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This section includes 26 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering Chemistry knowledge and support exam preparation. Choose a topic below to get started.
1. |
Choose the incorrect statement from the following options. |
A. | In bonding molecular orbital, electron density is low in the region between the nuclei of bonded atoms |
B. | The energy of antibonding molecular orbital is higher than that of atomic orbitals from which it is formed |
C. | Every electron in bonding molecular orbital contributes toward stability of the molecule |
D. | Antibonding takes place when lobes of atomic orbitals have different signs |
Answer» B. The energy of antibonding molecular orbital is higher than that of atomic orbitals from which it is formed | |
2. |
According to Molecular Orbital Theory, the shape and size of a molecular orbital depends upon _________ |
A. | Shape and size of the combining atomic orbitals |
B. | Numbers of the combining atomic orbitals |
C. | Orientation of the combining atomic orbitals |
D. | All of the mentioned |
Answer» E. | |
3. |
The relative energies of molecular orbitals in increasing order have been found to be as follows.(σ1s) < (σ*1s) < (σ2s) < (σ*2s) < [(π2py)(π2pz)] < (σ 2px) < [(π*2py)(π*2pz)] < (σ*2px) |
A. | For O2 to Ne2 |
B. | For H2 to N2 |
C. | For H2 to Ne2 |
D. | For N2 to Ne2 |
Answer» C. For H2 to Ne2 | |
4. |
Bond Order of O2, F2, N2 respectively are __________ |
A. | +1, +2, +3 |
B. | +2, +3, +1 |
C. | +2, +1, +3 |
D. | +3, +2, +1 |
Answer» D. +3, +2, +1 | |
5. |
The filling of molecular orbital takes place according to __________ |
A. | The Aufbau Principle |
B. | Pauli Exclusion Principle |
C. | Hund’s rule of maximum multiplicity |
D. | All of the mentioned |
Answer» E. | |
6. |
If the sign of the wave function is unchanged when the orbital is reflected about its centre, the orbital is ______________ |
A. | Gerade |
B. | Ungerade |
C. | Gerade as well as Ungerade |
D. | None of the mentioned |
Answer» B. Ungerade | |
7. |
Which of the following molecule is not true about paramagnetic molecules? |
A. | Attracted by the magnetic field |
B. | A molecular orbital is singly occupied |
C. | An example is oxygen molecule |
D. | Repelled by the magnetic field |
Answer» E. | |
8. |
What do you think is the relationship between bond order and bond length? |
A. | Directly proportional |
B. | Indirectly proportional |
C. | No relation |
D. | Cannot predict |
Answer» C. No relation | |
9. |
What’s the bond order of Oxygen? |
A. | 3 |
B. | 2 |
C. | 1 |
D. | 0 |
Answer» C. 1 | |
10. |
Take NA as the number of Anti-bonding molecular orbitals and NB as the number of Bonding molecular orbitals. The molecule is stable when NA ____________ NB. |
A. | is greater than |
B. | is equal to |
C. | is less than |
D. | is greater than or equal to |
Answer» D. is greater than or equal to | |
11. |
Which of the bonding orbital has greater energy comparatively? |
A. | Both Bonding molecular orbital and Anti-bonding molecular orbital have the same energy |
B. | The energy of Bonding molecular orbital and Anti-bonding molecular orbital depends on the situation |
C. | Bonding molecular orbital |
D. | Anti-bonding molecular orbital |
Answer» E. | |
12. |
Sigma molecular orbitals are not symmetrical around the bonding axis. |
A. | True |
B. | False |
Answer» C. | |
13. |
Which of the following is a condition for the combination of atomic orbitals? |
A. | Combining atomic orbitals need not have equal energy |
B. | Combining atomic orbitals must have symmetry as per molecular axis |
C. | Combining atomic orbitals must overlap to a minimum extent |
D. | For combining atomic orbitals, X-axis should be taken as a molecular axis |
Answer» C. Combining atomic orbitals must overlap to a minimum extent | |
14. |
\(\psi\)MO = \(\psi\)A + \(\psi\)B. |
A. | True |
B. | False |
Answer» B. False | |
15. |
Stability increases, as the energy ___________ |
A. | increases |
B. | doesn’t change |
C. | decreases |
D. | increases and then decreases |
Answer» D. increases and then decreases | |
16. |
