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This section includes 236 Mcqs, each offering curated multiple-choice questions to sharpen your Electrical Engineering knowledge and support exam preparation. Choose a topic below to get started.
51. |
Find the node voltage Vb in the given network. |
A. | – 40 V |
B. | 30 V |
C. | – 30V |
D. | 40 V |
Answer» C. – 30V | |
52. |
Equivalent resistance seen between the terminals a and b for the circuit shown below is: |
A. | 20 Ω |
B. | 4 Ω |
C. | 25 Ω |
D. | 5 Ω |
Answer» C. 25 Ω | |
53. |
A generator develops 200 V and has an internal resistance of 100 Ω. Find the power delivered to a load of 100 Ω. |
A. | 200 W |
B. | 100 W |
C. | 400 W |
D. | 800 W |
Answer» C. 400 W | |
54. |
_____________is an electrical network type which does not follow the law of superposition and also the circuit's parameter values change depending on various factors like current, voltage. |
A. | Bilateral Network |
B. | Non Linear Network |
C. | Active Network |
D. | Passive Network |
Answer» C. Active Network | |
55. |
In full sunlight, a solar cell has a short circuit current of 75 mA and a current of 70 mA for a terminal voltage of 0.6 V with a given load. The Thevenin resistance of solar cell is |
A. | 8 Ω |
B. | 8.6 Ω |
C. | 120 Ω |
D. | 240 Ω |
Answer» D. 240 Ω | |
56. |
Determine the value of Norton’s resistance (in Ω) for the given circuit. |
A. | 12 |
B. | 16 |
C. | 6 |
D. | 4 |
Answer» D. 4 | |
57. |
In the circuit, the value of the resistance Rs required for maximum power transfer from the 10 V source to the 10 Ω load is given by |
A. | 5 Ω |
B. | 10 Ω |
C. | 0 Ω |
D. | 30 Ω |
Answer» D. 30 Ω | |
58. |
For the circuit shown below, what is the value of Vth across X-Y terminals? |
A. | 12 V |
B. | 8 V |
C. | 6 V |
D. | 4 V |
Answer» C. 6 V | |
59. |
A two terminal network is connected to a resistive load whose resistance is equal to Norton resistance of the network. What will be the load current if Norton current is In? |
A. | 2 In / 3 |
B. | In / 2 |
C. | 2 In |
D. | In |
Answer» C. 2 In | |
60. |
In the circuit shown above, the maximum power absorbed by the load resistance RL is |
A. | 1.5 W |
B. | 2.25 W |
C. | 2.5 W |
D. | 5 W |
Answer» C. 2.5 W | |
61. |
Find the maximum power transferred to the load resistance (RL). |
A. | 1.0 W |
B. | 2.5 W |
C. | 6.0 W |
D. | 4.0 W |
Answer» C. 6.0 W | |
62. |
For the network shown below, the Thevenin’s voltage Vab is |
A. | -1.5 V |
B. | -0.5 V |
C. | 0.5 V |
D. | 1.5 V |
Answer» B. -0.5 V | |
63. |
A non-ideal voltage source VS has an internal impedance of ZS If a purely resistive load is to be chosen that maximizes the power transferred to the load, its value must be |
A. | 0 |
B. | Real part of Zs |
C. | Magnitude of Zs |
D. | Complex conjugate of Zs |
Answer» D. Complex conjugate of Zs | |
64. |
Determine the value of load resistance (in Ohms) for a circuit, when the maximum power transferred from the source of 50 V to the load is 25 W. |
A. | 50 |
B. | 40 |
C. | 35 |
D. | 25 |
Answer» E. | |
65. |
In the divider circuit, if RL is attached in parallel to R2, the voltage across R1 doubles. What is the value of RL? |
A. | 1 kΩ |
B. | 2 kΩ |
C. | 3 kΩ |
D. | 1.5 kΩ |
Answer» E. | |
66. |
As per Thevenin’s theorem: if internal impedances are not known, independent voltage and current sources will: |
A. | be replaced by open and short circuit respectively |
B. | be replaced by short and open circuit respectively |
C. | will both be replaced by open circuit |
D. | will both be replaced by short circuit |
Answer» C. will both be replaced by open circuit | |
67. |
Determine the Thevenin equivalent circuit values for the given circuit. |
A. | Vth = 20 V and Rth = 20 Ω |
B. | Vth = 20 V and Rth = 40 Ω |
C. | Vth = 10 V and Rth = 40 Ω |
D. | Vth = 10 V and Rth = 20 Ω |
Answer» C. Vth = 10 V and Rth = 40 Ω | |
68. |
Determine the power (in W) delivered form the source for the circuit given below. |
A. | 23.8 |
B. | 26.6 |
C. | 24.6 |
D. | 22.6 |
Answer» B. 26.6 | |
