototoxicological effect on the plant is ___________ |
| A. | 0.1μg/m3 |
| B. | 0.3μg/m3 |
| C. | 0.5μg/m3 |
| D. | 1μg/m3 |
| Answer» C. 0.5μg/m3 | |
| 873. |
The size of cigarette particles is ______________ |
| A. | 1μm |
| B. | 10μm |
| C. | <1μm |
| D. | >10μm |
| Answer» D. >10μm | |
| 874. |
Which of the following is not a part of photochemical smog? |
| A. | NO2 |
| B. | O3 |
| C. | PAN |
| D. | SPM |
| Answer» E. | |
| 875. |
The NWF method uses __________ |
| A. | TVD |
| B. | NVF |
| C. | Both NVF and TVD |
| D. | Neither NVF nor TVD |
| Answer» C. Both NVF and TVD | |
| 876. |
What is the difficulty in the direct use of nodal values without the deferred correction method? |
| A. | Convergence and stability |
| B. | Stability and accuracy |
| C. | Accuracy and Boundedness |
| D. | Boundedness and convergence |
| Answer» B. Stability and accuracy | |
| 877. |
The Downwind Weighing Factor is a function of the flow variables at ___________ |
| A. | the face and upwind nodes |
| B. | the far upwind, upwind and downwind nodes |
| C. | the upwind and downwind nodes |
| D. | the face, upwind and downwind nodes |
| Answer» E. | |
| 878. |
Which of these statements is correct? |
| A. | The DWF method converges faster than the NWF method |
| B. | Both the methods are of the same properties |
| C. | The NWF method is more robust than the DWF method |
| D. | The DWF method is more robust than the NWF method |
| Answer» D. The DWF method is more robust than the NWF method | |
| 879. |
What does NWF stand for? |
| A. | Normalized Weighing Factor |
| B. | Northern Weighing Factor |
| C. | Normalized West Factor |
| D. | Normalized Weighted Formulation |
| Answer» B. Northern Weighing Factor | |
| 880. |
Deferred correction procedure for high-resolution schemes leads to __________ |
| A. | NVF and TVD |
| B. | NWF and DWF |
| C. | NVF and DWF |
| D. | TVD and NWF |
| Answer» C. NVF and DWF | |
| 881. |
If the normalized difference between the cell face values is high, the convergence rate ___________ |
| A. | tends to infinity |
| B. | is undisturbed |
| C. | is low |
| D. | is high |
| Answer» D. is high | |
| 882. |
Difference between the upwind line and the high-resolution scheme line gives __________ |
| A. | the difference between the upwind and the downwind nodes |
| B. | the normalized difference between the cell face values |
| C. | the difference between the far upwind and the upwind nodes |
| D. | the difference between the far upwind and the downwind nodes |
| Answer» C. the difference between the far upwind and the upwind nodes | |
| 883. |
What is added as a source term in the deferred correction method? |
| A. | Difference between the high-resolution and the upwind schemes |
| B. | Constants in the high-resolution schemes |
| C. | Constants in the upwind schemes |
| D. | Difference between the downwind and the upwind schemes |
| Answer» B. Constants in the high-resolution schemes | |
| 884. |
The coefficients in the deferred correction procedure are based on ___________ |
| A. | the downwind scheme |
| B. | the quick scheme |
| C. | the upwind scheme |
| D. | the high-resolution scheme |
| Answer» D. the high-resolution scheme | |
| 885. |
Which of the following starter can sufficiently start the DC series motor? |
| A. | 3-point starter |
| B. | 4-point starter |
| C. | 2-point starter |
| D. | Cannot be determined |
| Answer» D. Cannot be determined | |
| 886. |
Which of the following is the correct formula for calculating step resistance? |
| A. | γ = rn/rn-1 |
| B. | γ = rn/rn+1 |
| C. | γ = rn*rn-1 |
| D. | γ = rn*rn+1 |
| Answer» B. γ = rn/rn+1 | |
| 887. |
