MCQOPTIONS
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MCQOPTIONS
This section includes 19 Mcqs, each offering curated multiple-choice questions to sharpen your Fluid Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If the side slope angle in a trapezoidal section is 45° and it discharges to the maximize extent, calculate the top width of the channel section. Given: y = 4m |
| A. | 10.31m |
| B. | 11.31m |
| C. | 12.31m |
| D. | 13.31m |
| Answer» C. 12.31m | |
| 2. |
The maximum discharge through the trapezoidal channel is 20 m3/s and the velocity of flow is 5 m/s. Calculate the base width of the channel if the side slope is 1H:4V. |
| A. | 3.31m |
| B. | 2.31m |
| C. | 1.31m |
| D. | 0.31m |
| Answer» C. 1.31m | |
| 3. |
Calculate the maximum discharge through a trapezoidal channel if the wetted perimeter is 6.24m, side slope of 1H:2V and base width of 4m. Given: C=55 and S0=1/1500. |
| A. | 3.52 m3/s |
| B. | 4.52 m3/s |
| C. | 5.52 m3/s |
| D. | 6.52 m3/s |
| Answer» C. 5.52 m3/s | |
| 4. |
The wetted perimeter of the most economical trapezoidal section is 7.47m, the base width is 3m and has the side slope of 1H:2V. |
| A. | 1m |
| B. | 2m |
| C. | 3m |
| D. | 4m |
| Answer» C. 3m | |
| 5. |
Calculate the depth of the most economical trapezoidal channel section having wetted area equal to 50m2 and the side slope of 1H:5V. |
| A. | 3.21m |
| B. | 4.21m |
| C. | 5.21m |
| D. | 6.21m |
| Answer» D. 6.21m | |
| 6. |
The wetted area of a most economical trapezoidal section is 21.58m2, base width of 5m and side slope of 1H:3V. Calculate the maximum discharge through the channel if the C=60 and S0=1/500. |
| A. | 56.32 m3/ s |
| B. | 66.32 m3/ s |
| C. | 76.32 m3/ s |
| D. | 86.32 m3/ s |
| Answer» D. 86.32 m3/ s | |
| 7. |
THE_WETTED_PERIMETER_OF_THE_MOST_ECONOMICAL_TRAPEZOIDAL_SECTION_IS_7.47M,_THE_BASE_WIDTH_IS_3M_AND_HAS_THE_SIDE_SLOPE_OF_1H:2V.?$ |
| A. | 1m |
| B. | 2m |
| C. | 3m |
| D. | 4m |
| Answer» C. 3m | |
| 8. |
The maximum discharge through the trapezoidal channel is 20 m3/s and the velocity of flow is 5 m/s. Calculate the base width of the channel if the side slope is 1H:4V.$ |
| A. | 3.31m |
| B. | 2.31m |
| C. | 1.31m |
| D. | 0.31m |
| Answer» C. 1.31m | |
| 9. |
Calculate the maximum discharge through a trapezoidal channel if the wetted perimeter is 6.24m, side slope of 1H:2V and base width of 4m. Given: C=55 and S0=1/1500.$ |
| A. | 3.52 m<sup>3</sup>/s |
| B. | 4.52 m<sup>3</sup>/s |
| C. | 5.52 m<sup>3</sup>/s |
| D. | 6.52 m<sup>3</sup>/s |
| Answer» C. 5.52 m<sup>3</sup>/s | |
| 10. |
If the side slope angle in a trapezoidal section is 45° and it discharges to the maximize extent, calculate the top width of the channel section. Given: y = 4m$ |
| A. | 10.31m |
| B. | 11.31m |
| C. | 12.31m |
| D. | 13.31m |
| Answer» C. 12.31m | |
| 11. |
Calculate the maximum discharge through a trapezoidal channel if the depth is 5m. |
| A. | 56.67 m<sup>3</sup>/s |
| B. | 66.67 m<sup>3</sup>/s |
| C. | 76.67 m<sup>3</sup>/s |
| D. | 86.67 m<sup>3</sup>/s |
| Answer» E. | |
| 12. |
What is the angle made by the sloping side when the trapezoidal channel discharges to the maximum extent? |
| A. | 30° |
| B. | 45° |
| C. | 60° |
| D. | 90° |
| Answer» D. 90¬¨¬®‚Äö√†√ª | |
| 13. |
Calculate the depth of the most economical trapezoidal channel section having wetted area equal to 50m2 and the side slope of 1H:5V? |
| A. | 3.21m |
| B. | 4.21m |
| C. | 5.21m |
| D. | 6.21m |
| Answer» D. 6.21m | |
| 14. |
The wetted area of a most economical trapezoidal section is 21.58m2, base width of 5m and side slope of 1H:3V. Calculate the maximum discharge through the channel if the C=60 and S0=1/500. |
| A. | 56.32 m<sup>3</sup>/ s |
| B. | 66.32 m<sup>3</sup>/ s |
| C. | 76.32 m<sup>3</sup>/ s |
| D. | 86.32 m<sup>3</sup>/ s |
| Answer» D. 86.32 m<sup>3</sup>/ s | |
| 15. |
Calculate the maximum discharge through a trapezoidal section having depth 3m, side slope 1H:4V and bed slope of 1 in 2000. Given: n = 0.025. |
| A. | 19.09 m<sup>3</sup>/s |
| B. | 20.09 m<sup>3</sup>/s |
| C. | 21.09 m<sup>3</sup>/s |
| D. | 22.09 m<sup>3</sup>/s |
| Answer» B. 20.09 m<sup>3</sup>/s | |
| 16. |
The base of the most economical trapezoidal channel section is 6m and the side slope is 1H:2V, calculate the maximum discharge through the channel if the bed slope is 1 in 1000 and C = 50. |
| A. | 120.61 m<sup>3</sup>/s |
| B. | 110.61 m<sup>3</sup>/s |
| C. | 100.61 m<sup>3</sup>/s |
| D. | 90.61 m<sup>3</sup>/s |
| Answer» D. 90.61 m<sup>3</sup>/s | |
| 17. |
The top width of a most economical trapezoidal channel section is 8m, determine the hydraulic radius of the channel if the side slope is 1H:3V. |
| A. | 1.8m |
| B. | 1.9m |
| C. | 2.0m |
| D. | 2.1m |
| Answer» C. 2.0m | |
| 18. |
The top width of a most economical trapezoidal channel section is 7m and the side slope of the channel is 1H:2V, determine the depth of the channel section. |
| A. | 2.13m |
| B. | 3.13m |
| C. | 4.13m |
| D. | 5.13m |
| Answer» C. 4.13m | |
| 19. |
Estimate the hydraulic radius of the most economical trapezoidal channel section having depth y and side slope Z. |
| A. | <sup>y</sup>‚ÅÑ<sub>2</sub> |
| B. | y |
| C. | 2y |
| D. | 3y |
| Answer» B. y | |