69. |
An ac source of voltage \(\rm E_S\) and an internal impedance of \(\rm {Z_{th}} = \left( {{R_S} + j{X_S}} \right)\) is connected to a load of impedance \(\rm {Z_L} = \left( {{R_L} + j{X_L}} \right)\). Consider the following condition in this regard.1. \(\rm {X_L} = {X_S}\) if only \(\rm X_L\) is varied2. \(\rm {X_L} = - {X_S}\) if only \(\rm X_L\) is varied3. \(\rm {R_L} = \sqrt {R_S^2 + {{\left( {{X_S} + {X_L}} \right)}^2}} \), if only \(\rm R_L\) is varied4. \(\rm \left| {{Z_L}} \right| = \left| {{Z_S}} \right|\) If the magnitude alone of \(\rm Z_L\) is varied, keeping the phase angle fixed.Among these conditions, those which are to be satisfied for maximum power transfer from the source to the load would include |
A. | 2 and 3 |
B. | 1 and 3 |
C. | 1, 2 and 4 |
D. | 2, 3 and 4 |
Answer» E. | |
70. |
Maximum power is transferred when the load resistance is |
A. | equal to source resistance |
B. | equal to half of the source resistance |
C. | equal to zero |
D. | none of these |
Answer» B. equal to half of the source resistance | |
71. |
______ states that if an element in a network is replaced by a voltage/current source whose voltage/current at any instant of time is equal to the voltage/current across the element in the previous network then the initial condition in the rest of the network will be unaltered. |
A. | Substitution Theorem |
B. | Thevenin’s Theorem |
C. | Reciprocity Theorem |
D. | Norton’s Theorem |
Answer» B. Thevenin’s Theorem | |
72. |
Find the current flowing through the resistor R4? |
A. | 0.48 A |
B. | 0.96 A |
C. | 0.24 A |
D. | 1.2 A |
Answer» C. 0.24 A | |
73. |
A network consists of a large number of ideal linear resistors, one of which is R and 2 constant ideal sources. The power consumed by R is P1 when only the first source is active and P2 when only the second source is active. If both sources are active simultaneously, then the power consumed by R is |
A. | P1 ± P2 |
B. | \(\sqrt {{P_1}} \pm \sqrt {{P_2}}\) |
C. | \({\left( {\sqrt {{P_1}} \pm \sqrt {{P_2}} } \right)^2}\) |
D. | \({\left( {{P_1} \pm {P_2}} \right)^2}\) |
Answer» D. \({\left( {{P_1} \pm {P_2}} \right)^2}\) | |
74. |
For AC networks, as per the maximum power transfer theorem, for maximum power transfer, the load impedance should be equal to: |
A. | twice the load impedance |
B. | Complex conjugate of the source impedance |
C. | Twice the complex conjugate of load impedance |
D. | None of these |
Answer» C. Twice the complex conjugate of load impedance | |
75. |
Consider the resistive circuit shown below, the value of Norton current across the terminal AB is |
A. | - 6 A |
B. | 2 A |
C. | 7 A |
D. | - 4.5 A |
Answer» D. - 4.5 A | |
76. |
Consider the following network:(a) The power dissipated in resistor R1 is P1(b) Power dissipated in resistor R2 is P2(c) Power dissipated in resistor R3 is P3Arrange the above in increasing order of the dissipated power: |
A. | (a), (c) = (b) |
B. | (a), (b), (c) |
C. | (b), (c), (a) |
D. | (c), (a), (b) |
Answer» B. (a), (b), (c) | |
77. |
If R2 is 6 kΩ, then determine the current I2 in the network shown using superposition principle. |
A. | 2.25 mA |
B. | 3.75 μA |
C. | 2.25 μA |
D. | 3.75 mA |
Answer» E. | |
78. |
Current through 2 Ω resistor in the network shown is: |
A. | 0 A |
B. | 5 A |
C. | 1 A |
D. | 2 A |
Answer» B. 5 A | |
79. |
Calculate current I in the following circuit using super position theorem. |
A. | 375 mA |
B. | 200 mA |
C. | 150 mA |
D. | 100 mA |
Answer» B. 200 mA | |
80. |
In the circuit shown above, for different values of R, the values of V and I are given, other elements remaining the sameWhen R = ∞, V = 5 VWhen R = 0, I = 2.5 AWhen R = 3 Ω, the value of V is given by |
A. | 1 V |
B. | 5 V |
C. | 3 V |
D. | 2 V |
Answer» D. 2 V | |
81. |
In the circuit below, when V0 = 0, I = 4 A. Find the current when V0 = 20 V. |
A. | 7 A |
B. | 9 A |
C. | 4 A |
D. | 5 A |
Answer» C. 4 A | |
82. |
A practical dc current source provides 20 kW to a 50 Ω load and 20 kW to a 200 Ω load. The maximum power that can drawn from it, is |
