Explore topic-wise MCQs in Mass Transfer.

This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Mass Transfer knowledge and support exam preparation. Choose a topic below to get started.

1.

Sherwood number is a function of

A. Lewis number and Reynolds number
B. Prandtl number and Lewis number
C. Reynolds number and Schmidt number
D. Schmidt number and Lewis number
Answer» D. Schmidt number and Lewis number
2.

The expression for average mass transfer coefficient is

A. Sh = 0.664 (Re)<sup> 0.5</sup> (Sc)<sup> 0.33</sup>
B. Sh = 0.664 (Re)<sup> 0.6</sup> (Sc)<sup> 0.33</sup>
C. Sh = 0.332 (Re)<sup> 0.7</sup> (Sc)<sup> 0.33</sup>
D. Sh = 0.332 (Re)<sup> 0.8</sup> (Sc)<sup> 0.33</sup>
Answer» B. Sh = 0.664 (Re)<sup> 0.6</sup> (Sc)<sup> 0.33</sup>
3.

The empirical correlation for local mass transfer coefficient for turbulent boundary layer flow past a flat plate is given by

A. Sh <sub>X</sub> = 0.332 (Re)<sup> 0.5</sup> (Sc)<sup> 0.33</sup>
B. Sh <sub>X</sub> = 0.332 (Re)<sup> 0.6</sup> (Sc)<sup> 0.33</sup>
C. Sh <sub>X</sub> = 0.0298 (Re)<sup> 0.7</sup> (Sc)<sup> 0.33</sup>
D. Sh <sub>X</sub> = 0.0298 (Re)<sup> 0.8</sup> (Sc)<sup> 0.33</sup>
Answer» E.
4.

The empirical correlation for local mass transfer coefficient for laminar boundary layer flow past a flat plate is given by

A. Sh <sub>X</sub> = 0.332 (Re)<sup> 0.5</sup> (Sc)<sup> 0.23</sup>
B. Sh <sub>X</sub> = 0.332 (Re)<sup> 0.5</sup> (Sc)<sup> 0.33</sup>
C. Sh <sub>X</sub> = 0.332 (Re)<sup> 0.5</sup> (Sc)<sup> 0.43</sup>
D. Sh <sub>X</sub> = 0.332 (Re)<sup> 0.5</sup> (Sc)<sup> 0.53</sup>
Answer» C. Sh <sub>X</sub> = 0.332 (Re)<sup> 0.5</sup> (Sc)<sup> 0.43</sup>
5.

Consider the above problem, find the value of Sherwood number

A. 84.44
B. 74.44
C. 64.44
D. 54.44
Answer» D. 54.44
6.

Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of air
D =0.82 * 10 -6 m2/s

A. nv = 15.5 * 10 -6 m<sup>2</sup>/s
B. 0.0176 m/s
C. 1.0176 m/s
D. 2.0176 m/s
E. 3.0176 m/s
Answer» B. 0.0176 m/s
7.

Consider the above problem, find out the value of Reynolds number

A. 14.09 * 10 <sup>8</sup>
B. 14.09 * 10 <sup>7</sup>
C. 14.09 * 10 <sup>6</sup>
D. 14.09 * 10 <sup>5</sup>
Answer» E.