MCQOPTIONS
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MCQOPTIONS
This section includes 19 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The ___________ forces do not cause the rotation if the rotation is considered in about the axis of the body or the centroid axis of the body. |
| A. | Non-concurrent |
| B. | Concurrent |
| C. | Parallel |
| D. | Non-Parallel |
| Answer» C. Parallel | |
| 2. |
Determine the magnitude of the moment of the force about the y-axis. |
| A. | -72Nm |
| B. | 82Nm |
| C. | 210Nm |
| D. | 50NmView Answer |
| Answer» D. 50NmView Answer | |
| 3. |
Determine the magnitude of the moment of the force about the axis PQ. |
| A. | -72Nm |
| B. | 82Nm |
| C. | 90Nm |
| D. | 50NmView Answer |
| Answer» B. 82Nm | |
| 4. |
Determine the moment of the force F along the segment QP of the pipe assembly shown in the figure. |
| A. | 110Nm |
| B. | 100Nm |
| C. | 500Nm |
| D. | 510NmView Answer |
| Answer» C. 500Nm | |
| 5. |
Determine the moment MQP in the vector form produced by the force as shown in the diagram, which tends to rotate the rod ORQP along QP. |
| A. | 72i + 36j Nm |
| B. | 72i – 36j Nm |
| C. | -72i – 36j Nm |
| D. | -72i + 36j NmView Answer |
| Answer» B. 72i – 36j Nm | |
| 6. |
What if the moment of the force calculated about the axis is negative? |
| A. | It means that the force is applied in the opposite direction as imagined |
| B. | It means that the direction of the motion is in the opposite sense as imagined |
| C. | It means that the radius vector is in the opposite sense as imagined |
| D. | Such calculation means that the calculations are wrongly done |
| Answer» C. It means that the radius vector is in the opposite sense as imagined | |
| 7. |
What if the perpendicular distance from the axis is infinity? |
| A. | The rotation is not possible |
| B. | The rotation is possible but the moment generated is very less |
| C. | The force applied will be very much high for even a small rotation |
| D. | No rotation unless the contact is being broken |
| Answer» D. No rotation unless the contact is being broken | |
| 8. |
The axis vector in the calculation of the moment along the axis of rotation is the axis which is collinear with the force vector. |
| A. | True |
| B. | False |
| Answer» C. | |
| 9. |
Determine the moment’s magnitude produced by the force as shown in the diagram, which tends to rotate the rod ORQP along QP. |
| A. | 80.49 Nm |
| B. | 72.12 Nm |
| C. | -36.67 Nm |
| D. | 36.67 NmView Answer |
| Answer» B. 72.12 Nm | |
| 10. |
WHAT_IF_THE_PERPENDICULAR_DISTANCE_FROM_THE_AXIS_IS_INFINITY??$ |
| A. | The rotation is not possible |
| B. | The rotation is possible but the moment generated is very less |
| C. | The force applied will be very much high for even a small rotation |
| D. | No rotation unless the contact is being broken |
| Answer» C. The force applied will be very much high for even a small rotation | |
| 11. |
WHICH_OF_THE_FOLLOWING_IS_CORRECT??$ |
| A. | We cannot represent the moment caused by the force along any axis in vector form |
| B. | We can represent the moment caused by the force along any axis in the scalar form |
| C. | We cannot represent the moment caused by the force along any point in vector form |
| D. | We can represent the moment caused by the force along any axis in vector form |
| Answer» C. We cannot represent the moment caused by the force along any point in vector form | |
| 12. |
What if the moment of the force calculated about the axis is negative?$ |
| A. | It means that the force is applied in the opposite direction as imagined |
| B. | It means that the direction of the motion is in the opposite sense as imagined |
| C. | It means that the radius vector is in the opposite sense as imagined |
| D. | Such calculation means that the calculations are wrongly done |
| Answer» C. It means that the radius vector is in the opposite sense as imagined | |
| 13. |
In the equation A.(rxF) the r is heading from ______________ and ending at _____________$ |
| A. | Axis of rotation, Force vector |
| B. | Axis of rotation, Force vector’s point of action on the body |
| C. | Force vector, Axis of rotation |
| D. | Force vector’s point of action on the body, Axis of rotation |
| Answer» B. Axis of rotation, Force vector‚Äö√Ñ√∂‚àö√ë‚àö¬•s point of action on the body | |
| 14. |
72i + 36j Nm |
| A. | 72i – 36j Nm |
| B. | -72i – 36j Nm |
| C. | -72i + 36j Nm |
| Answer» C. -72i + 36j Nm | |
| 15. |
In the equation A.(rxF), the r vector is what? |
| A. | The magnitude of the axis, i.e. the length of the axis |
| B. | The length of the force vector |
| C. | The length of the radius |
| D. | The radius vector |
| Answer» E. | |
| 16. |
Which of the following is correct? (For A representing the vector representation of the axis of rotation, r the radius vector and F the force vector) |
| A. | A.(rxF) |
| B. | Ax(rxF) |
| C. | A.(r.F) |
| D. | Fx(r.F) |
| Answer» C. A.(r.F) | |
| 17. |
In the calculation of the moment of the force about the axis, the cross product table, i.e. the 3X3 matrix which is made for doing the cross product having 3 rows, contains three elements. Which are they from top to bottom? |
| A. | Axis coordinates, point coordinates, and the force coordinates |
| B. | Point coordinates, axis coordinates, and the force coordinates |
| C. | Axis coordinates, force coordinates, and the point coordinates |
| D. | Force coordinates, point coordinates, and the axis coordinates |
| Answer» E. | |
| 18. |
The calculation of the moment about the axis and the moment about any point by a force applied on the body are different from each other. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 19. |
49 Nm |
| A. | 72.12 Nm |
| B. | -36.67 Nm |
| C. | 36.67 Nm |
| Answer» B. -36.67 Nm | |