A. | 22.5 kW |
B. | 30.3 kW |
C. | 40.5 kW |
D. | 45.0 kW |
Answer» B. 30.3 kW | |
83. |
A 120 V source has a series internal resistance of 1 Ω. The maximum power that can be delivered to load is |
A. | 1800 W |
B. | 3600 W |
C. | 800 W |
D. | 14400 W |
Answer» C. 800 W | |
84. |
Determine the Norton’s resistance (in Ohms) between terminal A and B for the circuit given below. |
A. | 6.5 |
B. | 5.4 |
C. | 4.5 |
D. | 3.5 |
Answer» E. | |
85. |
In the circuit shown below, VS is a constant voltage source and IL is a constant current load.The value of \(\rm I_L\) that maximizes the power absorbed by the constant current load is |
A. | \(\frac{{{{\rm{V}}_{\rm{s}}}}}{{4{\rm{R}}}}\) |
B. | \(\frac{{{{\rm{V}}_{\rm{s}}}}}{{2{\rm{R}}}}\) |
C. | \(\frac{{{{\rm{V}}_{\rm{s}}}}}{{\rm{R}}}\) |
D. | \(\rm\infty\) |
Answer» C. \(\frac{{{{\rm{V}}_{\rm{s}}}}}{{\rm{R}}}\) | |
86. |
In the circuit shown below, the Thevenin voltage VTH is |
A. | 2.4 V |
B. | 2.8 V |
C. | 3.6 V |
D. | 4.5 V |
Answer» D. 4.5 V | |
87. |
Find the Thevenin's voltage Vth across 2-ohm resistance. |
A. | 8.908 V |
B. | 3.455 V |
C. | 4.778 V |
D. | 2.571 V |
Answer» E. | |
88. |
Maximum power transfer from source to load occurs when the load resistance is ________ the internal resistance of the circuit. |
A. | equal to |
B. | more than |
C. | less than |
D. | double |
Answer» B. more than | |
89. |
Find the maximum power transferred to R in the circuit shown. |
A. | 3.025 W |
B. | 3.25 W |
C. | 2.151 W |
D. | 5.203 W |
Answer» B. 3.25 W | |
90. |
In the circuit shown, Thevenin’s voltage as seen from the terminals AB is |
A. | 0 V |
B. | 1.5 V |
C. | 6.0 V |
D. | indeterminate |
Answer» B. 1.5 V | |
91. |
According to maximum power transfer, the maximum efficiency that can be achieved during power transfer from a power source to an external load can be ______ % |
A. | 100 |
B. | 25 |
C. | 75 |
D. | 50 |
Answer» E. | |
92. |
Assuming an ideal transformer, The Thevenin’s equivalent voltage and impedance as seen from the terminals x and y for the circuit in figure are |
A. | 2 sin (ωt), 4 Ω |
B. | 1 sin (ωt), 1 Ω |
C. | 1 sin (ωt), 2 Ω |
D. | 2 sin (ωt), 0.5 Ω |
Answer» B. 1 sin (ωt), 1 Ω | |
93. |
In the circuit shown below, the value of the capacitor C required for maximum power to be transferred to the load is |
A. | 1 nF |
B. | 1 μF |
C. | 1 mF |
D. | 10 mF |
Answer» E. | |
94. |
A circuit having Thevenin voltage Vth and Thevenin resistor Rth is connected to a load resistor RL. The condition for maximum power to the load is: |
A. | RL = Rth |
B. | RL = Rth/2 |
C. | RL = 3 Rth |
D. | RL = 2 Rth |
Answer» B. RL = Rth/2 | |
95. |
In the given circuit, the value of current flowing through the 10-ohm resistance is: |
A. | 0.5 A |
B. | 0.88 A |
C. | 1 A |
D. | 2 A |
Answer» C. 1 A | |
96. |
A source having internal impedance of (9 + j12) Ω is to deliver maximum power to a resistive load. The load resistance should be |
A. | 9 Ω |
B. | 12 Ω |
C. | 15 Ω |
D. | 21 Ω |
Answer» D. 21 Ω | |
97. |
A non ideal ac voltage source Vs has an internal impedance of Zs. If a purely resistive load is to be chosen that maximized the power transferred to the load, its value must be: |
A. | 0 |
B. | Real part of Zs |
C. | Magnitude of Zs |
D. | Complex conjugats of Zs |
Answer» D. Complex conjugats of Zs | |
98. |
For the network shown in the given figure, find Norton’s current, assuming 2 ohm as the load. |
A. | 5 A |
B. | 1 A |
C. | 7 A |
D. | 14 A |
Answer» E. | |
99. |
By applying the principle of superposition to the circuit, the Vvoltage V across resistance R is: |
A. | 5 V |
B. | 4 V |
C. | 2 V |
D. | 1 V |
Answer» E. | |
100. |
For the network shown above, I = (0.2 V - 2) A, (I = the current delivered by the voltage source V). The Thevenin voltage Vth and resistance Rth for the network N across the terminal AB are respectively |
A. | -10 V, 5 Ω |
B. | 10 V, 5 Ω |
C. | -10 V, 0.2 Ω |
D. | 10 V, 0.2 Ω |
Answer» C. -10 V, 0.2 Ω | |