For a certain machine having γ = 1.8, we are using starter with 5 steps. What will be the resistance at step 3 if step 2 resistance is equal to 2 Ω? |
| A. | 2.111 |
| B. | 1.111 |
| C. | 3.6 |
| D. | 10.8 |
| Answer» C. 3.6 | |
| 888. |
Maximum allowable current for a 240-V DC shunt motor is equal to 65 A. Minimum allowable current for same is equal to 40 A. What will be the value of γ? |
| A. | 0.6153 |
| B. | 1.265 |
| C. | 1.625 |
| D. | 2.652 |
| Answer» D. 2.652 | |
| 889. |
What will be the γ value for starter taking 4 steps, where ratio of resistance at maximum allowable current to armature resistance is equal to 1.8? |
| A. | 1.2164 |
| B. | 1.8 |
| C. | 2.2468 |
| D. | 0.8220 |
| Answer» B. 1.8 | |
| 890. |
In three-point starter, as a starting handle is rotated __________ |
| A. | The resistance is added into armature circuit |
| B. | The resistance is removed from field circuit |
| C. | The resistance is added into field circuit |
| D. | Resistance is neither added nor removed |
| Answer» D. Resistance is neither added nor removed | |
| 891. |
In Polarization-twist reflector, sub-reflector consists of a horizontal grating of wires. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 892. |
Which of the following condition holds good for minimum total aperture blocking in Cassegrain? |
| A. | Area of sub-reflector and projected area of feed are equal |
| B. | Area of primary reflector and projected area of feed are equal |
| C. | Area of sub-reflector greater than area of primary reflector |
| D. | Area of sub-reflector is less than projected area of feed |
| Answer» B. Area of primary reflector and projected area of feed are equal | |
| 893. |
Which of the following is not used for aperture blocking? |
| A. | Reducing size of sub-reflector |
| B. | Offset feed system |
| C. | High directive feed |
| D. | Reducing spillover |
| Answer» D. Reducing spillover | |
| 894. |
In which of the following a sub-reflector called trans-reflector is present? |
| A. | Polarization-twist reflector |
| B. | Plane reflector |
| C. | Cassegrain |
| D. | Gregorian |
| Answer» B. Plane reflector | |
| 895. |
In which of the following the aperture blocking is reduced by permitting antenna to operate in a single polarization? |
| A. | Truncated reflector |
| B. | Cassegrain |
| C. | Polarization-twist reflector |
| D. | Plane reflector |
| Answer» D. Plane reflector | |
| 896. |
Which of the following statement is true regarding a Gregorian antenna? |
| A. | Sub-reflector ellipsoidal lies closer to the focus of the paraboloid |
| B. | Sub-reflector is a hyperboloid with its convex facing feed |
| C. | Sub-reflector is an ellipsoidal with its concave facing reflector |
| D. | Sub-reflector is an ellipsoidal with its concave facing feed |
| Answer» D. Sub-reflector is an ellipsoidal with its concave facing feed | |
| 897. |
In which of the following the secondary reflector faces the primary reflector? |
| A. | Cassegrain |
| B. | Gregorian |
| C. | Corner reflector |
| D. | Plane reflector |
| Answer» C. Corner reflector | |
| 898. |
Which of the following causes aperture blockage in a Cassegrain antenna? |
| A. | Main reflector |
| B. | Sub-reflector |
| C. | Feed radiator |
| D. | Noise from surroundings |
| Answer» C. Feed radiator | |
| 899. |
Which of the following is used to avoid the aperture blockage due to secondary reflector? |
| A. | Offset feed system |
| B. | Cassegrain |
| C. | Plane reflector |
| D. | Parabolic antenna |
| Answer» B. Cassegrain | |
| 900. |
Cross-layer communication between data link and network layer can minimize the wastage of resources caused by packet loss. |
| A. | True |
| B. | False |
| Answer» B. False | |