MCQOPTIONS
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This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Mathematics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be yellow if the first ball drawn is red? The balls are not replaced in the bag. |
| A. | ( frac {1}{3} ) |
| B. | ( frac {1}{2} ) |
| C. | 1 |
| D. | 0 |
| Answer» E. | |
| 2. |
A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be green if the first ball drawn is red? The balls are not replaced in the bag. |
| A. | 0.82 |
| B. | 0.91 |
| C. | 1.23 |
| D. | 0.5 |
| Answer» E. | |
| 3. |
A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white if the first ball drawn is white? The balls are replaced in the bag. |
| A. | ( frac {1}{9} ) |
| B. | ( frac {2}{9} ) |
| C. | ( frac {1}{8} ) |
| D. | ( frac {2}{8} ) |
| Answer» D. ( frac {2}{8} ) | |
| 4. |
A bag contains 3 red, 2 white and 4 green balls. What is the probability of drawing the second ball to be white if the first ball drawn is white? The balls are not replaced in the bag. |
| A. | ( frac {1}{9} ) |
| B. | ( frac {2}{9} ) |
| C. | ( frac {7}{8} ) |
| D. | ( frac {1}{8} ) |
| Answer» E. | |
| 5. |
A bag contains 4 red and 7 blue balls. What is the probability of drawing a red ball if the first ball drawn is blue? The balls drawn are replaced in the bag. |
| A. | ( frac {4}{11} ) |
| B. | ( frac {8}{11} ) |
| C. | ( frac {4}{18} ) |
| D. | ( frac {14}{11} ) |
| Answer» B. ( frac {8}{11} ) | |
| 6. |
A bag contains 4 red and 7 blue balls. What is the probability of drawing a red ball if the first ball drawn is blue? The balls drawn are not replaced in the bag. |
| A. | ( frac {7}{11} ) |
| B. | ( frac {7}{10} ) |
| C. | ( frac {4}{10} ) |
| D. | ( frac {9}{11} ) |
| Answer» D. ( frac {9}{11} ) | |
| 7. |
A bag contains 4 red and 7 blue balls. What is the probability of drawing a blue ball if the first ball drawn is red? The balls drawn are not replaced in the bag. |
| A. | ( frac {7}{10} ) |
| B. | ( frac {8}{10} ) |
| C. | ( frac {7}{1} ) |
| D. | ( frac {4}{11} ) |
| Answer» B. ( frac {8}{10} ) | |
| 8. |
A bag contains 4 red and 7 blue balls. What is the probability of drawing a blue ball if the first ball drawn is red? The balls drawn are replaced into the bag. |
| A. | ( frac {8}{11} ) |
| B. | ( frac {7}{11} ) |
| C. | ( frac {4}{11} ) |
| D. | ( frac {7}{4} ) |
| Answer» C. ( frac {4}{11} ) | |
| 9. |
A box contains 3 red and 4 blue marbles. Two marbles are drawn without replacement. What is the probability that the second marble is red if it is known the first marblel is red? |
| A. | ( frac {3}{7} ) |
| B. | ( frac {4}{7} ) |
| C. | ( frac {1}{3} ) |
| D. | ( frac {1}{7} ) |
| Answer» D. ( frac {1}{7} ) | |
| 10. |
A bag contains 9 identical balls, of which are 4 are blue and 6 are green. Three balls are taken out randomly from the bag after one another. Find the probability that all three balls are blue? |
| A. | ( frac {5}{8} ) |
| B. | ( frac {6}{19} ) |
| C. | ( frac {5}{21} ) |
| D. | ( frac {4}{7} ) |
| Answer» D. ( frac {4}{7} ) | |
| 11. |
A bag contains 6 pink and 8 white pebbles. What is the probability of drawing a brown pebble if the first pebble drawn is pink? The balls drawn are not replaced in the bag. |
| A. | 0 |
| B. | ( frac {8}{11} ) |
| C. | 1 |
| D. | ( frac {14}{11} ) |
| Answer» B. ( frac {8}{11} ) | |
| 12. |
A box contains 5 brown and 7 black pebbles. What is the probability of drawing a brown pebble if the first pebble drawn is black? The balls drawn are not replaced in the box. |
| A. | ( frac {5}{11} ) |
| B. | ( frac {8}{11} ) |
| C. | ( frac {4}{18} ) |
| D. | ( frac {14}{11} ) |
| Answer» B. ( frac {8}{11} ) | |
| 13. |
Which of this represents the multiplication theorem of probability? |
| A. | P(A B) = P(B) P(B/A) |
| B. | P(A B) = P(A) P(B/A) |
| C. | P(A B) = P(A) P(B/B) |
| D. | P(A B) = P(A) P(A/A) |
| Answer» C. P(A B) = P(A) P(B/B) | |