 
			 
			MCQOPTIONS
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				This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Fluid Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. | If the side slope angle in a trapezoidal section is 45 and it discharges to the maximize extent, calculate the top width of the channel section. Given: y = 4m | 
| A. | 10.31m | 
| B. | 11.31m | 
| C. | 12.31m | 
| D. | 13.31m | 
| Answer» C. 12.31m | |
| 2. | What is the side slope for the most economic trapezoidal channel having depth y and base width B? | 
| A. | ( frac{1}{ sqrt{2}} ) | 
| B. | ( frac{1}{ sqrt{3}} ) | 
| C. | ( frac{1}{2} ) | 
| D. | ( frac{1}{3} ) | 
| Answer» C. ( frac{1}{2} ) | |
| 3. | The maximum discharge through the trapezoidal channel is 20 m3/s and the velocity of flow is 5 m/s. Calculate the base width of the channel if the side slope is 1H:4V. | 
| A. | 3.31m | 
| B. | 2.31m | 
| C. | 1.31m | 
| D. | 0.31m | 
| Answer» C. 1.31m | |
| 4. | Calculate the maximum discharge through a trapezoidal channel if the wetted perimeter is 6.24m, side slope of 1H:2V and base width of 4m. Given: C=55 and S0=1/1500. | 
| A. | 3.52 m<sup>3</sup>/s | 
| B. | 4.52 m<sup>3</sup>/s | 
| C. | 5.52 m<sup>3</sup>/s | 
| D. | 6.52 m<sup>3</sup>/s | 
| Answer» C. 5.52 m<sup>3</sup>/s | |
| 5. | The wetted perimeter of the most economical trapezoidal section is 7.47m, the base width is 3m and has the side slope of 1H:2V. | 
| A. | 1m | 
| B. | 2m | 
| C. | 3m | 
| D. | 4m | 
| Answer» C. 3m | |
| 6. | Calculate the depth of the most economical trapezoidal channel section having wetted area equal to 50m2 and the side slope of 1H:5V. | 
| A. | 3.21m | 
| B. | 4.21m | 
| C. | 5.21m | 
| D. | 6.21m | 
| Answer» D. 6.21m | |
| 7. | Determine the top width length of the most economical trapezoidal channel section having depth y and side slope Z. | 
| A. | ( sqrt{1+Z^2} ) | 
| B. | ( frac{y}{2} sqrt{1+Z^2} ) | 
| C. | y ( sqrt{1+Z^2} ) | 
| D. | 2y ( sqrt{1+Z^2} ) | 
| Answer» E. | |