Combination of two atomic orbitals results in the formation of two molecular orbitals namely _________ |
A. | one bonding and one non-bonding orbital |
B. | two bonding orbitals |
C. | two non-bonding orbitals |
D. | two bonding and non-bonding orbitals |
Answer» B. two bonding orbitals | |
17. |
CHOOSE_THE_INCORRECT_STATEMENT_FROM_THE_FOLLOWING_OPTIONS.?$ |
A. | In bonding molecular orbital, electron density is low in the region between the nuclei of bonded atoms |
B. | The energy of antibonding molecular orbital is higher than that of atomic orbitals from which it is formed |
C. | Every electron in bonding molecular orbital contributes toward stability of the molecule |
D. | Antibonding takes place when lobes of atomic orbitals have different signs |
Answer» B. The energy of antibonding molecular orbital is higher than that of atomic orbitals from which it is formed | |
18. |
ACCORDING_TO_MOLECULAR_ORBITAL_THEORY,_THE_SHAPE_AND_SIZE_OF_A_MOLECULAR_ORBITAL_DEPENDS_UPON?$ |
A. | Shape and size of the combining atomic orbitals |
B. | Numbers of the combining atomic orbitals |
C. | Orientation of the combining atomic orbitals |
D. | All of the mentioned |
Answer» E. | |
19. |
The relative energies of molecular orbitals in increasing order have been found to be as follows? |
A. | < (σ*<sub>1s</sub>) < (σ<sub>2s</sub>) < (σ*<sub>2s</sub>) <[(π<sub>2py</sub>)(π<sub>2pz</sub>)] < (σ <sub>2px</sub>) < [(π*<sub>2py</sub>)(π*<sub>2pz</sub>)] < (σ*<sub>2px</sub>) |
B. | For O<sub>2</sub> to Ne<sub>2</sub> |
C. | For H<sub>2</sub> to N<sub>2</sub> |
D. | For H<sub>2</sub> to Ne<sub>2</sub> |
Answer» C. For H<sub>2</sub> to N<sub>2</sub> | |
20. |
Which of the following molecule does not exist due to its zero bond order? |
A. | H<sub>2</sub><sup>+</sup> |
B. | He<sub>2</sub><sup>+</sup> |
C. | He<sub>2</sub> |
D. | H<sub>2</sub><sup>–</sup> |
Answer» D. H<sub>2</sub><sup>‚Äö√Ñ√∂‚àö√ë‚àö¬®</sup> | |
21. |
On the basis of molecular orbital theory, select the most appropriate option. |
A. | The bond order of O<sub>2</sub> is 2.5 and it is paramagnetic |
B. | The bond order of O<sub>2</sub> is 1.5 and it is paramagnetic |
C. | The bond order of O<sub>2</sub> is 2 and it is diamagnetic |
D. | The bond order of O<sub>2</sub> is 2 and it is paramagnetic |
Answer» E. | |
22. |
Arrange the following molecules in the order of increasing stability. |
A. | N<sub>2</sub><sup>+</sup> < N<sub>2</sub> < N<sub>2</sub><sup>–</sup> < N<sub>2</sub><sup>2-</sup> |
B. | N<sub>2</sub><sup>2-</sup> < N<sub>2</sub><sup>–</sup> < N<sub>2</sub> < N<sub>2</sub><sup>+</sup> |
C. | N<sub>2</sub><sup>2-</sup> < N<sub>2</sub><sup>–</sup> = N<sub>2</sub><sup>+</sup> < N<sub>2</sub> |
D. | N<sub>2</sub> < N<sub>2</sub><sup>+</sup> = N<sub>2</sub><sup>–</sup> < N<sub>2</sub><sup>2-</sup> |
Answer» D. N<sub>2</sub> < N<sub>2</sub><sup>+</sup> = N<sub>2</sub><sup>‚Äö√Ñ√∂‚àö√ë‚àö¬®</sup> < N<sub>2</sub><sup>2-</sup> | |
23. |
Arrange the following molecules in decreasing bond length. |
A. | O<sub>2</sub> > O<sub>2</sub><sup>–</sup> > O<sub>2</sub><sup>+</sup> > O<sub>2</sub><sup>2-</sup> |
B. | O<sub>2</sub><sup>2-</sup> > O<sub>2</sub><sup>–</sup> > O<sub>2</sub> > O<sub>2</sub><sup>+</sup> |
C. | O<sub>2</sub><sup>2-</sup> > O<sub>2</sub><sup>–</sup> > O<sub>2</sub><sup>+</sup> > O<sub>2</sub> |
D. | O<sub>2</sub><sup>–</sup> > O<sub>2</sub><sup>+</sup> > O<sub>2</sub><sup>2-</sup> > O<sub>2</sub> |
Answer» C. O<sub>2</sub><sup>2-</sup> > O<sub>2</sub><sup>‚Äö√Ñ√∂‚àö√ë‚àö¬®</sup> > O<sub>2</sub><sup>+</sup> > O<sub>2</sub> | |
24. |
Bond Order of O2, F2, N2 respectively are |
A. | +1, +2, +3 |
B. | +2, +3, +1 |
C. | +2, +1, +3 |
D. | +3, +2, +1 |
Answer» D. +3, +2, +1 | |
25. |
The filling of molecular orbital takes place according to |
A. | The Aufbau Principle |
B. | Pauli Exclusion Principle |
C. | Hund’s rule of maximum multiplicity |
D. | All of the mentioned |
Answer» E. | |
26. |
If the sign of the wave function is unchanged when the orbital is reflected about its centre, the orbital is |
A. | Gerade |
B. | Ungerade |
C. | Gerade as well as Ungerade |
D. | None of the mentioned |
Answer» B. Ungerade | |